Lua Missing } unexpected - syntax

function love.load()
Tileset = love.graphics.newImage('countryside.png')
TileW, TileH = 32, 32
local tilesetW, tilesetH = Tileset:getWidth(), Tileset:getHeight()
Quads = {
love.graphics.newQuad(0, 0, TileW, TileH, tilesetW, tilesetH) -- 1 = grass
love.graphics.newQuad(32, 0, TileW, TileH, tilesetW, tilesetH) -- 2 = box
love.graphics.newQuad(0, 32, TileW, TileH, tilesetW, tilesetH) -- 3 = flowers
love.graphics.newQuad(32, 32, TileW, TileH, tilesetW, tilesetH) -- 4 = box
}
TileTable = {
{1, 1, 1},
{1, 2, 1},
{1, 1, 1}
}
end
This code gives this error:
Syntax error: main.lua:9: '}' expected (to close '{' at line 7) near 'love'
I don't understand it. Anyone got any help?

In Lua, an array is initialized as below, hope it helps:
Quads = {
love.graphics.newQuad(0, 0, TileW, TileH, tilesetW, tilesetH), -- 1 = grass
love.graphics.newQuad(32, 0, TileW, TileH, tilesetW, tilesetH), -- 2 = box
love.graphics.newQuad(0, 32, TileW, TileH, tilesetW, tilesetH), -- 3 = flowers
love.graphics.newQuad(32, 32, TileW, TileH, tilesetW, tilesetH), -- 4 = box
}

Related

RuntimeError: mat1 and mat2 shapes cannot be multiplied (1280x5 and 6400x4096)?

Defining Alexnet using the following code,I can train successfully.But when I want to see the output of each layer,it will be an error ‘RuntimeError: mat1 and mat2 shapes cannot be multiplied (1280x5 and 6400x4096)?’
class AlexNet(nn.Module):
def __init__(self):
super(AlexNet, self).__init__()
self.conv = nn.Sequential(
nn.Conv2d(1, 96, 11, 4),
nn.ReLU(),
nn.MaxPool2d(3, 2),
nn.Conv2d(96, 256, 5, 1, 2),
nn.ReLU(),
nn.MaxPool2d(3, 2),
nn.Conv2d(256, 384, 3, 1, 1),
nn.ReLU(),
nn.Conv2d(384, 384, 3, 1, 1),
nn.ReLU(),
nn.Conv2d(384, 256, 3, 1, 1),
nn.ReLU(),
nn.MaxPool2d(3, 2)
)
self.fc = nn.Sequential(
nn.Linear(256*5*5, 4096),
nn.ReLU(),
nn.Dropout(0.5),
nn.Linear(4096, 4096),
nn.ReLU(),
nn.Dropout(0.5),
nn.Linear(4096, 10)
)
def forward(self, img):
feature = self.conv(img)
output = self.fc(feature.view(img.shape[0], -1))
return output
X=torch.randn(1,1,224,224)
for name,layer in net.named_children():
X=layer(X)
print(name,X.shape)
Could u help me?
You forgot to flatten the output array of self.conv in the for cycle. You can split it into two cycles, one for the convolution layers, and one for the fully connected ones.
X = torch.randn(1, 1, 224, 224)
for name, layer in net.conv.named_children():
X = layer(X)
print(name, X.shape)
X = X.flatten() # or X = X.view(X.shape[0], -1)
for name, layer in net.fc.named_children():
X = layer(X)
print(name, X.shape)

D3 Chord Diagram Not Rendering Correctly

Using the excellent guide by Nadieh Bremer I'm making a stretched chord diagram.
However, with certain data inputs the rendering goes awry.
I've made a demo to demonstrate my issue here:
https://codepen.io/benmayocode/pen/MPEwdr
Specifically, in the .js file lines 269 to 281 file I have:
var respondents = 40,
emptyPerc = 0.4,
emptyStroke = Math.round(respondents*emptyPerc);
var Names = ['BEN', 'ROSE', '', '1', '2', '6', ''];
var matrix = [
[0, 0, 0, 10, 10, 0, 0] ,
[0, 0, 0, 0, 10, 10, 0] ,
[0, 0, 0, 0, 0, 0, 24] ,
[10, 0, 0, 0, 0, 0, 0] ,
[10, 10, 0, 0, 0, 0, 0] ,
[0, 10, 0, 0, 0, 0, 0] ,
[0, 0, 0, 24, 0, 0, 0] ,
];
This renders incorrectly - but if I change it to...
var respondents = 40,
emptyPerc = 0.4,
emptyStroke = Math.round(respondents*emptyPerc);
var Names = ['BEN', 'LIB', 'ROSE', '', '1', '2', '6', ''];
var matrix = [
[0, 0, 0, 0, 10, 10, 0, 0] ,
[0, 0, 0, 0, 0, 10, 0, 0] ,
[0, 0, 0, 0, 0, 10, 10, 0] ,
[0, 0, 0, 0, 0, 0, 0, 24] ,
[10, 0, 0, 0, 0, 0, 0, 0] ,
[10, 10, 10, 0, 0, 0, 0, 0] ,
[0, 0, 10, 0, 0, 0, 0, 0] ,
[0, 0, 0, 0, 24, 0, 0, 0] ,
];
Then it works great. I obviously see the difference between the two blocks of code, but why are they producing different results, and is it possible to modify my code to accommodate both examples?
If you examine the dodgy arc, you will see you can flip it into the right place by altering the sign on the transform from (50,0) to (-50,0). If you then look at the code that assigns the transform, it is
.attr("transform", function(d, i) {
d.pullOutSize = pullOutSize * ( d.startAngle + 0.01 > Math.PI ? -1 : 1);
return "translate(" + d.pullOutSize + ',' + 0 + ")";
});
with a note in the original text to say that "the 0.01 is for rounding errors". Given that the startAngle is already 3.13--i.e. very close to Pi--it looks like this is an edge case where the value fell just the wrong side of the cutoff. Changing the allowable rounding error value to 0.02 puts the arc in the correct place, or you could do something like
d.pullOutSize = pullOutSize * (
// is the start angle less than Pi?
d.startAngle + 0.01 < Math.PI ? 1 :
// if yes, is the end angle also less than Pi?
d.endAngle < Math.PI ? 1 : -1 );
to prevent edge cases like that in your dataset.

Dual pivot quick sort algorithm

I was analyzing the code for Arrays.sort() method in java . My question is for what values of integer array a[] will this code return true ?
if (less < e1 && e5 < great)
After Sorting left and right parts recursively, excluding known pivots for what value of array a[] will the center part become too large (comprises > 4/7 of the array) ?
Given QUICKSORT_THRESHOLD = 286 .
Array size cannot be more than 286
Any example of int array please .
It happens when all candidates for pivots are close to either the maximum or the minimum value of the array.
java.util.DualPivotQuicksort#sort() chooses the pivots from 5 positions in the array:
int seventh = (length >> 3) + (length >> 6) + 1;
int e3 = (left + right) >>> 1; // The midpoint
int e2 = e3 - seventh;
int e1 = e2 - seventh;
int e4 = e3 + seventh;
int e5 = e4 + seventh;
So, in order to construct an array that satisfies the condition, we need to fill those 5 positions with extreme values. For example:
int[] x = {
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, -2, /* e1 = 10 */
0, 0, 0, 0, 0, 0, -1, /* e2 = 17 */
0, 0, 0, 0, 0, 0, 0, /* e3 = 24 */
0, 0, 0, 0, 0, 0, 1, /* e4 = 31 */
0, 0, 0, 0, 0, 0, 2, /* e5 = 38 */
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0
};
Arrays.sort(x);
And a non-trivial case where the method changes the boundaries of the central part before sorting it:
int[] x = {
70, 66, 11, 24, 10, 28, 58, 13, 19, 90, 15,
79, 16, 69, 39, 14, 10, 16,
40, 59, 47, 77, 90, 50, 50,
50, 16, 76, 86, 70, 33, 90,
24, 35, 73, 93, 87, 19, 91,
73, 87, 22, 15, 24, 92, 34, 35, 98, 11, 40
};

difference between CV_32FC3 and CV_64FC3 in OpenCV?

I was testing around with OpenCV matrices and the display function and had this bug. It took me more than half a day to reveal it:
I originally tried to display OpenCV matrices regardless of the type of matric e.g. CvMat or Mat, ...
with a display method recommended by Mr vasile from another post of mine Multi channel Mat display function
The display method simply fetches all data of the matrix to cout stream
this is my program:
// First: CV_32FC3 works OK
float objpts[12] = {0, 105, 105, 0, 0, 0, 105, 105, 0, 0, 0, 0};
CvMat objptsmat = cvMat( 1, 4, CV_32FC3, objpts);
CvMat* objectPoints = &objptsmat;
CvMatShow(objectPoints);
getchar();
output:
// Second: CV_64FC3 crashes
float objpts[12] = {0, 105, 105, 0, 0, 0, 105, 105, 0, 0, 0, 0};
CvMat objptsmat = cvMat( 1, 4, CV_64FC3, objpts);
CvMat* objectPoints = &objptsmat;
CvMatShow(objectPoints);
getchar();
output:
they should be both the same. Right??!!
In the second example, you should have the array declared as
double objpts[12] = {0, 105, 105, 0, 0, 0, 105, 105, 0, 0, 0, 0};
You can read CV_xxtCn as
xx: number of bits
t: type (F = floating point type, S = signed integer, U = unsigned integer)
n: number of channels

Lighting and OpenGL ES

I'm working on getting a simple lighting right on my OpenGL ES iPhone scene. I'm displaying a simple object centered on the origin, and using an arcball to rotate it by touching the screen. All this works nicely, except I try to add one fixed light (fixed w.r.t. eye position) and it is badly screwed: the whole object (an icosahedron in this example) is lit uniformly, i.e. it all appears in the same color.
I have simplified my code as much as possible so it's standalone and still reproduces what I experience:
glClearColor (0.25, 0.25, 0.25, 1.);
glClear (GL_COLOR_BUFFER_BIT | GL_DEPTH_BUFFER_BIT);
glEnable (GL_DEPTH_TEST);
glEnable(GL_LIGHTING);
glMatrixMode (GL_PROJECTION);
glLoadIdentity ();
glOrthof(-1, 1, -(float)backingWidth/backingHeight, (float)backingWidth/backingHeight, -10, 10);
glMatrixMode (GL_MODELVIEW);
glLoadIdentity ();
GLfloat ambientLight[] = { 0.2f, 0.2f, 0.2f, 1.0f };
GLfloat diffuseLight[] = { 0.8f, 0.8f, 0.8, 1.0f };
GLfloat specularLight[] = { 0.5f, 0.5f, 0.5f, 1.0f };
GLfloat position[] = { -1.5f, 1.0f, -400.0f, 0.0f };
glEnable(GL_LIGHT0);
glLightfv(GL_LIGHT0, GL_AMBIENT, ambientLight);
glLightfv(GL_LIGHT0, GL_DIFFUSE, diffuseLight);
glLightfv(GL_LIGHT0, GL_SPECULAR, specularLight);
glLightfv(GL_LIGHT0, GL_POSITION, position);
glShadeModel(GL_SMOOTH);
glEnable(GL_NORMALIZE);
float currRot[4];
[arcball getCurrentRotation:currRot];
glRotatef (currRot[0], currRot[1], currRot[2], currRot[3]);
float f[4];
f[0] = 0.5; f[1] = 0; f[2] = 0; f[3] = 1;
glMaterialfv (GL_FRONT_AND_BACK, GL_AMBIENT, f);
glMaterialfv (GL_FRONT_AND_BACK, GL_DIFFUSE, f);
f[0] = 0.2; f[1] = 0.2; f[2] = 0.2; f[3] = 1;
glMaterialfv (GL_FRONT_AND_BACK, GL_SPECULAR, f);
glEnableClientState (GL_VERTEX_ARRAY);
drawSphere(0, 0, 0, 1);
where the drawSphere function actually draws an icosahedron:
static void drawSphere (float x, float y, float z, float rad)
{
glPushMatrix ();
glTranslatef (x, y, z);
glScalef (rad, rad, rad);
// Icosahedron
const float vertices[] =
{ 0., 0., -1., 0., 0., 1., -0.894427, 0., -0.447214, 0.894427, 0.,
0.447214, 0.723607, -0.525731, -0.447214, 0.723607, 0.525731,
-0.447214, -0.723607, -0.525731, 0.447214, -0.723607, 0.525731,
0.447214, -0.276393, -0.850651, -0.447214, -0.276393, 0.850651,
-0.447214, 0.276393, -0.850651, 0.447214, 0.276393, 0.850651,
0.447214 };
const GLubyte indices[] =
{ 1, 11, 7, 1, 7, 6, 1, 6, 10, 1, 10, 3, 1, 3, 11, 4, 8, 0, 5, 4, 0,
9, 5, 0, 2, 9, 0, 8, 2, 0, 11, 9, 7, 7, 2, 6, 6, 8, 10, 10, 4, 3,
3, 5, 11, 4, 10, 8, 5, 3, 4, 9, 11, 5, 2, 7, 9, 8, 6, 2 };
glVertexPointer (3, GL_FLOAT, 0, vertices);
glDrawElements (GL_TRIANGLES, sizeof(indices)/sizeof(indices[0]), GL_UNSIGNED_BYTE, indices);
glPopMatrix ();
}
A movie of what I see as the result is here. Thanks to anyone who can shed some light into this (no kidding!). I'm sure it will look embarassingly trivial to someone, but I swear I have looked at many lighting tutorials before this and am stuck.
Try adding some vertex normals using glNormalPointer(). It looks like OpenGL ES is just using the default normal for everything.

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