In Oracle I have a table with a DB_FLD_4 defined as VARCHAR2(20 BYTE) but actually holds DATE information with looks like this:
select DB_FLD_4 from DM_SUPDES_DISTRIB order by DB_FLD_4 desc;
4/9/2017
4/7/2017
4/6/2017
Kind of m/d/yyyy format.
I would like to create SP that would delete every day rows from the table older than 1 month.
My sysdate looks like this:
select sysdate from dual;
SYSDATE
24-APR-17 04.41:00
Please help to manipulate formats to make this possible.
Many thanks !!!
Use to_date() on your column, then trunc the sysdate to "round" to the day
delete
from MyTable
where to_date(MyColumn, 'MM/DD/YYYY') < add_months(trunc(sysdate), -1)
Related
I want to insert some records with insert into select query in oracle. My condition should be when month of CREATE_DATE in SITA_HOSTS table is equal with month of sysdate - 1. Now my question is what should I write for the where statement?
This is my code:
DECLARE
p_year VARCHAR2(50);
n_year NUMBER;
n_month NUMBER;
j_year VARCHAR2(4);
j_month VARCHAR2(4);
c_month NUMBER;
BEGIN
SELECT TO_CHAR(sysdate, 'YYYY-MM-DD','nls_calendar=persian') INTO p_year FROM dual; --Change sysdate to jalali date
SELECT regexp_substr(p_year,'[^-]+', 1, 1) INTO j_year
FROM dual; -- Get year of jalalian sysdate
SELECT regexp_substr(p_year,'[^-]+', 1, 2) INTO j_month
FROM dual;--Get month of jalalian sysdate
n_year := TO_NUMBER(j_year);
n_month := TO_NUMBER(j_month);
insert into sita_orders(REL_MODULE,REL_ID,CREATE_DATE,AMOUNT,CUSTOMER_ID,PROJECT_ID,ORDER_STATUS,TITLE,YEAR)
SELECT 1,ID,sysdate,78787878,CUSTOMER_ID,PROJECT_ID,0,HOSTING_TITLE,j_year
FROM SITA_HOSTS
WHERE ????;
END;
At the end I should say that my date is Jalali date
Here is one way:
WHERE TRUNC(create_date,'MM') = ADD_MONTHS(TRUNC(SYSDATE,'MM'), -1)
TRUNC(date, 'MM') truncates to midnight on the first day of the month of the date.
It really depends on the content/meaning and data type of create_date within sita-hosts table. In addition to that is the requirement also unclear. Shall the insert also cover hosts that were created a couple of years ago or only the ones created last month.
solution for the hosts created during the last month. With trying to enforce the usage of indexes if there are some.
select <your select list>
from sita_hosts
where create_date between add_months(trunc(sysdate,'mm')-1) and trunc(sysdate,'mm')
and create_date < trunc(sysdate,'mm')
the second where clause will exclude all times that are on the start of this month just at midnight.
Thanks a lot guys. I have written this code and it works fine:
insert into sita_orders(REL_MODULE,REL_ID,CREATE_DATE,AMOUNT,CUSTOMER_ID,PROJECT_ID,ORDER_STATUS,TITLE,YEAR)
SELECT 1,ID,sysdate,100000,CUSTOMER_ID,PROJECT_ID,0,HOSTING_TITLE,TO_CHAR(sysdate, 'YYYY','nls_calendar=persian')
FROM SITA_HOSTS
WHERE
to_number(TO_CHAR(CREATE_DATE, 'MM','nls_calendar=persian')) <= to_number(TO_CHAR(sysdate, 'MM','nls_calendar=persian') - 1)
and ID not in (
select REL_ID from sita_orders where REL_MODULE=1 and YEAR=TO_CHAR(sysdate, 'YYYY','nls_calendar=persian')
);
This is how my Date column looks like
RPT_DT (Data Type is Number)
20180131
20180130
20180129
I wanna extract month out of these dates(either Month or mm), and I tried below
select extract(month from to_date(Rpt_dt))
from
(
select distinct to_char(to_date(RPT_DT,'yyyymmdd'),'mm/dd/yyyy') Rpt_dt
from TABLE_NAME
)
I am getting the error "Not a valid month"
if there is not any particular reason to have a double conversion I would suggest you to handle the problem with this simple query:
select substr(to_char(RPT_DT),5,2)from THE_TABLE
this query should be more performant since it make only one conversion. in your sample you transform:
a number to a date
then a date to a char
the char again in date
finally you extract the month
let me know if it help
r.
try this,
SELECT EXTRACT(MONTH FROM TO_DATE(rpt_dt, 'YYYYMMDD'))
FROM TABLE_NAME;
and I believe you need to modify your query as you did not put the format 'MM/DD/YYYY',
select extract(month from to_date(Rpt_dt, 'MM/DD/YYYY'))
from
(
select distinct to_char(to_date(RPT_DT,'yyyymmdd'),'mm/dd/yyyy') Rpt_dt
from TABLE_NAME
)
This back-and-forth conversion is useless. Try this
select
extract(month from to_date(RPT_DT,'yyyymmdd'))
from TABLE_NAME;
What is the query in Oracle to fetch the data for current_date
the column end_date is like the following
end_date
27-10-16 03:35:00.000000000 PM
23-11-16 11:15:00.000000000 AM
02-11-16 03:00:00.000000000 PM
08-11-16 09:00:00.000000000 AM
Like I am running the following query as
Select * from table1
where end_date < TO_DATE('2017-04-11 00:00:00', 'YYYY-MM-DD HH24:MI:SS')
it is running successfully, but when i replace the query with the current date ... it is not giving the results
Select * from table1
where end_date < TO_DATE(current_date, 'YYYY-MM-DD HH24:MI:SS')
could someone tell me what is the cause the second query is not giving results.
CURRENT_DATE returns date. There is no need to use TO_DATE. The below query should be enough.
Select * from table1
where end_date < current_date;
If you run the below query you'll understand what went wrong for you. Year becomes 0011.
SELECT TO_DATE(current_date, 'YYYY-MM-DD HH24:MI:SS') FROM DUAL;
Please note that CURRENT_DATE returns the current date in the session time zone. SYSDATE returns the current date and time set for the operating system on which the database resides. This means that CURRENT_DATE and SYSDATE can return different results. You can have a look at this
The query worked like this :
Select * from table1
where trunc(end_date) < trunc(sysdate)
Trunc is used to compare the both dates and it fetch the results.
CURRENT_DATE is already a DATE value. You can format the output using to_char if you want.
end_date < CURRENT_DATE should do the job. Or you can set the nls parameter accordingly for a better readability.
If you are comparing only date, without timestamp, you can go with trunc()
I want to create an Oracle table which contains 3-4 columns in which I want to insert just time in one of the columns.
First, I set the datatype of that column to varchar2 but then I am unable to do any operations on that time.
create table attendance(
ID varchar2(10),
EmpIntime varchar2(10) ,
EmpoutTime varchar2(10));
I want to insert time in 9:00AM format and calculate total time.
Here is DEMO
i want output like that
"emp_in - emp_out = total working hours"
Just make it with to_date like below
select to_date(emp_out,'HH:MIAM')-to_date(emp_in,'HH:MIAM') from attendance
made an sqlfiddle http://sqlfiddle.com/#!4/96975/8 with the hours difference between time
Try this one,this will give you time in hours,minutes and seconds :-
create table attend(ID int,emp_in varchar2(10) ,emp_out varchar2(10));
insert all
into attend values(1,'09:00AM','05:00PM')
into attend values(2,'09:30AM','05:00PM')
into attend values(3,'10:00AM','08:00PM')
select * from dual;
commit;
select outtime-intime time_difference
from(
select to_timestamp(EMP_IN, 'hh:mi am') intime ,
to_timestamp(EMP_OUT, 'hh:mi am') outtime
FROM attend);
I have database, where i have inserted timestamps(6) in this format :
18-AUG-14 02.49.27.000000000 PM .
I want to extract it into this: 2014-08
Its called ISO 8601
You'll need to use the to_char function to extract the year-month from timestamp.
select to_char(timestamp, 'yyyy-mm') from your_table
I've done this in this way -
select extract(year from timestmp) || '-' || extract(month from timestmp) from texmp1;
Hope this helps.
Here is the table structure:
create table texmp1
(
timestmp timestamp
);