String match and do the condition - bash

When I try to match a string and do some conditions; it always fails to do so.
date=`date +%Y%m%d`
kol="/home/user/test_$date"
regex='Terminating the script'
if [ -f $kol ]; then
sudo tail -f $kol | while read line; do
if [[ $line = *"Terminating the"* ]]
then
echo "failed"
else
echo $line >> /home/user/test123_$date
fi
else
echo "File is not yet present"
exit 0
fi
I have also tried with regex and that to failed. So when ever I input the matching string into the file ($path) it wont output "failed"; Is there anything wrong in the code. Help is much appreciated.

You can try this. At least it works for me:
sudo tail -f $1 | while read line; do
if [[ $line = '' ]]
then
break
fi
if [[ $line = *"Terminating the"* ]]
then
echo "failed"
else
echo $line >> /home/nurzhan/test123_$date
fi
done < "$1"
$path is parameter to the running script. Also note that by default the command tail returns only 10 last lines.

Related

Bash sed command gives me "invalid command code ."

I'm trying to automate a build process by replacing .js chunks for particular lines in my main.config.php file. When I run the following code:
declare -a js_strings=("footer." "footerJQuery." "headerCSS." "headerJQuery.")
build_path="./build/build"
config_path="./system/Config/main.config.php"
while read -r line;
do
for js_string in ${js_strings[#]}
do
if [[ $line == *$js_string* ]]
then
for js_file in "$build_path"/*
do
result="${js_file//[^.]}"
if [[ $js_file == *$js_string* ]] && [[ ${#result} -eq 3 ]]
then
sed -i "s/$line/$line$(basename $js_file)\";/g" $config_path
fi
done
fi
done
done < "$config_path"
I get this message back, and file has not been updated/edited:
sed: 1: "./system/Config/main.co ...": invalid command code .
I haven't been able to find anything in my searches that pertain to this specific message. Does anyone know what I need to change/try to get the specific lines replaced in my .php file?
Updated script with same message:
declare -a js_strings=("footer." "footerJQuery." "headerCSS." "headerJQuery.")
build_path="./build/build"
config_path="./system/Config/main.config.php"
while read -r line;
do
for js_string in ${js_strings[#]}
do
if [[ $line == *$js_string* ]]
then
for js_file in "$build_path"/*
do
result="${js_file//[^.]}"
if [[ $js_file == *$js_string* ]] && [[ ${#result} -eq 3 ]]
then
filename=$(basename $js_file)
newline="${line//$js_string*/$filename\";}"
echo $line
echo $newline
sed -i "s\\$line\\$newline\\g" $config_path
echo ""
fi
done
fi
done
done < "$config_path"
Example $line:
$config['public_build_header_css_url'] = "http://localhost:8080/build/headerCSS.js";
Example $newline:
$config['public_build_header_css_url'] = "http://localhost:8080/build/headerCSS.7529a73071877d127676.js";
Updated script with changes suggested by #Vercingatorix:
declare -a js_strings=("footer." "footerJQuery." "headerCSS." "headerJQuery.")
build_path="./build/build"
config_path="./system/Config/main.config.php"
while read -r line;
do
for js_string in ${js_strings[#]}
do
if [[ $line == *$js_string* ]]
then
for js_file in "$build_path"/*
do
result="${js_file//[^.]}"
if [[ $js_file == *$js_string* ]] && [[ ${#result} -eq 3 ]]
then
filename=$(basename $js_file)
newline="${line//$js_string*/$filename\";}"
echo $line
echo $newline
linenum=$(grep -n "^${line}\$" ${config_path} | cut -d':' -f 1 )
echo $linenum
[[ -n "${linenum}" ]] && sed -i "${linenum}a\\
${newline}
;${linenum}d" ${config_path}
echo ""
fi
done
fi
done
done < "$config_path"
Using sed's s command to replace a line of that complexity is a losing proposition, because whatever delimiter you choose may appear in the line and mess things up. If these are in fact entire lines, it is better to delete them and insert a new one:
linenum=$(fgrep -nx -f "${line}" "${config_path}" | awk -F : "{print \$1}" )
[[ -n "${linenum}" ]] && sed -i "" "${linenum}a\\
${newline}
;${linenum}d" "${config_path}"
What this does is search for the line number of the line that matches $line in its entirety, then extracts the line number portion. fgrep is necessary otherwise the symbols in your file are interpreted as regular expressions. If there was a match, then it runs sed, appending the new line (a) and deleting the old one (d).

Catch the search value into the variable in unix shell script

I am trying to search content of file 1 into file 2 and if the content is found then store in found.csv file or store in notfound.csv file
Below is my code,
cd /mnt/data/dobiminer/scripts
usage="Usage:sh scriptname.sh 'ToSearchFile' 'MainSearchFile' 'CR' "
Date=`date +%m%d%y%H%M%S`
File=$(<$2)
echo "File Input $2"
echo $File
if [ $# != 3 ]
then
echo $usage
exit 1
else
echo > "$3-Found-$Date.csv"
echo > "$3-NotFound-$Date.csv"
for MasterClip in `cat $1`
do
echo $MasterClip
String=$(echo "$File" | grep -x $MasterClip)
echo $String
if [ -z $String ];
then
echo "NotFound"
echo $MasterClip >> "$3-NotFound-$Date.csv"
else
echo "Found"
echo $MasterClip >> "$3-Found-$Date.csv"
fi
done
fi
My guess is that the below line of code is not working, as whenever I am running the code, the string value is empty only. It is not catching the search value into it.
String=$(echo "$File" | grep -x $MasterClip)
echo $String
I tried multiple things but not sure where I am going wrong.
THanks for helping me out

[[Bash]] Search for combined Expressions in every row

I am very new to Bash Scripting and I have a question regarding my CheckOurCodingRules.sh script:
I want to search for every 'hPar,' in a textfile and if found it should be checked if there is a also a 'const' in the same row.
Thats what I got so far but there is something wrong here:
while read line
do
if [[ $line == *hPar\,* ]] && [[ $line == *const\*]];then
DOCUMENTATION_TEST_A=1
else
echo DOCUMENTATION_TEST_A=0
fi
done < $INPUT_FILE
if [[DOCUMENTATION_TEST_A=0]];then
echo "error: Rule1: No const before hpar"
fi
There are a couple of issues with your script, see the code below which works for me:
DOCUMENTATION_TEST_A=0 # initial value
while read line
do
# spaces between conditional and brackets, no backslashes
if [[ $line == *hPar,* ]] && [[ $line == *const* ]]
then
DOCUMENTATION_TEST_A=1
break # optional, no need to scan the rest of the file
fi
done < $INPUT_FILE
# spaces and $, -eq is used for numerical comparisons
if [[ $DOCUMENTATION_TEST_A -eq 0 ]];
then
echo "error: Rule1: No const before hpar"
fi
A cleaner solution would be to use grep:
if ! grep "hPar," $INPUT_FILE | grep "const" >/dev/null
then
echo "error: Rule1: No const before hpar"
fi

Bash while loop if statment

Can anyone see whats wrong here? If I put X|9 in lan.db (or any db in this directory) and run the following code, the IF statement does not work. It's weird! if you echo $LINE, it is indeed pulling X|9 out of lan.db (or any db in this directory) and setting it equal to LINE, but it wont do the comparison.
DBREGEX="^[0-9]|[0-9]$"
shopt -s nullglob
DBARRAY=(databases/*)
i=0
for i in "${!DBARRAY[#]}"; do
cat ${DBARRAY[$i]} | grep -v \# | while read LINE; do
echo "$LINE" (Whats weird is that LINE DOES contain X|9)
if [[ !( $LINE =~ $DBREGEX ) ]]; then echo "FAIL"; fi
done
done
If however I just manually sent LINE="X|9" the same code (minus the while) works fine. ie LINE=X|9 fails, but LINE=9|9 succeeds.
DBREGEX="^[0-9]|[0-9]$"
Comment shopt -s nullglob
Comment DBARRAY=(databases/*)
Comment i=0
Comment for i in "${!DBARRAY[#]}"; do
Comment cat ${DBARRAY[$i]} | grep -v \# | while read LINE; do
LINE="X|9"
if [[ !( $LINE =~ $DBREGEX ) ]]; then echo "FAIL"; fi
Comment done
Comment done
* UPDATE *
UGH I GIVE UP
Now not even this is working...
DBREGEX="^[0-9]|[0-9]$"
LINE="X|9"
if [[ ! $LINE =~ $DBREGEX ]]; then echo "FAIL"; fi
* UPDATE *
Ok, so it looks like I have to escape |
DBREGEX="^[0-9]\|[0-9]$"
LINE="9|9"
echo "$LINE"
if [[ ! $LINE =~ $DBREGEX ]]; then echo "FAIL"; fi
This seems to work ok again
| has a special meaning in a regular expression. ^[0-9]|[0-9]$ means "starts with a digit, or ends with a digit". If you want to match a literal vertical bar, backslash it:
DBREGEX='^[0-9]\|[0-9]$'
for LINE in 'X|9' '9|9' ; do
echo "$LINE"
if [[ ! $LINE =~ $DBREGEX ]] ; then echo "FAIL" ; fi
done
You don't need round brackets in regex evaluation. You script is also creating a sub shell and making a useless use of cat which can be avoided.
Try this script instead:
while read LINE; do
echo "$LINE"
[[ "$LINE" =~ $DBREGEX ]] && echo "PASS" || echo "FAIL"
done < <(grep -v '#' databases/lan.db)

how to search for blank lines in bash

I am trying to create an if statement that performs an action when it reads a blank line.
I would assume it would be something like this : if ($line=='\n');then
where line is the line that it is reading from a text file. But this is not working.
while read line; do
if [ "$line" = "" ]; then
echo BLANK
fi
done < filename.txt
or a slight variation:
while read line; do
if [ "$line" ]; then
echo NOT BLANK
else
echo BLANK
fi
done < filename.txt
try this:
if [[ "x$line" == "x" ]]; then...
or
if [[ "$line" =~ "^$" ]]; ...
Or also:
grep -q '.' <<< $line
Returns 1 if line is empty, 0 if non-empty

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