Extra argument error in call [duplicate] - swift2

Question

This question already has answers here:
Swift: Extra argument 'error' in call
(3 answers)
Closed 5 years ago.
I have been trying to login for a while using php but I have a final bug that stops me from finishing. It turns out to give a bug in NSJSONSerialization where the error tells me: error extra argument in call. Then I will provide a screenshot so that the error is clearer and the code so you can help me since I am in a blocking moment and I do not know how to solve it. Thanks in advance
Photo error: [
Code:
#IBAction func loginButtonTapped(sender: AnyObject) {
let userEmail = userEmailTextField.text;
let userPassword = userPasswordTextField.text;
if(userEmail!.isEmpty || userPassword!.isEmpty) { return; }
let myUrl = NSURL(string: "http://localhost/billapp/userSignIn.php");
let request = NSMutableURLRequest(URL:myUrl!);
request.HTTPMethod = "POST";
let postString = "userEmail=\(userEmail)&userPassword=\(userPassword)";
request.HTTPBody = postString.dataUsingEncoding(NSUTF8StringEncoding);
let task = NSURLSession.sharedSession().dataTaskWithRequest(request){
data, response, error in
if error != nil{
print("error=\(error)")
return
}
var err: NSError?
var json = NSJSONSerialization.JSONObjectWithData(data, options: .MutableContainers, error:NSError) as? NSDictionary
if let parseJSON = json {
var resultValue:String = parseJSON["status"] as String!;
print("result: \(resultValue)")
if(resultValue=="Success")
{
NSUserDefaults.standardUserDefaults().setBool(true, forKey: "isUserLoggedIn");
NSUserDefaults.standardUserDefaults().synchronize();
self.dismissViewControllerAnimated(true, completion: nil);
}
}
}
task.resume()
}
last error

Answer 1

You can follow the quick fix sugestions. Doing so will let you end up like this:
do {
var json = try JSONSerialization.jsonObject(with: Data(), options: .mutableContainers)
if let parseJSON = json {
//your code
}
} catch {
//handle error
}

Answer 2

Unlike Objective C, as per the new methodolgy in Swift, errors are handled using try/catch block instead of passing the error object in the method.
Use the following code for Swift 3.
do {
var json = try JSONSerialization.jsonObject(with: data, options: .mutableContainers)
if let parseJSON = json {
var resultValue:String = parseJSON["status"] as String!;
print("result: \(resultValue)")
if(resultValue=="Success")
{
NSUserDefaults.standardUserDefaults().setBool(true, forKey: "isUserLoggedIn");
NSUserDefaults.standardUserDefaults().synchronize();
self.dismissViewControllerAnimated(true, completion: nil);
}
}
} catch let error {
//Perform the error handling here
}
Following for Swift 2
do {
var json = try NSJSONSerialization.JSONObjectWithData(data, options: .MutableContainers)
if let parseJSON = json {
var resultValue:String = parseJSON["status"] as String!;
print("result: \(resultValue)")
if(resultValue=="Success")
{
NSUserDefaults.standardUserDefaults().setBool(true, forKey: "isUserLoggedIn");
NSUserDefaults.standardUserDefaults().synchronize();
self.dismissViewControllerAnimated(true, completion: nil);
}
}
} catch let error {
//Perform the error handling here
}