Rename files with a suffix with name of its folder - bash

Each folder has a .mkv or .avi file.
E.g:
Sommerferien201308/eins.avi
Sommerferien201309/eins.mkv
Herbst201401/film.avi
Herbst201402/krz.mkv
Renaming to:
Sommerferien201308/Sommerferien201308.avi
Sommerferien201309/Sommerferien201309.mkv
Herbst201401/Herbst201401.avi
Herbst201402/Herbst201402.mkv
How can I rename the filename to the name of its folder?
Of course every foldername is unique. And too much to do it manually for each file/folder.
I Would try with find.
find . -type d -name "" -exec cd "" && mv {} \;
But i dont know how to select the folder name and how to make the .avi or .mkv selection and how to store the selected folder name..

You can use this find command from base folder of your folders that contain *.avi and *.mkv files:
while IFS= read -rd '' f; do
(
IFS=/
arr=($f)
if [[ $f != *"/${arr[len-2]}"* ]]; then
len=${#arr[#]}
ext="${arr[len-1]##*.}"
cd "$(dirname "$f")" && echo mv "${arr[len-1]}" "${arr[len-2]}.$ext"
fi
)
done < <(find . \( -name '*.mkv' -o -name '*.avi' \) -print0)
When you're satisfied with the output remove echo before mv.

Related

Bash script to rename files with current timestamp

master_sheet_2022_03_25_1141.csv
master_sheet_2021_03_30_1034.csv
master_sheet_2021_03_31_1857.csv
master_sheet_2021_03_31_1930.csv
master_sheet_2021_03_31_2037.csv
master_sheet_2021_03_31_2109.csv
For each file in above directory, rename the file but append master_sheet
master_sheet__$(date "+%Y.%m.%d-%H.%M.%S").csv"
eg: master_sheet__2022_04_06_09:30
Here is my current script
#!/bin/bash
find . -type f -name "*.csv" | \
while read -r files; do
mv "$files" "${files%.*}_$(date "+%Y.%m.%d-%H.%M.%S").csv"
# for files in *; do echo "${files%.*}"; done
done
Current output
master_sheet_2022_03_22_1351_2022.04.06-09.14.00_2022.04.06-09.19.27_2022.04.06-09.20.12
master_sheet_2022_03_29_1043_2022.04.06-09.14.00_2022.04.06-09.19.27_2022.04.06-09.20.12

Move all files in a folder to a new location if the same existing Folder name exists at remote location

Looking for a bash script:
Here's the situation:
I have 1000's folders and subfolders on my Backup Directory Drive
lets say.....
/backup
/backup/folderA
/backup/folderA/FolderAA
/backup/folderB
/backup/folderB/FolderBB
I have Dozens of similar folders in a secondary location (with files in them) and the Folder names will match one of the folders or subfolders in the main backup drive.
I would like to move all contents of specific extension types from my secondary location $FolderName to the Backup location + matching subfolder ONLY if the $FolderName matches exactly and remove the folders from my secondary location!
If there is no corrosponding folder or subfolder in the backup location then leave the source folders & files alone.
looking forward to getting some help/guidance.
Mike
Additional info requested.Expected input and ouput
Lets say i have the following:
Backup Folder
/backup/test/file.bak
And for my secondary folder location:
/secondarylocation/mike/test/hello/john.bak
/secondarylocation/mike/test/hello/backup.zip
i would like this as the end result
/backup/test/file.bak
/backup/test/john.bak
/backup/test/backup.zip
and /secondarylocation/mike/test *and sub folders and files removed
run this script with quoted folders and file types:
./merge.sh "backup" "secondarylocation/mike" "*.zip" "*.bak"
replace -iname with -name if you want to search for suffix case sensitive
replace mv -fv with mv -nv when you don't want to overwrite duplicate file names
add -mindepth 1 to last find if you want to keep empty folder test
merge.sh
#!/bin/bash
# read folders from positional parameters
[ -d "$1" ] && targetf="$1" && shift
[ -d "$1" ] && sourcef="$1" && shift
if [ -z "$targetf" ] || [ -z "$sourcef" ]
then
echo -e "usage: ./merge.sh <targetfolder> <sourcefolder> [PATTERN]..."
exit 1
fi
# add prefix -iname for each pattern
while [ ${pattern:-1} -le $# ]
do
set -- "$#" "-iname \"$1\""
shift
pattern=$((${pattern:-1}+1))
done
# concatenate all prefix+patterns with -o and wrap in parentheses ()
if (( $# > 1 ))
then
pattern="\( $1"
while (( $# > 1 ))
do
pattern="$pattern -o $2"
shift
done
pattern="$pattern \)"
else
pattern="$1"
fi
# move files from searchf to destf
find "$targetf" -mindepth 1 -type d -print0 | sort -z | while IFS=$'\0' read -r -d $'\0' destf
do
find "$sourcef" -mindepth 1 -type d -name "${destf##*/}" -print0 | sort -z | while IFS=$'\0' read -r -d $'\0' searchf
do
if (( $# ))
then
# search with pattern
eval find "\"$searchf\"" -depth -type f "$pattern" -exec mv -fv {} "\"$destf\"" \\\;
else
# all files
find "$searchf" -depth -type f -exec mv -fv {} "$destf" \;
fi
# delete empty folders
find "$searchf" -depth -type d -exec rmdir --ignore-fail-on-non-empty {} +
done
done
exit 0
this will merge hello into test (earn the fruits and cut the tree)

How to check all specific file type files are copied into a directory?

I've tried to compare specific file type (like .txt) and a specific directory by using the diff function but it doesn't turn out right. Can I get some help here?
backup=$(find . -name "*.text" -type f)
backup2=$(find /home/user/Desktop/backupfile -name "*.text" -type f)
diff -rq $backup $backup2
You can try the below, using a for loop comparing the files in both locations (if found) :
for f in ($find . -type f -name "*.text")
do
name=$(basename "$f")
if [ -f /home/user/Desktop/backupfile/"$name" ]
then
diff -rq "$f" /home/user/Desktop/backupfile/"$name"
else
echo match of "$f" not found under /home/user/Desktop/backupfile/
done

to delete files older than 7 days using Unix

Requirement:
i am having the path where the files will be present .
i need to get the path from it and delete the files older than 7 days with name as .logo or ,out0 ..
ISSUE:tried the below but its going to many paths that were not listed..
#reading source path from rem_logs.txt
cat rem_logs.txt | while read FILE_PATH
do
echo " Path obtained from rem_logs.txt --> '$FILE_PATH'"
echo "File has to be removed from '$FILE_PATH'"
#moving to the specified path above
find $FILE_PATH -type f -mtime +7 -print | while read FILE_NAME
echo "File is '$FILE_NAME'"
do
chmod 777 $FILE_NAME
echo "$FILE_NAME is received"
if [ "$FILE_NAME"=*.log0* -o "$FILE_NAME"=*.out0*]
then
echo " $FILE_PATH/$FILE_NAME" > $LOGPATH/abdul.txt
used above statement for testing in testing environment
else
echo "This file - $FILE_NAME need not be removed"
fi
done
UpdateLog_del.sh "$FILE_NAME is presently deleted from the above mentioned path"
done
Consider doing something like this:
while read FILE_PATH
do
#for each filename found
for FILE_NAME in $(find $FILE_PATH \( -name "*.log0" -o -name "*.out0" \) -type f -mtime +7 -print)
do
chmod 777 $FILE_NAME
echo "$FILE_NAME" >> $LOGPATH/abdul.txt
done
UpdateLog_del.sh "$FILE_NAME is presently deleted from the above mentioned path"
#read from rem_logs.txt which contains the paths
done < rem_logs.txt
Try this:
find /path -type f -mtime +7 -regex '$\|.*log0$\|.*out0$' -print | xargs -I '{}' -n1 rm -f {}

How to loop through a directory recursively to delete files with certain extensions

I need to loop through a directory recursively and remove all files with extension .pdf and .doc. I'm managing to loop through a directory recursively but not managing to filter the files with the above mentioned file extensions.
My code so far
#/bin/sh
SEARCH_FOLDER="/tmp/*"
for f in $SEARCH_FOLDER
do
if [ -d "$f" ]
then
for ff in $f/*
do
echo "Processing $ff"
done
else
echo "Processing file $f"
fi
done
I need help to complete the code, since I'm not getting anywhere.
As a followup to mouviciel's answer, you could also do this as a for loop, instead of using xargs. I often find xargs cumbersome, especially if I need to do something more complicated in each iteration.
for f in $(find /tmp -name '*.pdf' -or -name '*.doc'); do rm $f; done
As a number of people have commented, this will fail if there are spaces in filenames. You can work around this by temporarily setting the IFS (internal field seperator) to the newline character. This also fails if there are wildcard characters \[?* in the file names. You can work around that by temporarily disabling wildcard expansion (globbing).
IFS=$'\n'; set -f
for f in $(find /tmp -name '*.pdf' -or -name '*.doc'); do rm "$f"; done
unset IFS; set +f
If you have newlines in your filenames, then that won't work either. You're better off with an xargs based solution:
find /tmp \( -name '*.pdf' -or -name '*.doc' \) -print0 | xargs -0 rm
(The escaped brackets are required here to have the -print0 apply to both or clauses.)
GNU and *BSD find also has a -delete action, which would look like this:
find /tmp \( -name '*.pdf' -or -name '*.doc' \) -delete
find is just made for that.
find /tmp -name '*.pdf' -or -name '*.doc' | xargs rm
Without find:
for f in /tmp/* tmp/**/* ; do
...
done;
/tmp/* are files in dir and /tmp/**/* are files in subfolders. It is possible that you have to enable globstar option (shopt -s globstar).
So for the question the code should look like this:
shopt -s globstar
for f in /tmp/*.pdf /tmp/*.doc tmp/**/*.pdf tmp/**/*.doc ; do
rm "$f"
done
Note that this requires bash ≥4.0 (or zsh without shopt -s globstar, or ksh with set -o globstar instead of shopt -s globstar). Furthermore, in bash <4.3, this traverses symbolic links to directories as well as directories, which is usually not desirable.
If you want to do something recursively, I suggest you use recursion (yes, you can do it using stacks and so on, but hey).
recursiverm() {
for d in *; do
if [ -d "$d" ]; then
(cd -- "$d" && recursiverm)
fi
rm -f *.pdf
rm -f *.doc
done
}
(cd /tmp; recursiverm)
That said, find is probably a better choice as has already been suggested.
Here is an example using shell (bash):
#!/bin/bash
# loop & print a folder recusively,
print_folder_recurse() {
for i in "$1"/*;do
if [ -d "$i" ];then
echo "dir: $i"
print_folder_recurse "$i"
elif [ -f "$i" ]; then
echo "file: $i"
fi
done
}
# try get path from param
path=""
if [ -d "$1" ]; then
path=$1;
else
path="/tmp"
fi
echo "base path: $path"
print_folder_recurse $path
This doesn't answer your question directly, but you can solve your problem with a one-liner:
find /tmp \( -name "*.pdf" -o -name "*.doc" \) -type f -exec rm {} +
Some versions of find (GNU, BSD) have a -delete action which you can use instead of calling rm:
find /tmp \( -name "*.pdf" -o -name "*.doc" \) -type f -delete
For bash (since version 4.0):
shopt -s globstar nullglob dotglob
echo **/*".ext"
That's all.
The trailing extension ".ext" there to select files (or dirs) with that extension.
Option globstar activates the ** (search recursivelly).
Option nullglob removes an * when it matches no file/dir.
Option dotglob includes files that start wit a dot (hidden files).
Beware that before bash 4.3, **/ also traverses symbolic links to directories which is not desirable.
This method handles spaces well.
files="$(find -L "$dir" -type f)"
echo "Count: $(echo -n "$files" | wc -l)"
echo "$files" | while read file; do
echo "$file"
done
Edit, fixes off-by-one
function count() {
files="$(find -L "$1" -type f)";
if [[ "$files" == "" ]]; then
echo "No files";
return 0;
fi
file_count=$(echo "$files" | wc -l)
echo "Count: $file_count"
echo "$files" | while read file; do
echo "$file"
done
}
This is the simplest way I know to do this:
rm **/#(*.doc|*.pdf)
** makes this work recursively
#(*.doc|*.pdf) looks for a file ending in pdf OR doc
Easy to safely test by replacing rm with ls
The following function would recursively iterate through all the directories in the \home\ubuntu directory( whole directory structure under ubuntu ) and apply the necessary checks in else block.
function check {
for file in $1/*
do
if [ -d "$file" ]
then
check $file
else
##check for the file
if [ $(head -c 4 "$file") = "%PDF" ]; then
rm -r $file
fi
fi
done
}
domain=/home/ubuntu
check $domain
There is no reason to pipe the output of find into another utility. find has a -delete flag built into it.
find /tmp -name '*.pdf' -or -name '*.doc' -delete
The other answers provided will not include files or directories that start with a . the following worked for me:
#/bin/sh
getAll()
{
local fl1="$1"/*;
local fl2="$1"/.[!.]*;
local fl3="$1"/..?*;
for inpath in "$1"/* "$1"/.[!.]* "$1"/..?*; do
if [ "$inpath" != "$fl1" -a "$inpath" != "$fl2" -a "$inpath" != "$fl3" ]; then
stat --printf="%F\0%n\0\n" -- "$inpath";
if [ -d "$inpath" ]; then
getAll "$inpath"
#elif [ -f $inpath ]; then
fi;
fi;
done;
}
I think the most straightforward solution is to use recursion, in the following example, I have printed all the file names in the directory and its subdirectories.
You can modify it according to your needs.
#!/bin/bash
printAll() {
for i in "$1"/*;do # for all in the root
if [ -f "$i" ]; then # if a file exists
echo "$i" # print the file name
elif [ -d "$i" ];then # if a directroy exists
printAll "$i" # call printAll inside it (recursion)
fi
done
}
printAll $1 # e.g.: ./printAll.sh .
OUTPUT:
> ./printAll.sh .
./demoDir/4
./demoDir/mo st/1
./demoDir/m2/1557/5
./demoDir/Me/nna/7
./TEST
It works fine with spaces as well!
Note:
You can use echo $(basename "$i") # print the file name to print the file name without its path.
OR: Use echo ${i%/##*/}; # print the file name which runs extremely faster, without having to call the external basename.
Just do
find . -name '*.pdf'|xargs rm
If you can change the shell used to run the command, you can use ZSH to do the job.
#!/usr/bin/zsh
for file in /tmp/**/*
do
echo $file
done
This will recursively loop through all files/folders.
The following will loop through the given directory recursively and list all the contents :
for d in /home/ubuntu/*;
do
echo "listing contents of dir: $d";
ls -l $d/;
done

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