I have a following line as input.
Parsing events:hostname='tom';Ipaddress='10.10.10.1';situation_name='sgd_abc_app_a';type='General';
Like this there are many fields in a line separated by a delimiter as semi-colon. (But starting with Parsing Events:)
I want to extract onlysgd_abc_app_a when it matches situation_name.
Thanks
Kulli
Try
sed -n 's/^.*situation_name=//p' input_file| awk -F "'" '{print $2}'
For your request, it would work no matter the position of situation_name
$ awk '/situation_name/{match($0,/situation_name=[^;]+/); print substr($0,RSTART+16,RLENGTH-17)}' file
sgd_abc_app_a
awk solution:
s="Parsing events: hostname='tom';Ipaddress='10.10.10.1';situation_name='sgd_abc_app_a';type='General';"
awk -F'[=;]' '{ gsub("\047","",$6); print $6 }' <<< $s
Or with sed:
sed -n "s/^Parsing events:.*situation_name='\([^']*\).*/\1/p" <<< $s
The output:
sgd_abc_app_a
Related
From the cmd (awk 'some expression') I got a result in the format
Key:(white_space)Value
Key:(white_space)Value
...
How to manipulate the result to be in the format:
Key=Value
I need this because I want to put the information into .properties file format which is key=value
In other words I need to replace : with = and remove the whitespace.
Is there a command in awk that can achieve this ?
You ask for awk, while sed provides just as easy a solution. However, awk makes it trivial with sub as well:
awk '{ sub(/:[ \t]*/,"=") }1'
Example
$ echo "Key: Value" | awk '{ sub(/:[ \t]*/,"=") }1'
Key=Value
Another awk approach.
awk -F'[: ]' '{print $1 "=" $NF}' file.txt
I have a string like X1.7_RC02.20170811110948 and I need to increase only the number between RC and the next point, example:
Original string:
X1.7_RC02.20170811110948
Incremented string:
X1.7_RC03.20170811110948
How can I increase in 1 (or more this value)?
with GNU awk for the 3rd arg to match():
$ awk 'match($0,/(.*RC)([^.]+)(.*)/,a){$0=sprintf("%s%02d%s",a[1],a[2]+1,a[3])} 1' file
X1.7_RC03.20170811110948
With GNU sed
sed -r 's/(.*)(RC0?)([1-9]+)(\..*)/echo "\1\2$((\3+1))\4"/e' <<<X1.7_RC02.20170811110948
Considering your data is same as shown example then try with following awk once too and let me know if this helps you.
awk '{val=$0;gsub(/.*RC|\..*/,"",val);val=sprintf("%02d",++val);sub(/RC[0-2]+/,"RC"val);print}' Input_file
Or if you have a string then you could print it's value and could run above command like:
echo "$var" | awk '{val=$0;gsub(/.*RC|\..*/,"",val);val=sprintf("%02d",++val);sub(/RC[0-2]+/,"RC"val);print}'
awk solution:
Initial string:
s="X1.7_RC02.20170811110948"
awk 'BEGIN{ FS=OFS="_RC"}{ n=substr($2,1,2); print $1,sprintf("%02.f",n+1) substr($2,3)}' <<< $s
The output:
X1.7_RC03.20170811110948
I have the following line. I can grep one part but struggling with also grepping the second portion.
Line:
html:<TR><TD>PICK_1</TD><TD>36.0000</TD><TD>1000000</TD><TD>26965</TD><TD>100000000</TD><TD>97074000</TD><TD>2926000</TD><TD>2.926%</TD><TD>97.074%</TD></TR>
I want to have the following results after grepping this line.
PICK_1 97.074%
Currently just grepping first portion via following command.
grep -Po "<TR><TD>[A-Z0-9_]+" test.txt
Appreciate any help on how I can go about doing this. Thanks.
Use awk with a custom field separator:
awk -F'[<>TDR/]+' '{ print $2, $(NF-1) }' file
This splits the line on things that look like one or more opening or closing <TD> or <TR> tags, and prints the second and second-last field.
Warning: this will break on almost every input except the one that you've shown, since awk, grep and friends are designed for processing text, not HTML.
If you always have the same number of fields delimited by "TD" tags, you can try with this (dirty) awk:
awk -F'[<TD>|</TD>]' '{print $8 " " $80}'
Or this combination of column and awk:
column -t -s "</TD>" | awk -F' ' '{print $3 " " $11}'
Or with sed instead of column:
sed -e 's/<TD>/ /g' | awk -F' ' '{print $3 " " $11}'
try provide each patter after "-e" option
grep -e PICK_1 -e "<TR><TD>[A-Z0-9_]+" test.txt
awk -F'[<>]' '{print $5,$(NF-4)}' file
PICK_1 97.074%
I am scripting an awk statement and I want to insert quotations around the column of text (one at the beginning and 1 at the end of first column)
Example
before
https://otrs.com/ID=24670 2014060910001178
after
"https://otrs.com/ID=24670" 2014060910001178
so far I have
awk '{ print $2"\""$2"\""$0 }'F1 request.txt > request1.txt
but that prints a repeat of the second value and I just want the quotes to go around the first column.
Thanks for your help
Through sed,
$ echo 'https://otrs.com/ID=24670 2014060910001178' | sed 's/^\([^ ]*\)\(.*\)$/"\1"\2/g'
"https://otrs.com/ID=24670" 2014060910001178
Through awk,
$ echo 'https://otrs.com/ID=24670 2014060910001178' | awk '{gsub(/^/,"\"",$1);gsub(/$/,"\"",$1);}1'
"https://otrs.com/ID=24670" 2014060910001178
Another for awk:
awk '{ $1 = "\"" $1 "\"" }1' request.txt > request1.txt
I have a line like:
one:two:three:four:five:six seven:eight
and I want to use awk to get $1 to be one and $2 to be two:three:four:five:six seven:eight
I know I can get it by doing sed before. That is to change the first occurrence of : with sed then awk it using the new delimiter.
However replacing the delimiter with a new one would not help me since I can not guarantee that the new delimiter will not already be somewhere in the text.
I want to know if there is an option to get awk to behave this way
So something like:
awk -F: '{print $1,$2}'
will print:
one two:three:four:five:six seven:eight
I will also want to do some manipulations on $1 and $2 so I don't want just to substitute the first occurrence of :.
Without any substitutions
echo "one:two:three:four:five" | awk -F: '{ st = index($0,":");print $1 " " substr($0,st+1)}'
The index command finds the first occurance of the ":" in the whole string, so in this case the variable st would be set to 4. I then use substr function to grab all the rest of the string from starting from position st+1, if no end number supplied it'll go to the end of the string. The output being
one two:three:four:five
If you want to do further processing you could always set the string to a variable for further processing.
rem = substr($0,st+1)
Note this was tested on Solaris AWK but I can't see any reason why this shouldn't work on other flavours.
Some like this?
echo "one:two:three:four:five:six" | awk '{sub(/:/," ")}1'
one two:three:four:five:six
This replaces the first : to space.
You can then later get it into $1, $2
echo "one:two:three:four:five:six" | awk '{sub(/:/," ")}1' | awk '{print $1,$2}'
one two:three:four:five:six
Or in same awk, so even with substitution, you get $1 and $2 the way you like
echo "one:two:three:four:five:six" | awk '{sub(/:/," ");$1=$1;print $1,$2}'
one two:three:four:five:six
EDIT:
Using a different separator you can get first one as filed $1 and rest in $2 like this:
echo "one:two:three:four:five:six seven:eight" | awk -F\| '{sub(/:/,"|");$1=$1;print "$1="$1 "\n$2="$2}'
$1=one
$2=two:three:four:five:six seven:eight
Unique separator
echo "one:two:three:four:five:six seven:eight" | awk -F"#;#." '{sub(/:/,"#;#.");$1=$1;print "$1="$1 "\n$2="$2}'
$1=one
$2=two:three:four:five:six seven:eight
The closest you can get with is with GNU awk's FPAT:
$ awk '{print $1}' FPAT='(^[^:]+)|(:.*)' file
one
$ awk '{print $2}' FPAT='(^[^:]+)|(:.*)' file
:two:three:four:five:six seven:eight
But $2 will include the leading delimiter but you could use substr to fix that:
$ awk '{print substr($2,2)}' FPAT='(^[^:]+)|(:.*)' file
two:three:four:five:six seven:eight
So putting it all together:
$ awk '{print $1, substr($2,2)}' FPAT='(^[^:]+)|(:.*)' file
one two:three:four:five:six seven:eight
Storing the results of the substr back in $2 will allow further processing on $2 without the leading delimiter:
$ awk '{$2=substr($2,2); print $1,$2}' FPAT='(^[^:]+)|(:.*)' file
one two:three:four:five:six seven:eight
A solution that should work with mawk 1.3.3:
awk '{n=index($0,":");s=$0;$1=substr(s,1,n-1);$2=substr(s,n+1);print $1}' FS='\0'
one
awk '{n=index($0,":");s=$0;$1=substr(s,1,n-1);$2=substr(s,n+1);print $2}' FS='\0'
two:three:four five:six:seven
awk '{n=index($0,":");s=$0;$1=substr(s,1,n-1);$2=substr(s,n+1);print $1,$2}' FS='\0'
one two:three:four five:six:seven
Just throwing this on here as a solution I came up with where I wanted to split the first two columns on : but keep the rest of the line intact.
Comments inline.
echo "a:b:c:d::e" | \
awk '{
split($0,f,":"); # split $0 into array of fields `f`
sub(/^([^:]+:){2}/,"",$0); # remove first two "fields" from `$0`
print f[1],f[2],$0 # print first two elements of `f` and edited `$0`
}'
Returns:
a b c:d::e
In my input I didn't have to worry about the first two fields containing escaped :, if that was a requirement, this solution wouldn't work as expected.
Amended to match the original requirements:
echo "a:b:c:d::e" | \
awk '{
split($0,f,":");
sub(/^([^:]+:)/,"",$0);
print f[1],$0
}'
Returns:
a b:c:d::e