How do I redirect stdout from a program continuously into a spawned process using expect? - bash

Question

Need to open telnet, send a few commands and then send stdout from pocketsphinx.
Currently expect will wait until the program is finished and then output everything to the telnet process.
I need pocketsphix to continuously feed the spawned telnet process.
This is what I have so far:
#!/usr/bin/expect -d
set send_human {.1 .3 1 .05 2}
spawn telnet 192.168.1.104 23
expect “*”
send "\x01"; send "2\r"
expect “:”
send -h "hello world\r"
send -h "goodbye world\r"
send -h "Test Test Test\r"
send -- [exec pocketsphinx_continuous -infile speech.wav 2> /dev/null ]\n

Answer 1

You can use expect command interact for connecting together two spawned processes.
By default, interact expects the user to be writing stdin and reading stdout of the Expect process
itself. The -u flag (for "user") makes interact look for the user as the process named by its argument
(which must be a spawned id).
This allows two unrelated processes to be joined together without using an explicit loop. To aid in
debugging, Expect diagnostics always go to stderr (or stdout for certain logging and debugging information).
For the same reason, the interpreter command will read interactively from stdin.
For example
set send_human {.1 .3 1 .05 2}
spawn telnet 192.168.1.104 23
expect “*”
send "\x01"; send "2\r"
expect “:”
send -h "hello world\r"
send -h "goodbye world\r"
send -h "Test Test Test\r"
set sid_telnet $spawn_id
spawn pocketsphinx_continuous -infile speech.wav 2> /dev/null
interact -u $sid_telnet