Implementing RxSwift with TRON - rx-swift

Question

I am trying to start using RxSwift, therefore I tried to create a function that does a request and I tried to implement the rxResult() function that comes with TRON, the HTTP library I use. But the documentation on this is not very detailed. Can anyone point me in the right direction on what I am doing wrong? This is the function I have written:
static func readAllWithRx() {
let token = UserDefaults.standard.value(forKey: Constants.kTokenUserDefaultsKey) as! String
let url = URL(string: "api/url")!
let request: APIRequest<AssessmentResponse, MyAppError> = APIHelper.tron.request(url.absoluteString)
_ = request.rxResult().subscribe(onNext: { AssessmentResponse in
print("RX AssessmentResponse \(AssessmentResponse)")
}, onError: { Error in
}, onCompleted: {
}, onDisposed: {
})
}
Finally I try to call this request within my Controller using:
let read = Assessments.readAllWithRx()

Answer 1

There’re 2 things at the beginning:
let read = Assessments.readAllWithRx() assumes the function returns something synchronously
Implementation of readAllWithRx you posted doesn’t return anything.
I’ve never used TRON, but as far as I can see, its rxResult() returns an Observable<T> where T is a type of the response. In this case, to get asynchronously AssesmentResponse, you need to subscribe to the observable (as you already did by the way).
Here's an example - an updated implementation of your readAllWithRx (won’t compiled probably, writing code in notepad):
static func readAllWithRx() -> Observable<AssessmentResponse> {
let token = UserDefaults.standard.value(forKey: Constants.kTokenUserDefaultsKey) as! String
let url = URL(string: "api/url")!
let request: APIRequest<AssessmentResponse, MyAppError> = APIHelper.tron.request(url.absoluteString)
return request.rxResult()
}
then, if you need to get AssessmentResponse somewhere in the code:
Assessments.readAllWithRx().subscribe(onNext: { result in
// your response here
print(result)
})