I am working with a Makefile for conversion of documents.
To specify which document to convert, I have to give folder names in 2 make-variables:
NAME and DATE.
The directory structure is /data/$(NAME)/$(DATE)
NAME may contain numbers and characters.
DATE follows this format: YYYYMMDD_XXXXXXXX where X is a hex-char.
I want to make complete suggest the NAME and DATE variables in tcsh (mandatory use on site), because it is annoying to enter those random X-chars.
I ended up having the following to suggest me the NAME variable:
'c#{NAME}=#D:/data#' \
'C/N*/(NAME=)/'
This works as expected as long as I do unset addsuffix.
make N[TAB] » make NAME=[TAB] » make NAME=10001.1
If addsuffix is set, the cursor will be after the trailing whitespace in make NAME=.
For complete a new word starts, so it does not suggest me the directories for NAME then.
If I go to NAME= then, it also adds the trailing / to folder name, which is not needed.
Is there a way to disable this behaviour for these completions?
tcsh.org states:
addsuffix If set, filename completion adds `/' to the end of directories and a space to the end of normal files when they are matched exactly. Set by default.
Obviously I want to keep the behaviour (as set by the user) for other completion.
The [suffix] is what I want to be void.
from documentation:
complete [command [word/pattern/list[:select]/[[suffix]/] ...]]
So I end up with
complete make \
'c#NAME=#D:/data/#' \
'c#DATE=#`echo $COMMAND_LINE | sed -f /data/sandbox/sbulka/tmp/sed-tmp.sed | xargs ls`#' \
'C/N*/(NAME=)//' \
'n/NAME=/(DATE=)//'
The sed is in a file so I don't have to bother quoting. Looks like this:
s/^.*NAME=\([^ ]*\).*$/\/data\/\1/
Related
I have a script that I call with an application, I can't run it from command line. I derive the directory where the script is called and in the next variable go up 1 level where my files are stored. From there I have 3 variables with the full path and file names (with wildcard), which I will refer to as "masks".
I need to find and "do something with" (copy/write their names to a new file, whatever else) to each of these masks. The do something part isn't my obstacle as I've done this fine when I'm working with a single mask, but I would like to do it cleanly in a single loop instead of duplicating loop and just referencing each mask separately if possible.
Assume in my $FILESFOLDER directory below that I have 2 existing files, aaa0.csv & bbb0.csv, but no file matching the ccc*.csv mask.
#!/bin/bash
SCRIPTFOLDER=${0%/*}
FILESFOLDER="$(dirname "$SCRIPTFOLDER")"
ARCHIVEFOLDER="$FILESFOLDER"/archive
LOGFILE="$SCRIPTFOLDER"/log.txt
FILES1="$FILESFOLDER"/"aaa*.csv"
FILES2="$FILESFOLDER"/"bbb*.csv"
FILES3="$FILESFOLDER"/"ccc*.csv"
ALLFILES="$FILES1
$FILES2
$FILES3"
#here as an example I would like to do a loop through $ALLFILES and copy anything that matches to $ARCHIVEFOLDER.
for f in $ALLFILES; do
cp -v "$f" "$ARCHIVEFOLDER" > "$LOGFILE"
done
echo "$ALLFILES" >> "$LOGFILE"
The thing that really spins my head is when I run something like this (I haven't done it with the copy command in place) that log file at the end shows:
filesfolder/aaa0.csv filesfolder/bbb0.csv filesfolder/ccc*.csv
Where I would expect echoing $ALLFILES just to show me the masks
filesfolder/aaa*.csv filesfolder/bbb*.csv filesfolder/ccc*.csv
In my "do something" area, I need to be able to use whatever method to find the files by their full path/name with the wildcard if at all possible. Sometimes my network is down for maintenance and I don't want to risk failing a change directory. I rarely work in linux (primarily SQL background) so feel free to poke holes in everything I've done wrong. Thanks in advance!
Here's a light refactoring with significantly fewer distracting variables.
#!/bin/bash
script=${0%/*}
folder="$(dirname "$script")"
archive="$folder"/archive
log="$folder"/log.txt # you would certainly want this in the folder, not $script/log.txt
shopt -s nullglob
all=()
for prefix in aaa bbb ccc; do
cp -v "$folder/$prefix"*.csv "$archive" >>"$log" # append, don't overwrite
all+=("$folder/$prefix"*.csv)
done
echo "${all[#]}" >> "$log"
The change in the loop to append the output or cp -v instead of overwrite is a bug fix; otherwise the log would only contain the output from the last loop iteration.
I would probably prefer to have the files echoed from inside the loop as well, one per line, instead of collect them all on one humongous line. Then you can remove the array all and instead simply
printf '%s\n' "$folder/$prefix"*.csv >>"$log"
shopt -s nullglob is a Bash extension (so won't work with sh) which says to discard any wildcard which doesn't match any files (the default behavior is to leave globs unexpanded if they don't match anything). If you want a different solution, perhaps see Test whether a glob has any matches in Bash
You should use lower case for your private variables so I changed that, too. Notice also how the script variable doesn't actually contain a folder name (or "directory" as we adults prefer to call it); fixing that uncovered a bug in your attempt.
If your wildcards are more complex, you might want to create an array for each pattern.
tmpspaces=(/tmp/*\ *)
homequest=($HOME/*\?*)
for file in "${tmpspaces[#]}" "${homequest[#]}"; do
: stuff with "$file", with proper quoting
done
The only robust way to handle file names which could contain shell metacharacters is to use an array variable; using string variables for file names is notoriously brittle.
Perhaps see also https://mywiki.wooledge.org/BashFAQ/020
I have the variables below in a large and important SH file and I need to remove some data from a variable and keep only part of the text.
I get "repoTest" with a link to an internal git repo and I need the variable "nameAppTest" to only receive the constant data after the last "/".
Example:
I get: repoTest="ssh://git#code.br.repo.local/code/ecsb/name-repo.git"
I try to do a split: nameAppTest=$(echo "$repoTest"|cut -d'/' -f5|sed -e 's/.git//g')
Response I get: echo "$nameAppTest" (ecsb).
What I expect to receive: name-repo
I tried like this and failed: nameAppTest=$(echo "$repoTest"|cut -d'/' -f5|sed -e 's/.git//g')
Here's a nifty trick:
nameAppTest=$(basename "$repoTest" .git)
Uses basename to get just the last component of the URL, and strip the extension all in one step.
You can also use sh parameter expansion to do it in two steps without any external programs:
# Remove everything up to and including the last /
temp="${repoTest##*/}"
# Remove the trailing .git
nameAppTest="${temp%.git}"
I have a Bash script that takes in a directory as a parameter, and after some processing will do some output based on the files in that directory.
The command would be like the following, where dir is a directory with the following structure inside
dir/foo
dir/bob
dir/haha
dir/bar
dir/sub-dir
dir/sub-dir/joe
> myscript ~/files/stuff/dir
After some processing, I'd like the output to be something like this
foo
bar
sub-dir/joe
The code I have to remove the path passed in is the following:
shopt -s extglob
for file in $files ; do
filename=${file#${1}?(/)}
This gets me to the following, but for some reason the optional / is not being taken care of. Thus, my output looks like this:
/foo
/bar
/sub-dir/joe
The reason I'm making it optional is because if the user runs the command
> myscript ~/files/stuff/dir/
I want it to still work. And, as it stands, if I run that command with the trailing slash, it outputs as desired.
So, why does my ?(/) not work? Based on everything I've read, that should be the right syntax, and I've tried a few other variations as well, all to no avail.
Thanks.
that other guy's helpful answer solves your immediate problem, but there are two things worth nothing:
enumerating filenames with an unquoted string variable (for file in $files) is ill-advised, as sjsam's helpful answer points out: it will break with filenames with embedded spaces and filenames that look like globs; as stated, storing filenames in an array is the robust choice.
there is no strict need to change global shell option shopt -s extglob: parameter expansions can be nested, so the following would work without changing shell options:
# Sample values:
file='dir/sub-dir/joe'
set -- 'dir/' # set $1; value 'dir' would have the same effect.
filename=${file#${1%/}} # -> '/sub-dir/joe'
The inner parameter expansion, ${1%/}, removes a trailing (%) / from $1, if any.
I suggested you change files to an array which is a possible workaround for non-standard filenames that may contain spaces.
files=("dir/A/B" "dir/B" "dir/C")
for filename in "${files[#]}"
do
echo ${filename##dir/} #replace dir/ with your param.
done
Output
A/B
B
C
Here's the documentation from man bash under "Parameter Expansion":
${parameter#word}
${parameter##word}
Remove matching prefix pattern. The word is
expanded to produce a pattern just as in pathname
expansion. If the pattern matches the beginning of
the value of parameter, then the result of the
expansion is the expanded value of parameter with
the shortest matching pattern (the ``#'' case) or
the longest matching pattern (the ``##'' case)
deleted.
Since # tries to delete the shortest match, it will never include any trailing optional parts.
You can just use ## instead:
filename=${file##${1}?(/)}
Depending on what your script does and how it works, you can also just rewrite it to cd to the directory to always work with paths relative to .
This may be poorly titled as I'm not fully sure what the process is called.
Basically I want to get only the last part of a symlink path, and I'm trying to use the same method I use with PWD.
For example:
if I do
PWD
it prints
/opt/ct/mydir
if I do
echo ${PWD##*/}
it prints only the last part
mydir
So using that design I can do
readlink mysymlink
which gives
/opt/ct/somedir
and I can do
TMP=$(readlink mysymlink)
echo ${TMP##*/}
and it will print
somedir
So now how can I combine that last part into one line like
TMP=$(readlink mysymlink && echo ${TMP##*/})
???
The example I show gives me 2 concatenated results.. one with the full path and one with just the part I want. I only want that last directory.
I also tried
TMP=${ $(readlink mysymlink)##*/}
to no avail
Variable substitution suffixes can only be used with variables, not command substitutions. You either have to set the variable and modify it in separate statements, as in your first attempt, or use additional command substitutions:
TMP=$(basename $(readlink))
I have to ls command to get the details of certain types of files. The file name has a specific format. The first two words followed by the date on which the file was generated
e.g.:
Report_execution_032916.pdf
Report_execution_033016.pdf
Word summary can also come in place of report.
e.g.:
Summary_execution_032916.pdf
Hence in my shell script I put these line of codes
DATE=`date +%m%d%y`
Model=Report
file=`ls ${Model}_execution_*${DATE}_*.pdf`
But the value of Model always gets resolved to 'REPORT' and hence I get:
ls: cannot access REPORT_execution_*032916_*.pdf: No such file or directory
I am stuck at how the resolution of Model is happening here.
I can't reproduce the exact code here. Hence I have changed some variable names. Initially I had used the variable name type instead of Model. But Model is the on which I use in my actual code
You've changed your script to use Model=Report and ${Model} and you've said you have typeset -u Model in your script. The -u option to the typeset command (instead of declare — they're synonyms) means "convert the strings assigned to all upper-case".
-u When the variable is assigned a value, all lower-case characters are converted to upper-case. The lower-case attribute is disabled.
That explains the upper-case REPORT in the variable expansion. You can demonstrate by writing:
Model=Report
echo "Model=[${Model}]"
It would echo Model=[REPORT] because of the typeset -u Model.
Don't use the -u option if you don't want it.
You should probably fix your glob expression too:
file=$(ls ${Model}_execution_*${DATE}*.pdf)
Using $(…) instead of backticks is generally a good idea.
And, as a general point, learn how to Debug a Bash Script and always provide an MCVE (How to create a Minimal, Complete, and Verifiable Example?) so that we can see what your problem is more easily.
Some things to look at:
type is usually a reserved word, though it won't break your script, I suggest you to change that variable name to something else.
You are missing an $ before {DATE}, and you have an extra _ after it. If the date is the last part of the name, then there's no point in having an * at the end either. The file definition should be:
file=`ls ${type}_execution_*${DATE}.pdf`
Try debugging your code by parts: instead of doing an ls, do an echo of each variable, see what comes out, and trace the problem back to its origin.
As #DevSolar pointed out you may have problems parsing the output of ls.
As a workaround
ls | grep `date +%m%d%y` | grep "_execution_" | grep -E 'Report|Summary'
filters the ls output afterwards.
touch 'Summary_execution_032916.pdf'
DATE=`date +%m%d%y`
Model=Summary
file=`ls ${Model}_execution_*${DATE}*.pdf`
worked just fine on
GNU bash, version 4.3.11(1)-release (x86_64-pc-linux-gnu)
Part of question:
But the value of Model always gets resolved to 'REPORT' and hence I get:
This is due to the fact that in your script you have exported Model=Report
Part of question:
ls: cannot access REPORT_execution_*032916_*.pdf: No such file or directory
No such file our directory issue is due to the additional "_" and additional "*"s that you have put in your 3rd line.
Remove it and the error will be gone. Though, Model will still resolve to Report
Original 3rd line :
file=`ls ${Model}_execution_*${DATE}_*.pdf`
Change it to
file=`ls ${Model}_execution_${DATE}.pdf`
Above change will resolve the could not found issue.
Part of question
I am stuck at how the resolution of Model is happening here.
I am not sure what you are trying to achieve, but if you are trying to populate the file parameter with file name with anything_exection_someDate.pdf, then you can write your script as
DATE=`date +%m%d%y`
file=`ls *_execution_${DATE}.pdf`
If you echo the value of file you will get
Report_execution_032916.pdf Summary_execution_032916.pdf
as the answer
There were some other scripts which were invoked before the control reaches the line of codes which I mentioned in the question. In one such script there is a code
typeset -u Model
This sets the value of the variable model always to uppercase which was the reason this error was thrown
ls: cannot access REPORT_execution_032916_.pdf: No such file or directory
I am sorry that
i couldn't provide a minimal,complete and verifiable code