I'm trying to create a new page in Laravel and I'm not sure what to do in the context of the Laravel framework.
If it was just html, then you just create a new html file. In Laravel, what are all the things you need to do when creating a new page?
The easiest way in Laravel is to define a route closure, and return a view from it.
In your routes/web.php file:
Route::get('/my-page', function () {
return view('my-page');
});
Then in resources/views you create a file called my-page.php, or if you want to use Laravel's Blade syntax (you probably do) call it my-page.blade.php.
Edit: there's now an even easier way to to it. Also in routes/web.php:
Route::view('/my-page', 'my-page');
This will do exactly the same thing as the previous example, without the need for a closure and explicitly calling view().
There are two locations to add New Page to your Laravel project:
You have to create an additional route in YOURAPP>routes>web.php file.
You have to add PHP file with that name to YOURAPP>resources>views folder. If you want to use BLADE for your project, than you should put name_of_page.blade.php. And you should concider it as a must at the very beginning :).
Now, in routes you should be able to add only first part of the file rather than .blade.php. For example: about.blade.php, you can put in route only about
It should work out of the box :).
You can also try this in routes/web.php
Route::get('/my-page', function () {
return view('my-page');
})->name('my-page');
Related
Am trying to use two different functions from one controller in a single page route
Route::get('/cart','App\Http\Controllers\Frontend\CartController#index');
Route::get('/cart','App\Http\Controllers\Frontend\CartController#alldata');
But the problem is the function alldata works where the function index doesn't
You can't have 2 GET routes with the same path.
Route::get('/cart','App\Http\Controllers\Frontend\CartController#index');
Route::get('/cart/all','App\Http\Controllers\Frontend\CartController#alldata');
The /cart route is overwritten by the alldata(). So the alldata() is calling instead of index().
kindly remove the alldata()'s route and pass the data from index().
Route::get('/cart','App\Http\Controllers\Frontend\CartController#index');
Route::get('/cart','App\Http\Controllers\Frontend\CartController#alldata');
Try to manipulate your logic in controller rather than in route file.
Use conditional in controller function.
If I want to create RESTful APIs, which one should I choose?
How do the URLs as index.php/id/1 work? I think it's a file path, not a URL.
If I want to get an image as abc.com/img/1.png, it may have conflicts with abc.com/img/{param}. How do I solve?
BTW, I use Laravel now.
Thanks so much.
The difference is in route model binding
https://laravel.com/docs/5.7/routing#route-model-binding
This allows you to get the model with the id that is passed into the route
So for example a route like this:
Route::get('users/{user}', 'UsersController#getUser');
Will allow you to do this in you method:
use App\User
public function getUser(User $user) {
return $user;
}
This means that you get the full record for the id that is in the route.
So your Questions:
1: I would use this for sending model id's
2: the variables in the route are passed in that order to the method allowing you to get access to them.
3: You will need to be careful with your routes as you can have conflicts. having said that Laravel does not use a traditional directory structure for storage. I believe that if you have a folder stucture of /public/img and that folder contains an img named 1.png it will get the image but I have not tested this.
I am working on a Laravel project, where I want to toggle partials based on the URL data like
foo.bar.com/#itemone/create
foo.bar.com/#itemone/view
Basically, I want to pass whether it is create or view to the partials like this
#include('partials.layouts._core_activity_header',['layout_type' => "create"])
How do I achieve this? Any help would be appreciated.
you can use the route name
Route::getCurrentRoute()->getName()
this will return the route alias
Hello everyone I just installed laravel4 and spend two days trying to make the first step. Now I made it but I'm confused about the Route::get() function and his paremeters.
I installe laravel directly in
/opt/lampp/htdocs/laravel
then follow tutorial to create file
userform.php
into app/views, then add following codes into routes.php
Route::get('userform', function()
{
return View::make('userform');
});
. Then I go to
/localhost/laravel/public
to see welcome page, and
/localhost/laravel/public/userform
to see the form defined in the view/userform.php.
Q1: According to chrome dev tools, i see in the html page, the form action is
http://localhost/laravel/public/userform
but there is nothing under public but
index.php, favicon.ico packages robots.txt
Q2: for
Route::get('userform', function()
{
return View::make('userform');
});
what is the first "userform" represent?? according the official tutorial, it's supposed to be url, but what is the former part?
for this line
return View::make('userform')
I guess "userform" referes to the file /app/views/userform.php, right?
The .htaccess file in the public directory is responsible for funnelling all incoming requests through the index.php file. This allows Laravel to grab the URI and match it to the route you defined and eventually return to you the view you made.
So you request localhost/laravel/public/userform, the request is funnelled through index.php and Laravel is booted. Laravel picks off the userform part of the URI and matches it against your defined routes. It finds the route you defined and fires it and returns the response.
You're spot on with what you were thinking with your second question as well. When you call View::make the first argument is the name of the view you want to "make". If you named your view app/views/forms/user.php then you would return it like so in your route:
return View::make('forms.user');
Or you could use a slash:
return View::make('forms/user');
Say I have a controller, "Articles" but I want it to appear as a sub-folder (e.g. "blog/articles"), I can add a route like this:
$route['blog/articles'] = 'articles';
$route['blog/articles/(:any)'] = 'articles/$1';
This works fine, the only problem now is that example.com/articles and example.com/blog/articles both use the Articles controller and thus resolve to the same content. Is there a way to prevent this?
To add a little more clarity in case people aren't understanding:
In this example, I don't have a 'blog' controller, but I want 'articles' etc to appear to be in that subfolder (it's an organization thing).
I could have a blog controller with an 'articles' function, but I'm likely to have a bunch of 'subcontrollers' and want to separate the functionality (otherwise I could end up with 30+ functions for separate entities in the blog controller).
I want example.com/articles to return a 404 since that is not the correct URL, example.com/blog/articles is.
Shove this in your controller:
function __construct()
{
parent::Controller();
$this->uri->uri_segment(1) == 'blog' OR show_404();
}
You can use subfolders in Codeigniter controllers, so in CI, the following directory structure works:
application/controllers/blog/articles.php and is then accessed at
http://example.com/blog/articles/*.
If, for some reason, you're set on routing instead of accessing the controllers in folders (you want to have a blog controller, for example, and don't want to route to it), you can do as suggested above and add the test for 'blog' to the constructor.
If you're in PHP5, you can use the constructor function like this:
function __construct()
{
parent::Controller();
$this->uri->uri_segment(1) == 'blog' OR redirect('/blog/articles');
}
or, in PHP4, like this:
function Articles()
{
parent::Controller();
$this->uri->uri_segment(1) == 'blog' OR redirect('/blog/articles');
}
I would suggest using redirect('blog/articles') instead of show_404(), though, so that you're directing users who hit /articles to the correct location, instead of just showing them a 404 page.
Routing there does not mean it will use a different controller, it just creates alias url segment to same controller. The way will be to create another controller if you are looking to use a different controller for those url segments.
If both /blog/ and /articles/ use the same controller, you can reroute one of them to a different one by just adding a new rule in your routes file.