sec:authorize access="hasRole('ROLE_USER')" doesn't work - spring

Question

My menu.jspx doesn't work correctly. I can see both <sec:authorize access
<sec:authorize access="hasRole('ROLE_USER')">
<h3>${menuAddContact}</h3><!--будет отображатсья только если юзер зашел и нужной ролью-->
</sec:authorize>
<sec:authorize access="isAnonymous()"><!--Если не зашел то отбражается форма входа-->
<div id="login">
<form name="loginForm" action="${loginUrl}" method="post">
<table>
<caption align="left">Login:</caption>
<tr>
<td>User Name:</td>
<td><input type="text" name="j_username"/></td>
</tr>
<tr>
<td>Password:</td>
<td><input type="password" name="j_password"/></td>
</tr>
<tr>
<td colspan="2" align="center"><input type="submit"
name="submit"
value="Login"/></td>
</tr>
</table>
</form>
</div>
<?xml version="1.0" encoding="UTF-8" standalone="no"?>
<div id="menu" xmlns:jsp="http://java.sun.com/JSP/Page"
xmlns:c="http://java.sun.com/jsp/jstl/core"
xmlns:spring="http://www.springframework.org/tags"
xmlns:sec="http://www.springframework.org/security/tags"
version="2.0">
<jsp:directive.page contentType="text/html;charset=UTF-8" />
<jsp:output omit-xml-declaration="yes" />
<spring:message code="menu_header_text" var="menuHeaderText"/>
<spring:message code="menu_add_contact" var="menuAddContact"/>
<spring:url value="/contacts?form" var="addContactUrl"/>
<spring:message code="label_login" var="labelLogin"/>
<spring:url var="loginUrl" value="/j_spring_security_check"/>
<h3>${menuHeaderText}</h3>
<sec:authorize access="hasRole('ROLE_USER')">
<h3>${menuAddContact}</h3><!--будет отображатсья только если юзер зашел и нужной ролью-->
</sec:authorize>
<sec:authorize access="isAnonymous()"><!--Если не зашел то отбражается форма входа-->
<div id="login">
<form name="loginForm" action="${loginUrl}" method="post">
<table>
<caption align="left">Login:</caption>
<tr>
<td>User Name:</td>
<td><input type="text" name="j_username"/></td>
</tr>
<tr>
<td>Password:</td>
<td><input type="password" name="j_password"/></td>
</tr>
<tr>
<td colspan="2" align="center"><input type="submit"
name="submit"
value="Login"/></td>
</tr>
</table>
</form>
</div>
</sec:authorize>
</div>
And in my header
<sec:authorize access="isAuthenticated()">${labelWelcome}
<sec:authentication property="principal.username" />
username does not exist(
It seems that spring security does not exist(
<?xml version="1.0" encoding="UTF-8"?>
<beans:beans xmlns="http://www.springframework.org/schema/security"
xmlns:beans="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/security
http://www.springframework.org/schema/security/spring-security.xsd">
<http use-expressions="true">
<intercept-url pattern='/WEB-INF' access='permitAll' />
<form-login login-page="/contacts" authentication-failure-url="/security/loginfail"
default-target-url="/contacts" />
<logout logout-success-url="/contacts"/>
</http>
<authentication-manager>
<authentication-provider>
<user-service>
<user name="user" password="user" authorities="ROLE_USER" />
</user-service>
</authentication-provider>
</authentication-manager>
</beans:beans>
But, if i use F12 in my browser i can see that spring return form data correctly
j_username:user
j_password:user
submit:Login
help me please( where my mistake?
UPD:
web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
version="3.0">
<display-name>java-blog-aggregator</display-name>
<context-param>
<param-name>spring.profiles.default</param-name>
<param-value>jdbc,mysql</param-value>
<!--<param-value>hibernate,mysql</param-value>-->
<!--<param-value>datajpa,mysql</param-value>-->
</context-param>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring/root-context.xml</param-value>
</context-param>
<servlet>
<servlet-name>dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring/dispatcher-servlet.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<filter>
<filter-name>CharacterEncodingFilter</filter-name>
<filter-class>org.springframework.web.filter.CharacterEncodingFilter</filter-class>
<init-param>
<param-name>encoding</param-name>
<param-value>UTF-8</param-value>
</init-param>
<init-param>
<param-name>forceEncoding</param-name>
<param-value>true</param-value>
</init-param>
</filter>
<filter-mapping>
<filter-name>CharacterEncodingFilter</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
<filter>
<filter-name>springSecurityFilterChain</filter-name>
<filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
</filter>
<filter-mapping>
<filter-name>springSecurityFilterChain</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
</web-app>
root-context.xml
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context.xsd">
<import resource="classpath:spring/app-context.xml"/>
<import resource="classpath:spring/security-context.xml"/>
</beans>

Answer 1

I didn't add in pom.xml taglib dependency