I need to print UID PID PPID PRI NI VSZ RSS STAT TTY TIME columns using ps of processes with typed name.
GNU nano 2.0.6
File: file2
ps o uid,pid,ppid,ni,vsz,rss,stat,tty,time | grep $2 > $1
cat $1
echo "enter pid of process to kill:"
read pid
kill -9 $pid
But it prints nothing, when I use this command with argument $2 = bash (this process exists)
UPDATE
GNU nano 2.0.6
File: file2
ps o uid,pid,ppid,ni,vsz,rss,stat,tty,time,command | grep $2 | awk '{print $1,$2,$3,$4,$5,$6,$7,$8,$9}' > $1
cat $1
echo "enter pid of process to kill:"
read pid
kill -9 $pid
This works for me, but actually this solution IMHO isn't the best one. I use shadow column command, after what grep name and print all columns excluding command.
You can always use the two-stage approach.
1.) find the wanted PIDs. For this use the simplest possible ps
ps -o pid,comm | grep "$2" | cut -f1 -d' '
the ps -o pid,comm prints only two columns, like:
67676 -bash
71548 -bash
71995 -bash
72219 man
72220 sh
72221 sh
72225 sh
72227 /usr/bin/less
74364 -bash
so grepping it is easy (and noise-less, without false triggers). The cut just extracts the PIDs. E.g. the
ps -o pid,comm | grep bash | cut -f1 -d' '
prints
67676
71548
71995
74364
2.) and now you can feed the found PIDs to the another ps using the -p flag, so the full command is:
ps -o uid,pid,ppid,ni,vsz,rss,stat,tty,time,command -p $(ps -o pid,comm | grep bash | cut -f1 -d' ')
output
UID PID PPID NI VSZ RSS STAT TTY TIME COMMAND
501 67676 67675 0 2499876 7212 S+ ttys000 0:00.04 -bash
501 71548 71547 0 2500900 8080 S ttys001 0:01.81 -bash
501 71995 71994 0 2457892 3616 S ttys002 0:00.04 -bash
501 74364 74363 0 2466084 7176 S+ ttys003 0:00.06 -bash
e.g. the solution using the $2 is
ps -o uid,pid,ppid,ni,vsz,rss,stat,tty,time,command -p $(ps -o pid,comm | grep "$2" | cut -f1 -d' ')
Related
I have simple unix shell script as follows. Which is giving different count for a service
#!/bin/bash
service=$1
ps -ef | grep $service | grep -v "grep" | wc -l
PROCESS_NUM=$(ps -ef | grep $service | grep -v "grep"| wc -l)
echo $PROCESS_NUM
In the above code below line gives output of 2.
ps -ef | grep $service | grep -v "grep" | wc -l
But when same line is assigned to variable as code below its giving output as 3.
PROCESS_NUM=$(ps -ef | grep $service | grep -v "grep"| wc -l)
echo $PROCESS_NUM
Why this is getting increased by 1 and how to tackle it.
You can see what is happening if the script tees the output to a file before counting the lines and then displaying the output after:
#!/bin/bash
service=$1
echo Directly in Script:
ps -ef | grep $service | grep -v grep | tee test.txt | wc -l
cat test.txt
echo Inside Subshell:
RESULT=$(ps -ef | grep $service | grep -v grep | tee test.txt | wc -l)
echo $RESULT
cat test.txt
When the output of a command is captured, bash starts another shell to run the command - but that subshell also shows up in the process list.
When I run that script I get:
$ ./test.sh lca
Directly in Script:
2
gcti 4268 1 0 2018 ? 21:59:03 ./lca 4999
t816826 9159 7009 0 09:22 pts/1 00:00:00 /bin/bash ./test.sh lca
Inside Subshell:
3
gcti 4268 1 0 2018 ? 21:59:03 ./lca 4999
t816826 9159 7009 0 09:22 pts/1 00:00:00 /bin/bash ./test.sh lca
t816826 9166 9159 0 09:22 pts/1 00:00:00 /bin/bash ./test.sh lca
I want my script to check if it's already running in another instance:
$ cat test.sh
#!/bin/bash
ps -ef | grep -v grep | grep -i "test.sh" | grep bash
ps -ef | grep -v grep | grep -i "test.sh" | grep -c bash
if [ `ps -ef | grep -v grep | grep -i "test.sh" | grep -c bash` -gt 1 ]; then echo "There's another instance running."
else echo "Only this instance is running."
fi
However the output is
$ ./test.sh
noes 9503 7494 0 09:32 pts/1 00:00:00 /bin/bash ./test.sh
1
There's another instance running.
Clearly, 1 is not greater than 1, so why is the if condition triggered?
Thanks
From test man page:
INTEGER1 -gt INTEGER2
INTEGER1 is greater than INTEGER2
So the answer is no, -gt is not triggered when values are equal. In fact, as you can see if you modify the script in this way:
$ cat test.sh
#!/bin/bash
ps -ef | grep -v grep | grep -i "test.sh" | grep bash
ps -ef | grep -v grep | grep -i "test.sh" | grep -c bash
STRINGS=`ps -ef | grep -v grep | grep -i "test.sh"`
echo "$STRINGS"
COUNT=`ps -ef | grep -v grep | grep -i "test.sh" | grep -c bash`
echo $COUNT
if [ `ps -ef | grep -v grep | grep -i "test.sh" | grep -c bash` -gt 1 ]; then echo "There's another instance running."
else echo "Only this instance is running."
fi
You get this:
$ ./test.sh
lucio 5097 4736 0 10:10 pts/2 00:00:00 /bin/bash ./test.sh
1
lucio 5097 4736 0 10:10 pts/2 00:00:00 /bin/bash ./test.sh
lucio 5106 5097 0 10:10 pts/2 00:00:00 /bin/bash ./test.sh
2
There's another instance running.
If you modify the script in this way, it will work:
#!/bin/bash
ps -ef | grep -v grep | grep -i "test.sh" | grep bash
pgrep -c test.sh
if [ $(pgrep -c test.sh) -gt 1 ]; then
echo "There's another instance running."
else
echo "Only this instance is running."
fi
This is the output:
$ ./test.sh
lucio 5197 4736 0 10:17 pts/2 00:00:00 /bin/bash ./test.sh
1
Only this instance is running.
Note the use $() instead of backticks. Check this answer for this change.
I have a bash script as follows:
if [[ "$1" == "stop" ]]; then
echo "[$(date +'%d/%m/%Y %H:%M:%S:%s')]: Killing all active watchers" >> $LOG
kill -9 $(ps -ef | grep "processname1" | grep -v "grep" | grep -v "$$" | awk
'{print $2}' | xargs)
echo "[$(date +'%d/%m/%Y %H:%M:%S:%s')]: Killing all current processname2
processes" >> $LOG
kill -9 $(ps -ef | grep "processname2" | grep -v "grep" | awk '{print $2}' |
xargs)
exit 0
when i run 'x service stop', the following is outputted:
kill: usage: kill [-s sigspec | -n signum | -sigspec] pid | jobspec ... or kill
-l [sigspec]
Killed
How do i stop the kill usage being displayed? It is successfully killing the process, however the fact that the usage is displayed is causing AWS CodeDeploy to fail.
Thanks!
Adam, please note that this is really just a comment with formatting. Don't take this as a real answer to your question. Please focus on the constructive comments to your question.
In my mis-spent youth, I wrote this bash function to do the ps -ef | grep .... madness:
# ps-grep
psg() {
local -a patterns=()
(( $# == 0 )) && set -- $USER
for arg do
patterns+=("-e" "[${arg:0:1}]${arg:1}")
done
ps -ef | grep "${patterns[#]}"
}
using the knowledge that the pattern [p]rocessname will not match the string [p]rocessname
I created this function to kill a process by partial name, put it in bash_profile, and executed it.
when I run it one command at a time manually, everything works.
but when I call the function, it fails with the output: "illegal process id"
function killServer() {
pid=$(ps -fe | grep '[p]rocessName' | awk '{print $2}')
if [[ -n $pid ]]; then
kill $pid
else
echo "Does not exist"
fi
}
output:
kill: illegal process id: i311821
running
ps -fe | grep '[p]rocessName'
gives:
1543721191 1947 1946 0 9:12AM ?? 0:46.76 ../../jdk/bin/java -server -da -XX:PermSize=256m Xrunjdwp:transport=dt_socket,address=8000,suspend=n,server=y -DMonitorDisabled -Xms2048m -Xmx2048m -Dwrapper.port=32000 -com.XXX.YYY.server.util.Main -b 0.0.0.0 -c default
what is the reason for that?
found the problem:
a space after $2 was missing. after the fix, it works:
ps -ef | grep "[X]XX" | grep -v grep | awk '{print $2 }' | xargs kill -9
I am trying to write a script to find a reverse SSH PID and kill it if present. I am stuck on "awk" as it gives error. below is the script:
a=('ps -aef | grep "ssh -fN" | grep -v grep | awk '{ print $2 }'')
if [ -n "$a" ]
then
echo "String \"$a\" is not null."
kill -9 "$a"
fi
I commented out if, then, kill and fi lines to debug the script. I get following error:
String "ps -aef | grep "ssh -fN" | grep -v grep | awk {" is not null.
I believe parenthesis for awk is creating the problem and I am unable to get a workaround for this. On Command line, this works perfectly and returns the correct PID.
ps -aef | grep "ssh -fN" | grep -v grep | (awk '{ print $2 }'
Once the PID is passed on to variable "a", I need to issue kill command. OS is Centos 6.4
P.S: I am not fluent on scripting but trying to achieve an objective. Help will be highly appreciated!
There are multiple problems with your script.
You need command substitution to store the output of ps pipeline into an array.
You need to check for the number of elements in the array.
Refer to the array instead of the variable.
The following might work for you:
pids=( $(ps -ef | grep '[s]sh -fN' | awk '{print $2}') )
if [ "${#pids[#]}" -gt 0 ]; then
kill -9 "${pids[#]}";
fi
First, if you have grep and then awk, you can get rid of the greps:
ps -aef | grep "ssh -fN" | grep -v grep | awk '{ print $2 }'
ps -aef |awk ' { if ( ($0 ~ /ssh -FN/) && (! $0 ~ /grep/) ) { print $2 } }'
However, instead of using ps, use pgrep.
pgrep -f "ssh -[fN][fN]" # Will match against either 'ssh -fN' or 'ssh -Nf'
There is even a pkill that will do the entire command for you:
pkill -f "ssh -[fN][fN]"
That will find all of the processes that match that particular string and kill them (if they exist).