Sum Values in Shell Script - bash

Question

I have the following values in this format in a file:
Filevalue.txt
abc
123
dev
456
hij
567
123
542
I need to add the numerical values from the character values which are below it
Output
abc 123
dev 456
hij 1232
Anyhelp will be deeply appreciated?

Answer 1

Here's another awk that mantains the order.
Example
$ awk '/[0-9]+/{a+=$1;next}a{print a;a=0}{printf($1FS);a=0}END{print a}' file
abc 123
dev 456
hij 1232
Explanation
/[0-9]+/{a+=$1;next}:When a number is detected as the content of the record, it's value is accumulated into a var, then next is used to stop further processing and pass the flow to the next record.
a{print a;a=0}: ONLY when the counter is not null we print a value that correspond to the previous word and initialize it.
{printf($1FS);a=0}: Print current record and the separator avoiding the carriage return. This is applied to all text records.
END{print a}: Show the final counter that will remain after the last record.

Answer 2

It's possible to do this by using awk and arrays:
$ awk '{if($1!~/^[0-9]+$/){cur=$1}else{sums[cur]+=$1}}END{for(el in sums){printf("%s %d\n",el,sums[el])}}' Filevalue.txt
hij 1232
dev 456
abc 123
Here is the same code but written to the file sum.awk and with comments:
# this block will be executed for every line in the file
{
# if current processing line is not a number, then it's a name of the next
# group, let's save it to cur variable
if ($1 !~ /^[0-9]+$/) {
cur = $1
} else {
# here we're summing values
sums[cur] += $1
}
}
# this block will be executed at the end of file processing, here we're
# printing array with sums
END {
for (el in sums) {
printf("%s %d\n", el, sums[el])
}
}
Use it like this:
$ awk -f sum.awk Filevalue.txt
hij 1232
dev 456
abc 123
The only downside of using awk here is that it doesn't preserve keys order.