get particular day between a data range from giving table - oracle

Question

I read many articles which introduce the using of connect by, but all of them get the particular days from a giving parameter(almost the begin date and end date)
What I want to know is how could I get split the rows from a certain table?
Example
Table T1
StartDate EndDate T_ID
2017-06-01 2017-06-15 01
2017-06-05 2017-06-06 02
The result I want is
TargetDate T_ID
2017-06-01 01
2017-06-02 01
2017-06-03 01
2017-06-04 01
2017-06-05 01
.
.
.
.
2017-06-15 01
2017-06-06 01
2017-06-06 02
I tried
SELECT T_ID, T1.StartDate+ LEVEL - 1 DD, LEVEL
FROM T1
WHERE T1.T_ID in = '01'
CONNECT BY LEVEL <= (TO_DATE(TRUNC(T1.EndDate)) - T1.StartDate + 1 ) ;
Waiting for your solution. Thanks.

Answer 1

Test Data:
CREATE TABLE t1 ( t_id, startdate, enddate ) AS
SELECT 1, DATE '2017-06-01', DATE '2017-06-15' FROM DUAL UNION ALL
SELECT 2, DATE '2017-06-05', DATE '2017-06-06' FROM DUAL;
Query:
SELECT T_ID,
COLUMN_VALUE AS dt,
ROW_NUMBER() OVER ( PARTITION BY t1.ROWID
ORDER BY Column_value ) AS lvl
FROM T1
CROSS JOIN
TABLE(
CAST(
MUTLTSET(
SELECT t1.Startdate + LEVEL - 1
FROM DUAL
CONNECT BY t1.Startdate + LEVEL - 1 <= t1.EndDate
) AS SYS.ODCIDATELIST
)
);
Output:
T_ID DT LVL
---- ---------- ---
1 2017-06-01 1
1 2017-06-02 2
1 2017-06-03 3
1 2017-06-04 4
1 2017-06-05 5
1 2017-06-06 6
1 2017-06-07 7
1 2017-06-08 8
1 2017-06-09 9
1 2017-06-10 10
1 2017-06-11 11
1 2017-06-12 12
1 2017-06-13 13
1 2017-06-14 14
1 2017-06-15 15
2 2017-06-05 1
2 2017-06-06 2

Answer 2

Here is the query in standard SQL (with a recursive cte) which also works in Oracle:
with all_dates(targetdate, t_id, enddate) as
(
select startdate as targetdate, t_id, enddate from t1
union all
select targetdate + 1, t_id, enddate from all_dates where targetdate < enddate
)
select targetdate, t_id
from all_dates
order by t_id, targetdate;

Answer 3

SELECT DISTINCT T_ID
, T1.StartDate+ LEVEL - 1 DD
, LEVEL
FROM T1
WHERE T1.T_ID IN( 1,2)
CONNECT BY LEVEL <= T1.EndDate - T1.StartDate + 1
But I'm not sure about performances (At moment I didn't find a way to limit without DISTINCT but using CONNECT BY clauses).
As an alternative you can use a CTE like this (you can remove RN column, I left it as a check):
with all_dates(targetdate, t_id, enddate, RN) as
(
select startdate as targetdate, t_id, enddate, 1 AS RN from t1
union all
select T1.startdate + all_dates.RN, T1.t_id, T1.enddate, all_dates.RN+1 AS RN
from t1
inner JOIN all_dates ON T1.startdate+all_dates.RN<=all_dates.enddate
AND T1.T_ID = all_dates.T_ID
)
select targetdate, t_id , RN
from all_dates
order by t_id, targetdate;
Sample data:
CREATE TABLE T1 (StartDate DATE, EndDate DATE, T_ID NUMBER(10,0));
INSERT INTO T1 VALUES ('20170601','20170615', 1);
INSERT INTO T1 VALUES ('20170605','20170606', 2);
INSERT INTO T1 VALUES ('20170701','20170703', 3);
Output:
20170601 1 1
20170602 1 2
20170603 1 3
20170604 1 4
20170605 1 5
20170606 1 6
20170607 1 7
20170608 1 8
20170609 1 9
20170610 1 10
20170611 1 11
20170612 1 12
20170613 1 13
20170614 1 14
20170615 1 15
20170605 2 1
20170606 2 2
20170701 3 1
20170702 3 2
20170703 3 3

Answer 4

If you're wanting to use connect by to achieve this, you will need to add a couple of additional clauses in order to get it to work with multiple rows:
WITH t1 AS (SELECT to_date('01/06/2017', 'dd/mm/yyyy') startdate, to_date('15/06/2017', 'dd/mm/yyyy') enddate, 1 t_id FROM dual UNION ALL
SELECT to_date('05/06/2017', 'dd/mm/yyyy') startdate, to_date('06/06/2017', 'dd/mm/yyyy') enddate, 2 t_id FROM dual)
SELECT t_id,
startdate + LEVEL -1 dd
FROM t1
CONNECT BY LEVEL <= enddate - startdate + 1
AND PRIOR t_id = t_id
AND PRIOR sys_guid() IS NOT NULL
ORDER BY t_id, dd;
T_ID DD
---------- -----------
1 01/06/2017
1 02/06/2017
1 03/06/2017
1 04/06/2017
1 05/06/2017
1 06/06/2017
1 07/06/2017
1 08/06/2017
1 09/06/2017
1 10/06/2017
1 11/06/2017
1 12/06/2017
1 13/06/2017
1 14/06/2017
1 15/06/2017
2 05/06/2017
2 06/06/2017