Free jqGrid. Getting column names in conjunction with a cell - jqgrid

I'm trying to implement a data fullness check with an error output that describes which cells were not filled in the line.
//get row id
var gr = $("#" + subgrid_table_id).jqGrid('getGridParam', 'selrow');
// check row select
if (gr != null) {
/*
var myGrid = $("#" + subgrid_table_id),
selRowId = myGrid.jqGrid('getGridParam', 'selrow'),
//get cell value:
col1Value = myGrid.jqGrid('getCell', selRowId, 'stage');
//get all colnames
var columnNames = myGrid.jqGrid('getGridParam','colNames');
//get column name by index:
var col1Name = columnNames[4];
if (col1Value == "") {
alert("This data is empty: "+col1Name);
}
else {
That is, everything seems to work, but when you change the number of columns, everything can go to waste. How can I link the column name to ColNames with its name in ColModel to get a dynamic solution?

First of all all parameters of jqGrid are saved in one object available by myGrid.jqGrid('getGridParam'). Thus var selRowId = myGrid.jqGrid('getGridParam', 'selrow'); is the same as p.selrow, where var p = myGrid.jqGrid('getGridParam');.
The columns will be identified by the index in the colModel: p.colModel[iCol]. On the other side the name property of the column will be known more frequently as the index of the column iCol. Moreover, there are exist the possibility to reorder the columns by drag and drop of the column headers. One need include sortable: true option of the grid to enable the possibility. The column order can be changed by columnChooser or by direct calls of the methods remapColumns or remapColumnsByName. Because of all the reasons it's recommend to save the name of columns (which will be never changed) instead of the column index.
To get the column index by the column name one can loop over colModel array and test the value of the name property. To speed-up such operation free jqGrid provided the map object iColByName as the option of jqGrid. Thus, if you know the column name cmName then you can use var iCol = p.iColByName[cmName]; to get the column index. The column in colModel will be p.colModel[iCol] and the text of the column header will be p.colNames[iCol].
By the way, I'm not sure that you correctly understand the value of colNames. The name of the parameter is not good, but it will be used because of the compatibility with the old version. The elements of the array colNames are HTML fragments, which will be placed in the column headers. One can have empty strings inside of colNames or to have the same headers for different columns. On the other side the name property of the colModel is the real name of the column. It can't be empty. One can't use duplicate names in different columns and the names can't contains spaces.
I hope that having the above information you will easy able to find full information about every column.
The final remark. There are three main methods, which can be used to get data of the grid: getCell, getRowData and getLocalRow. jqGrid get input data, formats the data and places the formatted HTML fragments in the cells (in <td>). Additionally jqGrid saves the original raw data in internal data parameter (which is array of items, represented the rows). The data parameter exists only in case of using local data (datatype: "local") or in case of loading the data from remote set (datatype: "json" or datatype: "xml"), but with loadonce: true option additionally. The methods getCell and getRowData unformats the data from the cell(s) (from <td>) and the method getLocalRow get you direct reference to internal JavaScript object from internal data, where the data of the row are already set. Thus, it's recommended to prefer to use getLocalRow instead of getCell or getRowData whenever the grid has local data.

Related

Add row name to cde table component

I have a table component in my Pentaho CDE dashboard and data source is sql. I want to make a table like this
enter image description here
I need to add a column as row names for this table and a row on the top of column header.
I found a method here:
Table Component SubColumns
to add header, but how can i add a column before other columns?
I think a clever way to do the extra column part would be by modifying the query result object after it's retrieved from the query, so that you add the columns and rows as needed. You can do this in the PostFetch callback function, which takes the query result object as first argument:
function yourTableComponentPostFetch(queryResult) {
// Let's say you have an array of row names
var rowNames = ['Title1', 'Title2', ... ];
// Add a "title" column for every row
queryResult.resultset.forEach(function (row, idx) {
// Push it at the beginning of the row array
row.unshift(rowNames[idx]);
});
// Change metadata description of columns to reflect this new structure
queryResult.metadata.unshift({
colName: 'Title',
colIndex: -1, // this makes sense when reindexing columns below ;)
colType: 'String'
});
// One last re-indexing of metadata column descriptions
queryResult.metadata.forEach(function (column, idx) {
// The title added column will be 0, and the rest will rearrange
column.colIndex++;
});
}
The only tricky part is the part about modifying the metadata since you are effectively changing the structure of the dataset, and making sure the queryResult object is updated in-place instead of just changing its reference (queryResult = myNewQueryResult would not work), but the code I proposed should do the trick.

Remove blank column in jqGrid - Pivot

I have created a jqGrid - Pivot table JSFiddle example: here.
In this It should not print the line if Component Type value is blank, I Used this empty column, to show all periods(months) in the year, which is mandatory.
Need help in removing that blank line. and also is it possible to remove the last sum column 2015 from grid, if so how?
You includes dummy data with ComponentType:"" group which you don't want to display. So the best solution which I see would be to include the data in the input pivot data only, but don't use the dummy data in the grid data. jqPivot uses datatype: "jsonstring" to prevent additional sorting of previously sorted data. The input data will be placed as the value of datastr option. So one can use the following onInitGrid to remove the dummy data before the data will be processed by jqGrid:
onInitGrid: function () {
var p = $(this).jqGrid("getGridParam"),
userdata = p.datastr.userdata;
p.datastr = $.grep(p.datastr, function (item) {
return item.ComponentType !== "";
});
p.datastr.userdata = userdata;
}
see the modified demo http://jsfiddle.net/OlegKi/b47ocLd7/11/.

jqgrid inline saving with clientArray throws error

I am new to jqGrid and have created a simple grid with local data with editurl set to clientArray. I am using inline navigation. I can edit a row and when I press the save button, the rows gets update. So far so good.
When I press on add row button, a new empty is row is inserted. When I type in there some data and click on the save button, I get the error message:
Uncaught TypeError: Cannot read property 'extraparam' of undefined jquery.jqGrid.min.js:398
The documentation only tells how the saveRow method should be called. But, apparently the inline navigator is calling it automatically. Which is perfect. But I guess I still need to set some parameters correctly so that it does not throw the error and saves the newly added row.
Hope some jqGrid guru has a good tip. Thanks.
function createTable(data,colNames,colModel,caption ){
...
$(table).jqGrid({ data:data,
datatype: "local",
height: 'auto',
colNames:colNames,
pager:'#'+pagerid,
colModel:colModel,
viewrecords: true,
caption:caption,
editurl:'clientArray',
});
var nav = $(table).jqGrid('navGrid','#'+pagerid,{edit:false,add:false,del:false});
$(table).jqGrid('inlineNav','#'+pagerid);
$(table).jqGrid('gridResize',{minWidth:350,maxWidth:800,minHeight:80, maxHeight:350});
$('#gbox_'+tableid).draggable();
}
You are right, It's a bug in inlineNav method. The lines
if(!o.addParams.addRowParams.extraparam) {
o.addParams.addRowParams.extraparam = {};
}
uses o.addParams.addRowParams.extraparam, but default value of parameter of addParams (see here) defined as addParams : {} and not as addParams : {addRowParams: {}}. So the expression o.addParams.addRowParams is equal undefined and o.addParams.addRowParams.extraparam is the same as undefined.extraparam which produce null reference exception.
I posted the corresponding bug report to trirand and the problem will be fixed in the next version of jqGrid.
As a workaround you can replace the line
$(table).jqGrid('inlineNav','#'+pagerid);
with the line
$(table).jqGrid('inlineNav','#'+pagerid, {addParams: {addRowParams: {}}});
Some common additional remarks to your code:
I strictly recommend that you always use gridview: true option which will improve performance of your code without any disadvantages
I recommend you to use autoencode: true option per default. Per default jqGrid interpret input data of the grid as HTML fragments which must be well formatted. So if you would try to display the data like a < b you can have problems because < is special character in HTML. If you would use autoencode: true option the input data will be interpreted as text instead of HTML fragments.
I recommend you remove index property from your model if you assign always the same value for index and name properties.
I recommend you to provide id property with unique values for every item of the input data. You should understand that jqGrid always assign id attribute for every row of grid. The value must be unique over all HTML elements on the page. If you get the data from the server and the data have native unique id from the database it's recommended to use the value as the value of id property. If you don't specify any id property jqGrid assign values 1, 2, 3, ... as the id values of rows (rowids). If you use more as one jqGrids on the page and don't provide unique id values you will have id duplicates which is HTML error.
I recommend you to use idPrefix option of jqGrid. If you have two grids on the page and you don't fill (and don't need) any id for data items then you have have id duplicates (id="1", id="2" etc in both grids). If you would define idPrefix: "g1_" for one grid and idPrefix: "g2_" option for another grid then the rowids of the first grid will be id="g1_1", id="g1_2" etc in the first grid and id="g2_1", id="g2_2" in the second grid. Even if you fill the id from the server then you provide unique id inside one table, but the ids from two tables of database can have the same id. So the usage of different idPrefix option for every grid will solve the problem of id duplicates in very simple way.
I'm having this same issue but my jqgrid markup is completely different (maybe newer version?)
I can use inline to edit and save a row, but adding a row will not save. I am not sure what the issue is.
<?php
ini_set("display_errors","1");
require_once 'jq-config.php';
// include the jqGrid Class
require_once ABSPATH."php/jqAutocomplete.php";
require_once ABSPATH."php/jqCalendar.php";
require_once ABSPATH."php/jqGrid.php";
// include the driver class
require_once ABSPATH."php/jqGridPdo.php";
// Connection to the server
$conn = new PDO(DB_DSN,DB_USER,DB_PASSWORD);
// Tell the db that we use utf-8
$conn->query("SET NAMES utf8");
// Create the jqGrid instance
$grid = new jqGridRender($conn);
// Write the SQL Query
$grid->SelectCommand = 'SELECT Serial, Type, Customer, Date, Notes FROM rmas';
$resize = <<<RESIZE
jQuery(window).resize(function(){
gridId = "grid";
gridParentWidth = $('#gbox_' + gridId).parent().width();
$('#' + gridId).jqGrid('setGridWidth',gridParentWidth);
})
RESIZE;
$grid->setJSCode( $resize);
// set the ouput format to json
$grid->dataType = 'json';
$grid->table ="rmas";
$grid->setPrimaryKeyId("Serial");
// Let the grid create the model
$grid->setColModel();
// Set the url from where we obtain the data
$grid->setUrl('rmaform.php');
$grid->cacheCount = true;
//$grid->toolbarfilter = true;
$grid->setGridOptions(array(
"caption"=>"RMAs",
"rowNum"=>50,
"sortname"=>"Serial",
"hoverrows"=>true,
"rowList"=>array(50,100,200),
"height"=>600,
"autowidth"=>true,
"shrinkToFit"=>false
));
$grid->callGridMethod('#grid', 'bindKeys');
// Change some property of the field(s)
$grid->setColProperty("Serial", array("align"=>"center","width"=>40));
$grid->setColProperty("Type", array("align"=>"center","width"=>40));
$grid->setColProperty("Customer", array("align"=>"center","width"=>65));
$grid->setColProperty("Date", array("align"=>"center","width"=>40));
$grid->setColProperty("Notes", array("align"=>"left","width"=>500));
// navigator first should be enabled
$grid->navigator = true;
$grid->setNavOptions('navigator', array("add"=>false,"edit"=>false,"excel"=>true));
// and just enable the inline
$grid->inlineNav = true;
$buttonoptions = array("#pager", array(
"caption"=>"Enable Cells",
"onClickButton"=>"js:function(){ jQuery('#grid').jqGrid('setGridParam',{cellEdit: true});}", "title"=> "Enable Excel like editing"
)
);
$grid->callGridMethod("#grid", "navButtonAdd", $buttonoptions);
$buttonoptions = array("#pager", array(
"caption"=>"Disable Cells",
"onClickButton"=>"js:function(){ jQuery('#grid').jqGrid('setGridParam',{cellEdit: false});}" , "title"=> "Disable Excel like editing"
)
);
$grid->callGridMethod("#grid", "navButtonAdd", $buttonoptions);
$grid->renderGrid('#grid','#pager',true, null, null, true,true);
$conn = null;
?>

idPrefix usage in jqGrid

Given a jqGrid populated with local data and created with the option of idPrefix:"custTable" , all the generated rows get the prefix in the html id i.e. custTableRow_1 custTableRow_2 etc. Does this idPrefix'ed version of the id need to be passed in to the jqGrid methods, if so which ones?
for example to delete a row with deleteRowData does it need the prefixed id? how about setRowData or addRowData? when adding after row x it seems to need the prefixed for the srcrowid parameter. How about multiselect rows?
If I delete a row using the prefixed id of the row it disappears from the display but when I reload the grid the delete item shows up again in the grid, like it wasn't removed. This doesn't happen when idPrefix is not used.
thanks for any help.
The option idPrefix was introduced to hold ids on the HTML page unique even you have on the page the ids like the rowids loaded from the server. Typical example is two grids with the data loaded from the server. Let us you have two tables in the database where you use IDENTITY or AUTOINCREMENT in the definition of the PRIMARY KEY. In the case the primary key will be generated automatically in the table and will be unique inside the table, but there are not unique over the tables. So if you would use the primary keys as ids of the grids and place on one page two grids you can have id duplicates.
To solve the problem you can use idPrefix: "a" as additional option in the first grid and use idPrefix: "b" in the second grid. In the case locally jqGrid will uses everywhere ids with the prefix, but the prefix will be cut if the ids will be sent to the server.
So you will see locally in all callbacks (events) and in all methods (like setRowData, addRowData etc) the ids with the prefix, but on the server side the ids the prefixes will be removed immediately before sending to the server.
I recommend you additionally to read another answer about the restrictions in the ids which I posted today.
UPDATED: I looked through the code which you posed on jsfiddle and found some clear bugs in your code. You current code
1) use wrong algorithm to generate id of the new row. For example the following code
// generic way to create an animal
function newAnimal(collection, defaults) {
var next = collection.length + 1;
var newpet = {
id : next,
name: defaults.name + next,
breed: defaults.breed
};
return newpet;
}
use collection.length + 1 for the new id. It's wrong if you allows to delete the items. By adding of two items, deleting one from there and adding new item one more time follows to id duplicates. Instead of that it's more safe to use some variable which will be only incremented. You can use $.jgrid.randId() for example which code is very simple.
2) you call addRowData with adding a prefix manually (see dogsPrefix+newdog.id below). It's wrong because jqGrid adds the prefix one more time to the rows.
// add dog button actions
$('#dogAddAtEnd').click(function() {
var newdog = newAnimal(dogs, dogDefaults);
dogs.push(newdog);
dogAdded();
dogsTable.jqGrid('addRowData', dogsPrefix+newdog.id, newdog);
});
Probably there are more problems, but at least these problems can explain the problems which you described.
UPDATED 2: I examined new demo which you posted. It has still the lines
grid.jqGrid('addRowData', newanimal.id, newanimal,
"after", prefix+ followingId);
and
dogsTable.jqGrid('addRowData', dogsPrefix+newdog.id, newdog);
which must be fixed to
grid.jqGrid('addRowData', newanimal.id, newanimal,
"after", followingId);
and
dogsTable.jqGrid('addRowData', newdog.id, newdog);
Nevertheless I tested the demo after the changes and found bugs in code of addRowData, delRowData and setRowData. The problem are in the line of the delRowData and the same line of setRowData
var pos = $t.p._index[rowid];
can be fixed to the following
var id = $.jgrid.stripPref($t.p.idPrefix, rowid), pos = $t.p._index[id];
Inside of addRowData I suggest to include the line
var id = rowid; // pure id without prefix
before the line
rowid = t.p.idPrefix + rowid;
of addRowData. Another tow lines of addRowData
lcdata[t.p.localReader.id] = rowid;
t.p._index[rowid] = t.p.data.length;
should be changed to
lcdata[t.p.localReader.id] = id;
t.p._index[id] = t.p.data.length;
where unprefixed id will be used.
The modified code of you demo which uses the fixed version of jquery.jqGrid.src.js you can test here.
I will post my bug report to trirand later to inform the developer of the jqGrid. I hope that soon the bug fix will be included in the main code of jqGrid.
Additionally I recommend you to use $.jgrid.stripPref method to strip prefixes from the rowids. For example the function
//general delete selected
function deleteSelectedAnimal(list, grid, prefix)
{
var sel = grid.jqGrid('getGridParam', 'selrow');
if (sel.length)
{
var gridrow = sel;
//get the unprefixed model id
var modelid = gridrow;
if (prefix.length !== 0)
{
modelid = modelid.split(prefix)[1];
}
// make it a numeric
modelid = Number(modelid);
//delete the row in the collection
list = RemoveAnimal(list, modelid);
//delete the row in the grid
grid.jqGrid('delRowData', gridrow);
}
}
from your demo can be rewritten to the following
//general delete selected
function deleteSelectedAnimal(list, grid)
{
var sel = grid.jqGrid('getGridParam', 'selrow'),
gridPrefix = grid.jqGrid('getGridParam', 'idPrefix');
if (sel !== null)
{
//delete the row in the collection
// ??? the gogs list will be not modified in the way !!!
list = RemoveAnimal(list, $.jgrid.stripPref(gridPrefix, sel));
//delete the row in the grid
grid.jqGrid('delRowData', sel);
}
}
I am not sure that the line list = RemoveAnimal(list, $.jgrid.stripPref(gridPrefix, sel)); or the function RemoveAnimal do what you want, but it's not a problem which connected with jqGrid.
One more small remark about your code. You use already in the objects which you add to the grid the id property. It's the same name as defined in the localReader.id. In the case the data from the id property will be used as id attribute of the grid rows (<tr>). The local data parameter will save the id additionally to other properties which are build from the name property of the items of colModel. So I see no sense to define hidden column
{ key: true, name: 'id', align: 'left', hidden: true }
How you can see on the demo all stay works exactly as before if you remove id column from the grids which you use.
UPDATED 3: As promised before I posted the corresponding bug report here.

jqgrid randId() produces duplicates after page reload

On my grid, after a user enters text on the bottom row, I am adding another row so they can fill out another row if needed. The grid will grow as needed by the user. This is working fine, however after a page reload and populating from db, the addrowdata() function does not honor existing row ids and creates duplicates, starting from 1 again, e.g. jqg1. It should look at existing row ids and create new unique ids. So if I have 5 rows already, it might start at jqg6. Here is the relevant code inside onCellSelect:
var records = jQuery("#table-1").jqGrid('getGridParam', 'records');
var lastRowId = jQuery("#table-1").jqGrid('getDataIDs')[records - 1];
if (lastRowId == id)
{
jQuery('#table-1').addRowData(undefined, {}, 'last');
}
I have also tried $.jgrid.randId() instead of undefined, same results as expected.
Thanks
Ryan
I think that the error is in the part where you fill grid with the data from the database. The data saved in the database has unique ids. The ids are not in the form jqg1, jqg2, ... So if should be no conflicts. You should just fill the id fields of the JSON with the ids from the database.
One more possibility is that you just specify the rowid parameter (the first parameter) of addRowData yourself. In the case you will have full control on the new ids of the rows added in the grid.
The code of $.jgrid.randId function is very easy. There are $.jgrid.uidPref initialized as 'jqg' and $.jgrid.guid initialized to 1. The $.jgrid.randId function do the following
$.jgrid.randId = function (prefix) {
return (prefix? prefix: $.jgrid.uidPref) + ($.jgrid.guid++);
}
If it is really required you can increase (but not decrease) the $.jgrid.guid value without any negative side effects.

Resources