Round off time value to before midnight in oracle sql - oracle

Question

I am writing a query that will allow me to workout dates for when particular jobs need to be completed.
The following is a list of my jobs and codes.
JOB_NO | CODES | RCVD_TIME
ABC1 | 1 | 07-JAN-17 09:44:07
DEF2 | 3 | 20-MAR-17 14:32:49
GHI3 | 3 | 27-MAR-17 10:00:03
JKL4 | 1 | 12-JAN-17 12:59:05
Now I have a few conditions in order to workout the end date/time for these jobs.
Code 1 - Add 1 day + anytime until 23:59:59
Code 3 - If rcvd time is before 1pm then job to be completed same day until 23:59:59, if rcvd time is 1pm or after then job to be completed before 1pm next day.
My simple query:
SELECT
JOB_NO, CODES, RCVD_TIME,
CASE
WHEN CODES = '1'
THEN RCVD_TIME + 1
ELSE RCVD_TIME
END AS TARGET
FROM...
This gives me (not sure how to write query for codes 3):
JOB_NO | CODES | RCVD_TIME | TARGET
ABC1 | 1 | 07-JAN-17 09:44:07 | 08-JAN-17 09:44:07
DEF2 | 3 | 20-MAR-17 14:32:49 | 20-MAR-17 14:32:49
GHI3 | 3 | 27-MAR-17 10:00:03 | 27-MAR-17 10:00:03
JKL4 | 1 | 12-JAN-17 12:59:05 | 13-JAN-17 12:59:05
This is what I would like:
JOB_NO | CODES | RCVD_TIME | TARGET
ABC1 | 1 | 07-JAN-17 09:44:07 | 08-JAN-17 23:59:59
DEF2 | 3 | 20-MAR-17 14:32:49 | 21-MAR-17 13:00:00
GHI3 | 3 | 27-MAR-17 10:00:03 | 27-MAR-17 23:59:59
JKL4 | 1 | 12-JAN-17 12:59:05 | 13-JAN-17 23:59:59
Would really appreciate if somebody could advise on how I can get my required answer.
Thanks in advance.
EDIT
bit frustrating but been told to add one more condition to consider working day of the week is between 1 and 6 so have to make sure the target time does not fall into a sunday (day 7). sorry guys for the double, just thought I would add it here in case it gets missed.

Answer 1

You can use a CASE statement in your SQL to handle your complex if-then logic.
-- TEST_DATA is not part of the solution
with test_data ( job_no, code, rcvd_time, target ) AS (
SELECT 'ABC1',1,to_date('07-JAN-17 09:44:07','DD-MON-YY HH24:MI:SS'),to_date('08-JAN-17 09:44:07','DD-MON-YY HH24:MI:SS') FROM DUAL UNION ALL
SELECT 'DEF2',3,to_date('20-MAR-17 14:32:49','DD-MON-YY HH24:MI:SS'),to_date('20-MAR-17 14:32:49','DD-MON-YY HH24:MI:SS') FROM DUAL UNION ALL
SELECT 'GHI3',3,to_date('27-MAR-17 10:00:03','DD-MON-YY HH24:MI:SS'),to_date('27-MAR-17 10:00:03','DD-MON-YY HH24:MI:SS') FROM DUAL UNION ALL
SELECT 'JKL4',1,to_date('12-JAN-17 12:59:05','DD-MON-YY HH24:MI:SS'),to_date('13-JAN-17 12:59:05','DD-MON-YY HH24:MI:SS') FROM DUAL)
-- Actual solution begins here...
SELECT job_no, code, rcvd_time,
case
when rcvd_time - trunc(rcvd_time) < 13/24 and code = 1 then
trunc(rcvd_time) + (86399/86400) + 1
when rcvd_time - trunc(rcvd_time) < 13/24 and code = 3 then
trunc(rcvd_time) + (86399/86400)
when rcvd_time - trunc(rcvd_time) >= 13/24 then
trunc(rcvd_time) + 1 + (13/24)
end target
from test_data;

Answer 2

You can use interval literals (so you do not need to sprinkle magic numbers throughout your code):
CASE
WHEN code = 1
THEN TRUNC( rcvd_time ) + INTERVAL '2' DAY - INTERVAL '1' SECOND
WHEN code = 3 AND TO_CHAR( rcvd_time, 'HH24' ) < '13'
THEN TRUNC( rcvd_time ) + INTERVAL '1' DAY - INTERVAL '1' SECOND
WHEN code = 3 -- AND TO_CHAR( rcvd_time, 'HH24' ) >= '13'
THEN TRUNC( rcvd_time ) + INTERVAL '1' DAY + INTERVAL '13' HOUR
END
To compare the time you can use various different techniques:
TO_CHAR( rcvd_time, 'HH24' ) < '13'
EXTRACT( HOUR FROM CAST( rcvd_time AS TIMESTAMP ) ) < 13
rcvd_time < TRUNC( rcvd_time ) + INTERVAL '13' HOUR

Answer 3

In the solution below, I assume that the "special" handling applies only when CODES is 3, otherwise the TARGET is the end of the next day. (This allows CODES values other than 1 and 3... you can adapt if you have more CODES values and additional rules.)
Since all TARGET date-times are offset from trunc(rcvd_time), I use a CASE expression just to determine the offset.
select job_no, codes, rcvd_time,
trunc(rcvd_time) +
case codes when 3 then
case when extract (hour from cast (rcvd_time as timestamp)) < 13
then interval '23:59:59' hour to second
else interval '1 13:00:00' day to second
end
else interval '1 23:59:59' day to second
end as target
from your_table;
NOTE: Thanks to MT0 for showing the ways to extract hour from a date; I had forgotten that extract(hour from...) works only for timestamps. I edited my answer accordingly.

Answer 4

Try this
select
t.*
,case when codes=3
and to_date(to_char(rcvd_time,'HH24:MI:SS'),'HH24:MI:SS')
>=to_date('13:00:00','HH24:MI:SS')
then trunc(rcvd_time)+1+(13/24) -- add 1 day and then add 13 hours
when codes=1
then trunc(rcvd_time)+2-(1/(24*60*60)) --add 2 days and subtract 1 second
else
trunc(rcvd_time)+1-(1/(24*60*60)) -- add 1 day and subtract 1 second
end as target
from tbl t;
Working sample
with tbl (JOB_NO,CODES,RCVD_TIME) as (
select 'ABC1',1,to_date('07-JAN-17 09:44:07','DD-MON-YY HH24:MI:SS') from dual union all
select 'DEF2',3,to_date('20-MAR-17 14:32:49','DD-MON-YY HH24:MI:SS') from dual union all
select 'GHI3',3,to_date('27-MAR-17 10:00:03','DD-MON-YY HH24:MI:SS') from dual union all
select 'JKL4',1,to_date('12-JAN-17 12:59:05','DD-MON-YY HH24:MI:SS') from dual)
select
t.*
,case when codes=3
and to_date(to_char(rcvd_time,'HH24:MI:SS'),'HH24:MI:SS')
>=to_date('13:00:00','HH24:MI:SS')
then trunc(rcvd_time)+1+(13/24) -- add 1 day and then add 13 hours
when codes=1
then trunc(rcvd_time)+2-(1/(24*60*60)) --add 2 days and subtract 1 second
else
trunc(rcvd_timeJOB_NO,CODES,RCVD_TIME)+1-(1/(24*60*60)) -- add 1 day and subtract 1 second
end as target
from tbl t;
Output
JOB_NO CODES RCVD_TIME TARGET
ABC1 1 07-JAN-2017 09:44:07 08-JAN-2017 23:59:59
DEF2 3 20-MAR-2017 14:32:49 21-MAR-2017 13:00:00
GHI3 3 27-MAR-2017 10:00:03 27-MAR-2017 23:59:59
JKL4 1 12-JAN-2017 12:59:05 13-JAN-2017 23:59:59