springboot exceptionhandling without controller class - spring-boot

How to handle exception handling in Spring Boot 1.5.4 without controller class? Currently, I have only entity & repository class as below.
Task.class: (entity)
#Entity
#Table(name = "task")
public class Task implements Serializable {
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
#Column(name = "id")
private long id;
#Length(min = 1)
private String name;
public Task() {
}
public Task(String name) {
this.name = name;
}
public Task(Long id, String name) {
this.name = name;
}
public long getId() {
return id;
}
public String getName(){
return name;
}
}
Repository.class:
public interface TaskRepository extends PagingAndSortingRepository<Task, Long> {
}
POST method: return 200 ok
http://localhost:8080/tasks
{
"name" : "test"
}
But,
{
"name" : ""
}
returns 500 , instead of 400 error.
Pls let me know, if any way to handle this exception without a controller class.

You could use a global #ExceptionHandler with the #ControllerAdvice annotation. Basically, you define which Exception to handle with #ExceptionHandler within the class with #ControllerAdvice annotation, and then you implement what you want to do when that exception is thrown.
Like this:
#ControllerAdvice(basePackageClasses = RepositoryRestExceptionHandler.class)
public class GlobalExceptionHandler {
#ExceptionHandler({ValidationException.class, JsonParseException.class})
public ResponseEntity<Map<String, String>> yourExceptionHandler(Exception e) {
Map<String, String> response = new HashMap<String, String>();
response.put("message", "Bad Request");
return new ResponseEntity<Map<String, String>>(response, HttpStatus.BAD_REQUEST);
}
}
See also: http://www.ekiras.com/2016/02/how-to-do-exception-handling-in-springboot-rest-application.html

Related

Error locating String field in Spring Boot

I'm trying to find a company by its CNPJ(Brazilian corporate tax payer registry number) in a DB (H2), but it's returning an error
{
"timestamp": "2022-03-30T19:30:23.823+00:00",
"status": 404,
"error": "Not Found",
"path": "/companies/cnpj/30101554000146"
}
I've tried other alternatives using:
http://localhost:8080/companies/cnpj/'30.101.554/0001-46', http://localhost:8080/companies/cnpj/"30.101.554/0001-46",
but the error persists. I implemented like this :
#Entity
#Table(name = "company")
public class Company implements Serializable {
private static final long serialVersionUID = 1L;
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private Long id;
private String name;
#CNPJ
private String cnpj;
//skipped
}
public interface CompanyRepository extends JpaRepository<Company,Long> {
Optional<Company> findByCnpj(String cnpj);
}
public class CompanyDTO {
private Long id;
private String name;
private String cnpj;
//skipped
}
#Service
#Transactionalpublic class CompanyService {
#Autowired
private CompanyRepository companyRepository;
#Transactional(readOnly = true)
public CompanyDTO findById(Long id) {
Company resultado = companyRepository.findById(id).get();
CompanyDTO dto = new CompanyDTO(resultado);
return dto;
}
#Transactional(readOnly = true)
public CompanyDTO findByCnpj(String cnpf) {
Optional<Company> resultado = companyRepository.findByCnpj(cnpf);
CompanyDTO dto = new CompanyDTO(resultado.get());
return dto;
}
}
#RestController
#RequestMapping(value = "/companies")public class CompanyController {
#Autowired
private CompanyService companyService;
#GetMapping(value = "/{id}")
public CompanyDTO findById(#PathVariable Long id) {
return companyService.findById(id);
}
#GetMapping(value = "/cnpj/{cnpj}")
public CompanyDTO findByCnpj(#PathVariable String cnpj) {
return companyService.findByCnpj(cnpj);
}
}
The expected output would be:
[
{"id": 1,
"nome": "Company 123",
"cnpj": "30.101.554/0001-46"
}
]
UPDATE:
I changed #GetMapping(value = "/cnpj/{cnpj}") to #GetMapping(value = "/cnpj/**") and:
#GetMapping(value = "/cnpj/**")
public CompanyDTO findByCnpj(HttpServletRequest request) {
return companyService.findByCnpj(request.getRequestURI().split(request.getContextPath() + "/cnpj/")[1]);
}
Works for me! Thanks
As explained here, pathParams with slashes can be realy tricky while using spring-boot. This article explains pretty well what to do to avoid getting an error 404 when your pathVariable has a slash.

Spring boot application I can not get data from oracle database it returns [] in postman

Spring boot application I can not get data from oracle database it returns []. In postman, it returns other requests e.g home method in controller class returns correctly. also, the table created by model class the problem is getting data from the table.
Here is the postman result:
I get this in console:
Model class
#Entity // This tells Hibernate to make a table out of this class
public class Userr {
#Id
#GeneratedValue(strategy=GenerationType.AUTO)
private Integer id;
private String name;
private String email;
public Integer getId() {
return id;
}
public void setId(Integer id) {
this.id = id;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public String getEmail() {
return email;
}
public void setEmail(String email) {
this.email = email;
}
}
//Controller Class
#RestController
public class MainController {
#Autowired // This means to get the bean called userRepository
// Which is auto-generated by Spring, we will use it to handle the data
private UserRepository userRepository;
#PostMapping(path="/add") // Map ONLY POST Requests
public #ResponseBody String addNewUser (#RequestParam String name
, #RequestParam String email) {
// #ResponseBody means the returned String is the response, not a view name
// #RequestParam means it is a parameter from the GET or POST request
Userr n = new Userr();
n.setName(name);
n.setEmail(email);
userRepository.save(n);
return "Saved";
}
#GetMapping(path="/all")
public #ResponseBody Iterable<Userr> getAllUsers() {
// This returns a JSON or XML with the users
//
return userRepository.findAll();
}
#GetMapping(path="/al")
public List<Userr> printPersonInfo() {
List<Userr> list = new ArrayList<>();
userRepository.findAll().forEach(list::add);
return list;
}
#RequestMapping("/user")
public String home(){
return "PPPPPP";
}
}
//Repository Class
public interface UserRepository extends CrudRepository<Userr, Integer> {
}
Add #Repository annotation to your UserRepository. It will help with your issue.

Error creating bean with name 'clienteRestController': Unsatisfied dependency expressed through field 'clientService';

Error creating bean with name 'clienteRestController': Unsatisfied dependency expressed through field 'clientService'.
Error creating bean with name 'clientServiceImpl': Unsatisfied dependency expressed through field 'clientDao'.
Error creating bean with name 'IClienteDao': Invocation of init method failed.
nested exception is java.lang.IllegalArgumentException: Not a managed type: class java.lang.Package
I am use eclipse with spring boot project with MySQL Database, when i run the project i see this error, i see some solves in stack Overflow but not worked , can any body help, thanks
#Entity
#Table(name = "package")
public class Package implements Serializable{
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private Long id;
private String name;
private int count;
#Column(precision=18, scale=2) /** Number (16, 2) **/
private double price;
#Column(name = "createAt")
#Temporal(TemporalType.TIMESTAMP)
private Date createAt;
public Long getId() {
return id;
}
public void setId(Long id) {
this.id = id;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public int getCount() {
return count;
}
public void setCount(int count) {
this.count = count;
}
public double getPrice() {
return price;
}
public void setPrice(double price) {
this.price = price;
}
public Date getCreateAt() {
return createAt;
}
public void setCreateAt(Date createAt) {
this.createAt = createAt;
}
private static final long serialVersionUID = 1L;
}
Controller "ClienteRestController":
#CrossOrigin(origins = {"http://localhost:4200"})
#RestController
#RequestMapping("/apiHorsesClub")
public class ClienteRestController {
#Autowired
private IClienteService clientService;
#GetMapping("clients")
public List<Package> index()
{
return clientService.findAll();
}
}
DAO layer "clientDao":
public interface IClienteDao extends CrudRepository<Package, Long>{
}
Service layer "IClienteService" :
public interface IClienteService {
public List<Package> findAll();
}
implementation the service "ClientServiceImpl " :
#Service
public class ClientServiceImpl implements IClienteService {
#Autowired
private IClienteDao clientDao;
#Override
#Transactional(readOnly = true)
public List<Package> findAll() {
return (List<Package>) clientDao.findAll();
}
}
Thanks all, i resolved the problem.
the problem in name of the entity "Package", its reserved in Java 😂

Why is the child collection is null in One-To-Many relationship of spring boot application?

I create a spring boot application with MySQL,JPA,Web dependencies,and manually config my database settings in .properties file of Spring boot. I passed compiling, and started application successfully, and adding one record is normal fine.
BUT, i use method 'findAll(Pageable pageable)' i got a problem, that was
Could not write JSON: failed to lazily initialize a collection of role,could not initialize proxy - no Session
I got confused, i started to debug my code, finally i found that the child collection of the result is null, and it contained an error, which is
"Exception occurred: com.sun.jdi.InvocationException occurred invoking method.."
I tried a lot to fix my code, but no use.
who can help me?
The entity relationship is a simple one to many:
TeacherInfo entity and ClassInfo entity, teacher manage multiple classes, just simple as this.
here is the enter point of my app:
#SpringBootApplication(exclude= {
DataSourceAutoConfiguration.class,
HibernateJpaAutoConfiguration.class,
DataSourceAutoConfiguration.class
})
#EnableTransactionManagement
public class OrmTestApplication {
public static void main(String[] args) {
SpringApplication.run(OrmTestApplication.class, args);
}
}
Database properties setting is here:
spring.datasource.primary.url=jdbc:mysql://localhost:3306/ormtest?useSSL=false
spring.datasource.primary.username=root
spring.datasource.primary.password=BlaNok2700
spring.datasource.primary.driver-class-name = com.mysql.jdbc.Driver
hibernate.hbm2ddl.auto = update
hibernate.show-sql = true
My Data base configure java code is here:
Configuration
#EnableJpaRepositories(basePackages = "com.lanjian.ormtest.repositories", entityManagerFactoryRef = "primaryEntityManagerFactory", transactionManagerRef = "primaryTransactionManager")
public class PrimaryDbConfig {
#Autowired
private Environment env;
#Bean
#ConfigurationProperties(prefix="spring.datasource.primary")
public DataSourceProperties primaryDataSourceProperties() {
return new DataSourceProperties();
}
#Bean
public DataSource primaryDataSource() {
DataSourceProperties dbProperty = primaryDataSourceProperties();
return DataSourceBuilder.create()
.driverClassName(dbProperty.getDriverClassName())
.url(dbProperty.getUrl())
.username(dbProperty.getUsername())
.password(dbProperty.getPassword())
.build();
}
#Bean
public LocalContainerEntityManagerFactoryBean primaryEntityManagerFactory() {
LocalContainerEntityManagerFactoryBean factory = new LocalContainerEntityManagerFactoryBean();
factory.setDataSource(primaryDataSource());
factory.setPackagesToScan("com.lanjian.ormtest.entities");
factory.setJpaVendorAdapter(new HibernateJpaVendorAdapter());
Properties jpaProperties = new Properties();
jpaProperties.put("hibernate.hbm2ddl.auto", env.getProperty("hibernate.hbm2ddl.auto"));
jpaProperties.put("hibernate.show-sql", env.getProperty("hibernate.show-sql"));
factory.setJpaProperties(jpaProperties);
return factory;
}
#Bean
public PlatformTransactionManager primaryTransactionManager() {
EntityManagerFactory factory = primaryEntityManagerFactory().getObject();
return new JpaTransactionManager(factory);
}
}
My REST controller method is here:
#Autowired
private TeacherRepository teacherRepository;
#GetMapping("/page")
public Page<TeacherInfo> page(Pageable pageable){
Page<TeacherInfo> list = teacherRepository.findAll(pageable);
return list;
}
What happened
After i started my application, and use postman send request, i got this:
got a 500 error
And i debugger my code, found this:
child collection is null
In the picture, 'classes' is a list collection, but it is null, i don't understand.
Here are the TeacherInfo entity I defined
#Entity
#Table(name = "teacher")
public class TeacherInfo {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private Long id;
private String name;
private byte age;
private boolean male;
#OneToMany(cascade = CascadeType.ALL,fetch = FetchType.LAZY, mappedBy="chargedTeacher")
private List<ClassInfo> classes = new ArrayList<>();
public void initialize() {
for (ClassInfo classInfo : classes) {
classInfo.setChargedTeacher(this);
for (StudentInfo studentInfo : classInfo.getStudents()) {
studentInfo.setClassInfo(classInfo);
}
}
}
//Setters and Getters}
Here is the ClassInfo Entity i defined
#Entity
#Table(name = "class_info")
public class ClassInfo {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private Long id;
private String name;
private int capacity;
#ManyToOne(fetch = FetchType.LAZY)
#JoinColumn(name = "teacher_id",nullable=false)
#JsonIgnore
private TeacherInfo chargedTeacher;
#OneToMany(cascade = CascadeType.ALL,fetch=FetchType.LAZY,mappedBy="classInfo")
private List<StudentInfo> students = new ArrayList<>();
public Long getId() {
return id;
}
public void setId(Long id) {
this.id = id;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public int getCapacity() {
return capacity;
}
public void setCapacity(int capacity) {
this.capacity = capacity;
}
public TeacherInfo getChargedTeacher() {
return chargedTeacher;
}
public void setChargedTeacher(TeacherInfo chargedTeacher) {
this.chargedTeacher = chargedTeacher;
}
public List<StudentInfo> getStudents() {
return students;
}
public void setStudents(List<StudentInfo> students) {
this.students = students;
}
}
I think that the problem may come from Transactionality and JPA Fetching types.
Your repository method is being invoked not using a transaction, which implies that the transaction is on the boundaries of the method invocation (which might not be wrong). Spring returns a Page with objects but when it tries to serialize them, transaction is gone so no way to access childs.
I would suggest to put the JPA relationship as EAGER fetching, allowing all the objects to be present on the repository result when the transaction ends.
EDIT:
Answer to comments
#Bean
public PlatformTransactionManager primaryTransactionManager(EntityManagerFactory factory) {
return new JpaTransactionManager(factory);
}

LazyInitializationException Spring and Hibernate

I am getting this exception nested exception is org.hibernate.LazyInitializationException: failed to lazily initialize a collection of role: com.ibm.ro.model.Location.subLocations, could not initialize proxy - no Session.
I do get that upon accessing the collection, the transaction has already been closed that's why the code is throwing this exception. Here is my sample code
#Entity
#Table(name="location")
public class Location extends BaseEntity {
private static final long serialVersionUID = 1L;
private String name;
private List<Location> subLocations;
private Location location;
#Column(name="name")
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
#OneToMany(fetch = FetchType.LAZY, mappedBy = "location")
public List<Location> getSubLocations() {
return subLocations;
}
public void setSubLocations(List<Location> subLocations) {
this.subLocations = subLocations;
}
#ManyToOne(fetch = FetchType.LAZY)
public Location getLocation() {
return location;
}
public void setLocation(Location location) {
this.location = location;
}
#Override
public String toString() {
return "Location [name=" + name + ", subLocations=" + subLocations
+ "]";
}
}
Here is my DAO:
#Repository("locationDao")
public class LocationDao implements ILocationDao{
#Autowired
private SessionFactory sessionFactory;
#Override
public List<Location> getAll() {
Session sess = getSession();
return sess.createCriteria(Location.class).setResultTransformer(CriteriaSpecification.DISTINCT_ROOT_ENTITY).list();
}
}
Then here is my service :
#Service("locationService")
#Transactional
public class LocationService implements ILocationService{
#Autowired
ILocationDao dao;
#Override
public List<Location> getAll() {
return dao.getAll();
}
}
Here is the controller where the exception is being thrown:
#Controller
public class BaseController {
#Autowired
ILocationService service;
private static final String VIEW_INDEX = "index";
private final static org.slf4j.Logger logger = LoggerFactory.getLogger(BaseController.class);
#RequestMapping(value = "/", method = RequestMethod.GET)
public String location(ModelMap model) {
logger.debug(service.getAll().toString());
return VIEW_INDEX;
}
}
What can I do to fix the problem without using OpenSessionInViewFilter?
You can iterate your Location inside your service (where you still have your transaction) and call Hibernate.initialize on the elements, the force initialization of a persistent collection.
#Override
public List<Location> getAll() {
List<Location> locations = dao.getAll();
for (Location location : locations ) {
Hibernate.intialize(location.getSubLocations())
}
return locations;
}

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