Check if read input is available in var - bash

Question

I try to list all Folders in /etc/nginx/html/.
I use this code:
folders=`for i in $(ls -d */ | grep -Ev "(backups)"); do echo ${i%%/}; done`
Now I get all folders with names non containing "backups".
Now I want to count the folder and save it into var. I use this code:
folders_count=( $folders )
echo ${#folders_count[#]}
It works. I get a list of all folders and I can count the folders.
Now I try to write a script that reads user input (or better, offers 1,2,3 choices, but I do not know how to do it) and install a script like Prestashop (as an example) into the folder the user has chosen if there are more than 1 folder.
Here is my code:
folders_count=( $folders )
echo ${#folders_count[#]}
echo
if [ ${#folders_count[#]} -gt 1 ]; then
echo "${info} Please choose a Website for Prestashop:" | awk '{ print strftime("[%H:%M:%S] |"), $0 }'
# for websites in $folders; do
# echo "${info} $folders" | awk '{ print strftime("[%H:%M:%S] |"), $0 }'
# echo "${info} $folders" | awk '{ print strftime("[%H:%M:%S] |"), $0 }'
# done
echo "$folders" | awk '{ print strftime("[%H:%M:%S] |"), $0 }'
#read websites_for_prestashop
read -e -i "$websites_for_prestashop" -p "Please enter your Website: " input
websites_for_prestashop="${input:-$websites_for_prestashop}"
if [ "$websites_for_prestashop" == "$folders" ]; then
echo "Website is $websites_for_prestashop"
else
echo "Website $websites_for_prestashop is not found"
fi
#echo "${info} Please choose a Website for Prestashop:" | awk '{ print strftime("[%H:%M:%S] |"), $0 }'
else
echo "nix"
fi
I dont know how I can make it work :/
Can anyone help me to fix it?
I would like to list the available folders. Then the user should be able to select in which folder he would like to install the script.
Folders:
[0] Folder 1
[1] Folder 2
[2] Folder 3
[3] Folder 4
....
Then a query will appear:
Please select an order for the installation:
The selection of the folder should then be stored in the variable read websites_for_prestashop

Answer 1

I do not know what your script is supposed to be doing. There are a bunch of lines commented out, the only assignment for websites_for_prestashop contains a reference to the variable itself and occurs after this variable is first used, and the script ultimately does nothing.
What I can tell you is that the way you extract filenames is not the right way to do it. Parsing the output of ls is not a good idea (see http://mywiki.wooledge.org/ParsingLs), and the way you do it will fail on any file with a name containing spaces, among other things.
This would be one way to do it:
declare -a folders=()
for f in */
do
[[ $f =~ backups ]] || folders+=("${f%/}")
done
echo "Folder count is: ${#folders[#]}"

Answer 2

Thank you for your help#
https://stackoverflow.com/users/2416376/olli-k
https://stackoverflow.com/users/7422249/fred
Solution is easy:
folders=`for i in $(ls -d */ | grep -Ev "(backups)"); do echo ${i%%/}; done`
echo "${info} Please choose a Website for Prestashop:" | awk '{ print strftime("[%H:%M:%S] |"), $0 }'
select websites_for_prestashop in $folders;
do
echo "You picked $websites_for_prestashop."
break
done