bash to identify and verify file headers - bash

Question

Using the tab-delimited file below I am trying to validate the header line 1 and then store that number in a variable $header to use in a couple of if statements. If $header equals 10 then file has expected number of fields, but if $header less than 10 file is missing header for: and the missing header fields are printed underneath. The bash seems close and if i use the awk by itself it seems to work perfectly, but I can not seem to use it in the if. Thank you :).
file.txt
Index Chr Start End Ref Alt Freq Qual Score Input
1 1 1 100 C - 1 GOOD 10 .
2 2 20 200 A C .002 STRAND BIAS 2 .
3 2 270 400 - GG .036 GOOD 6 .
file2.txt
Index Chr Start End Ref Alt Freq Qual Score
1 1 1 100 C - 1 GOOD 10
2 2 20 200 A C .002 STRAND BIAS 2
3 2 270 400 - GG .036 GOOD 6
bash
for f in /home/cmccabe/Desktop/validate/*.txt; do
bname=`basename $f`
pref=${bname%%.txt}
header=$(awk -F'\t' '{print NF, "fields detected in file and they are:" ORS $0; exit}') $f >> ${pref}_output # detect header row in file and store in header and write to output
if [[ $header == "10" ]]; then # display results
echo "file has expected number of fields" # file is validated for headers
else
echo "file is missing header for:" # missing header field ...in file not-validated
echo "$header"
fi # close if.... else
done >> ${pref}_output
desired output for file.txt
file has expected number of fields
desired output for file1.txt
file is missing header for:
Input

Answer 1

You can use awk if you like, but bash is more than capable of handling the first line fields comparison on its own. If you maintain an array of expected field names, you can then easily split the first line into fields, compare against the expected number of fields, and output the identity of the missing field if you read less than the expected number of fields from any given file.
The following is a short example that takes filenames as arguments (you need to take filenames from stdin for a large number of files, or use xargs, as required). The script simply reads the first line in each file, separates the line into fields, checks the field count, and outputs any missing fields in a short error message:
#!/bin/bash
declare -i header=10 ## header has 10 fields
## aray of field names (can be read from 1st file)
fields=( "Index"
"Chr"
"Start"
"End"
"Ref"
"Alt"
"Freq"
"Qual"
"Score"
"Input" )
for i in "$#"; do ## for each file given as argument
read -r line < "$i" ## read first line from file into 'line'
oldIFS="$IFS" ## save current Internal Field Separator (IFS)
IFS=$'\t' ## set IFS to word-split on '\t'
fldarray=( $line ); ## fill 'fldarray' with fields in line
IFS="$oldIFS" ## restore original IFS
nfields=${#fldarray[#]} ## get number of fields in 'line'
if (( nfields < header )) ## test against header
then
printf "error: only '%d' fields in file '%s'\nmissing:" "$nfields" "$i"
for j in "${fields[#]}" ## for each expected field
do ## check against those in line, if not present print
[[ $line =~ $j ]] || printf " %s" "$j"
done
printf "\n\n" ## tidy up with newlines
fi
done
Example Input
$ cat dat/hdr.txt
Index Chr Start End Ref Alt Freq Qual Score Input
1 1 1 100 C - 1 GOOD 10 .
2 2 20 200 A C .002 STRAND BIAS 2 .
3 2 270 400 - GG .036 GOOD 6 .
$ cat dat/hdr2.txt
Index Chr Start End Ref Alt Freq Qual Score
1 1 1 100 C - 1 GOOD 10
2 2 20 200 A C .002 STRAND BIAS 2
3 2 270 400 - GG .036 GOOD 6
$ cat dat/hdr3.txt
Index Chr Start End Alt Freq Qual Score Input
1 1 1 100 - 1 GOOD 10 .
2 2 20 200 C .002 STRAND BIAS 2 .
3 2 270 400 GG .036 GOOD 6 .
Example Use/Output
$ bash hdrfields.sh dat/hdr.txt dat/hdr2.txt dat/hdr3.txt
error: only '9' fields in file 'dat/hdr2.txt'
missing: Input
error: only '9' fields in file 'dat/hdr3.txt'
missing: Ref
Look things over, while awk can do many things bash cannot on its own, bash is more than capable with parsing text.

Answer 2

Here is one in GNU awk (nextfile):
$ awk '
FNR==NR {
for(n=1;n<=NF;n++)
a[$n]
nextfile
}
NF==(n-1) {
print FILENAME " file has expected number of fields"
nextfile
}
{
for(i=1;i<=NF;i++)
b[$i]
print FILENAME " is missing header for: "
for(i in a)
if(i in b==0)
print i
nextfile
}' file1 file1 file2
file1 file has expected number of fields
file2 is missing header for:
Input
The first file processed by the script defines the headers (in a) that the following files should have and compares them (in b) against it.

Answer 3

This piece of code will do exactly what you are asking. Let me know if it works for you.
for f in ./*.txt; do
[[ $( head -1 $f | awk '{ print NF}' ) -eq 10 ]] && echo "File $f has all the fields on its header" || echo "File $f is missing " $( echo "Index Chr Start End Ref Alt Freq Qual Score Input $( head -1 $f )" | tr ' ' '\n' | sort | uniq -c | awk '/1 / {print $2}' );
done
Output :
File ./file2.txt is missing Input
File ./file.txt has all the fields on its header