Assembly: how does this algorithm know when to stop - algorithm

This is a pretty easy code, but i was wondering how this algorithm could know how to stop himself.
I mean, is there a way i can tell the program to stop when it reaches the end of the last array (forth) without using a "Branch equal to zero" in the loop section?
.data
first: .word 1,second
second: .word 2,third
third: .word 3,forth
forth: .word 4
.text
la $t1, first
lw $t2, 0($t1)
add $t4, $zero, $t2
j loop
loop:
addi $t1, $t1, 8
lw $t3, 0($t1)
add $t4, $t3, $t4
j loop
li $v0, 1
move $a0, $t4
syscall
li $v0, 10
syscall
Sorry for my bad english, and thank you :)

Related

I'm getting an error which says MIPS: line 27: Runtime exception at 0x0040003c: address out of range 0x00000000. Don't really understand why

Write a MIPS assembly language program to count the number of occurrences of the lower-case "t" in a string. After running your code, the variable count (in memory) should contain the number of "t"'s in the string.
.text
.globl main
main: la $s1, strA
la $s2, count
lbu $s4, 0($s2)
add $s3, $zero, $zero
addi $t0, $zero, 116
add $t1, $zero, $zero
loop: lbu $s3, 0($s1)
addi $s1, $s1, 1
beq $s3, $t0, eqult
beq $s3, $zero, strgend
j loop
eqult: addi $t1, $t1, 1
j loop
strgend: sb $t1, 0($s4)
nop
.data 0x10010000
strA: .asciiz "the house on the left"
count: .byte 0

Asm program... something goes wrong

I load two arrays. I have to return a third array that contain the sum of the two and has the dimension of the smaller. Print the last one.
Example:
INPUT: Array1: [1 2 3 4 5] Array2: [2 6 1]
OUTPUT: Array3: [3 8 4]
Program runs... it give me the exact number of elements but every element is 0.
.data
vett1: .word 0:100
vett2: .word 0:100
vett3: .word 0:100
x: .word 0
space: .asciiz " "
.text
.globl main
main:
la $a0, vett1
la $a1, vett2
la $a2, vett3
la $a3, x
li $t0, 0
li $t1, 0
li $t2, 0
jal loadA1 #mi salvo 26 salto a caricavettore1
jal loadA2 #mi salvo 27 salto a caricavettore2
jal lenght #mi salvo 28 salto a controllalunghezza
lw $t2, ($a3)
lw $t3, ($a3)
la $a0, vett1
la $a1, vett2
la $a2, vett3
jal summ
jal print
li $v0, 10
syscall
loadA1:
li $v0, 5
syscall
beq $v0, -1, exit
sw $v0, ($a0)
addi $t0, $t0, 1
addi $a0, $a0, 4
j loadA1
exit: jr $ra
loadA2:
li $v0, 5
syscall
beq $v0, -1, exit2
addi $t1, $t1, 1
sw $v0, ($a1)
addi $a1, $a1, 4
j loadA2
exit2: jr $ra
lenght:
blt $t0, $t1, cond1
sw $t1, ($a3)
jr $ra
cond1: sw $t0, ($a3)
jr $ra
summ:
subi $sp, $sp, 4
sw $ra, 0($sp)
bnez $t2, rec
j exit3
rec: lw $s0, ($a0)
lw $s1, ($a1)
add $v0, $s0, $s1
sw $v0, ($a2)
addi $a0, $a0, 4
addi $a1, $a1, 4
addi $a2, $a2, 4
subi $t2, $t2, 1
jal summ
exit3:
lw $ra, 0($sp)
addi $sp, $sp, 4
jr $ra
print:
beqz $t3, exit4
lw $a0, ($a2)
li $v0, 1
syscall
la $a0, space
li $v0, 4
syscall
addi $a2, $a2, 4
subi $t3, $t3, 1
j print
exit4: jr $ra
When you sum the two arrays you add 4 to $a2 at the end of each iteration to point it to the next element of vett3. So after the summing is complete $a2 will point to the first memory location after the end of vett3.
Then you call print but don't reset $a2 to point at the start of vett3, so you end up printing garbage data (which could happen to be all zeroes - or mostly zeroes at least, since x and space will be there).

MIPS Program with Integer and Argument Example

I'm stuck on an exercise, and am unsure how to proceed. This is the exercise:
Write a MIPS assembly language procedure, Test, that accepts 2 integers as arguments and
returns 0 if the integers are equal, 1 if the first is less than the second, and 2 if the first is greater
than the second.
Write a MIPS assembly language program that reads in 2 integers, calls the procedure Test, then
outputs one of the following messages:
The integers are equal
The first integer is less than the second
The first integer is greater than the second
What would be an example to carry this out? Mips is very confusing to me, as I'm used to Java. Thank you.
EDIT: Here is the program I am using as a foundation, since I am unsure where to start:
.data
str1: .asciiz "Please Enter Integer 1: " # a
str2: .asciiz "Please Enter Integer 2: " # a
str3: .asciiz "The sum is " # a
newline: .asciiz "\n" # g
.text
main: addi $v0, $zero, 4
la $a0, str1
syscall
addi $v0, $zero, 5
syscall
add $s0, $zero, $v0
addi $v0, $zero, 4
la $a0, str2
syscall
addi $v0, $zero, 5
syscall
add $s1, $zero, $v0
L1: beq $s1, $zero, cont
addi $v0, $zero, 1
add $a0, $s0, $zero
addi $s1, $s1, -1
syscall
j L1
cont: addi $v0, $zero, 4
la $a0, newline
syscall
addi $v0, $zero, 10
syscall
jr $ra
To check whether one register's value is smaller than another register's value, we can use the
set-on-less-than instruction, which also has a set-on-less-than-immediate counterpart.
slt $r0, $r3, $r4
()if r3 < r4, r0 is set to 1
else r0 is set to 0
slti $r0, $r3, 10
()if r3 < 10, r0 is set to 1
else r0 is set to 0
slt and slti are similar to beq or bne, however, there are two differences. First, they test
whether one value is smaller than another value and, second, they don't branch to some
address, but, instead, set a flag, stored in the first operand.

Mips programming jump problems

Supposed to count number of R, I, and J instructions in the code starting from the first line in main. I have updated the code to all suggestions but results do not seem correct still. :(
EDIT: added those syntax changes, the variables seem to be working better, but the loop doesn't seem to be properly running through itself at all. Any noticeable problems anyone sees?
EDIT2: How do i change the loop to make $t1 rotate through 1 instruction set at a time? THAT is my key problem right now other than the silly syntax from a new mips user.
EDIT3: I have updated the code to all suggestions but results do not seem correct still. :(
.text
Main:
la $t1, 0x400000
li $t5, 0
li $t3, 2
li $t4, 3
li $t2, 0
la $s0, 0x400000
loop:
lw $t1, 0($s0)
addi $s0, 4
addi $t5, 1
beq $t5, 20 exit
srl $s4, $t1, 26
beq $s4, $t2 R
beq $s4, $t3 J
beq $s4, $t4 J
addi $s3, 1
j loop
R:
addi $s1, 1
j loop
J:
addi $s2, 1
j loop
exit:
sw $s1, RType
sw $s2, JType
sw $s3, IType
jr $ra
I see a set of problems:
1) Initialize the registers (don't assume register initial value is zero). For example, addi $t5, 1 requieres a previous add $t5, $zero, $zero (or li to the value you want).
2) the beq jump instruction requires two registers. For example, you have to change beq $s4, 3 J by:
li $t6, 3
beq $s4, $t6, J
In addition to Miguel's points I'd like to add that you're using the instruction set in a strange manner. Perhaps your assembler is capable of figuring out what you meant, but it's still makes the code confusing to read.
lw $t3, 2
lw $t4, 3
These should be li. The lw instruction is used for loading words from memory.
la $t0, 4($t1)
This should be lw, and unless you only want to check the instructions starting from address 0x400004 you should drop the offset.
I also can't seem to find anywhere where you increment $t1, so you'll be using the same address for every iteration of the loop.

Bubble Sort in MIPS

I am trying to sort an array of integers in MIPS using bubble sort but every time that I run bubble sort I get an address out of range error. I have been staring at the code for hours and have no idea why this is happening. Hopefully' it is something really obvious that someone with more experience can see and help me fix.
The point of the program is simply to read in integers and symbols (price of stock, and stock symbol) and then sort those based on the prices. Here is the code:
.data
welcome: .asciiz "Welcome!\n"
prompt1: .asciiz "Enter how many stocks you have.\n >"
prompt2: .asciiz "Enter the four character NASDAQ abbrevation and price for each stock.\n"
prompt3p1: .asciiz "You have entered "
prompt3p2: .asciiz " stock abbreviations and prices. How many stocks do you want to buy:\n"
prompt4: .asciiz "How many stocks do you want to sell:\n"
InfoPrompt: .asciiz "Here are the symbols and the corresponding numbers that were entered: \n"
numStocks: .word 0
stockPrice: .space 40 # this will be the list of the stock prices
stockSymbol: .word 0:20 # this will be for the lit of stock abbrevs
symbols: .space 12 #this should be used for a 40 character array
inputFormat: .asciiz "\n> "
length: .word 0
buffer: .space 4
.globl main
.text
main: # display all of the propts
li $v0, 4 # get ready to print welcome
la $a0, welcome
syscall # print welcome
li $v0, 4 # not sure this is necessary since it was already loaded into v0 before
la $a0, prompt1
syscall # print("enter how many stocks you have.")
li $v0, 5 # this will get ready to accept the number of stocks
syscall # this should store the number into the $v0 register
sw $v0, numStocks # store in memory so we dont lose it
move $t0, $v0 # this will hold the num of stocks
#before we go into the procedure we need to declare and move the stack for the $t registers.
la $t1, symbols
la $t2, stockPrice
sub $sp, $sp, 8
sw $t1, 0($sp)
sw $t2, 4($sp)
jal getInfo
# now that we have all the information lets run a test to see how successful we were
# jal printInfo
li $v0, 4 #get ready to ask how many items you want to buy
la $a0, prompt3p1
syscall
li $v0, 1
lw $a0, numStocks # prints the number of stocks in the portfolio
syscall
li $v0, 4
la $a0, prompt3p2
syscall
# we need to now get the number of stocks the person wants to buy
li $v0, 4
la $a0, inputFormat
syscall #format the next input
li $v0, 5
syscall
move $t3, $v0 # the number of stocks we want to buy is now stored as $t3
#we need to get how many they want to buy
li $v0, 4
la $a0, prompt4
syscall
li $v0, 4
la $a0, inputFormat
syscall #format the next input
li $v0, 5
syscall
move $t4, $v0 # the number of stocks that you want to sell
# now we have to sort the list to figure out what elements we are going to sell and buy
la $a2, stockPrice
la $a0, stockPrice
la $a1, numStocks
jal buble_sort
jal printInfo
# end program
li $v0,10 #load the syscall number for terminating
syscall #terminate
####################################################################
# This will iterate for the number of stocks
# Only accepts the number of stocks
####################################################################
getInfo:
sub $sp, $sp, 8
sw $ra, 0($sp) # store the return value
sw $t0, 4($sp) # Save the t registers that we will be using
li $v0, 4 # set up the first call to initialize the calls for the abbreviations and numbers
la $a0, prompt2
syscall
# we want to have a place to store the symbols
la $t1, symbols
la $t2, stockPrice
GI_loop:
beq $t0, $zero, GI_loop_done # if the counter == 0 then we are done
li $v0, 4
la $a0, inputFormat
syscall #format the next input
# ask for the string input
li $v0, 8
la $a0, 0($t1)
li $a1, 6
syscall
#store the value in the array
addi $t1, $t1, 6 #increment our "array"
# ask for the integer input
li $v0, 4
la $a0, inputFormat
syscall #format the next input
li $v0, 5
syscall # get the integer value that we require
sw $v0, 0($t2) #store the value
addi $t2, $t2,4 #increment our counter
addi $t0, $t0, -1 # decrement our counter
j GI_loop
GI_loop_done:
lw $ra, 0($sp)
lw $t0, 4($sp)
lw $t1, 8($sp)
lw $t2, 12($sp)
add $sp, $sp, 8
jr $ra
####################################################################
# This will go through the lists and print out what was stored
# will go through the symbols then the numbers
####################################################################
printInfo:
sub $sp, $sp, 12
sw $ra, 0($sp)
sw $t0, 4($sp) # this will store the number of stocks that were entered
sw $t1, 8($sp)
li $v0, 4
la $a0, InfoPrompt
syscall
# we know that $t0 stores the correct number that was originally enetered so we need to loop through and print all the integers
InfoLoop:
beq $t0, $zero, InfoLoopDone # a basic counter check
#li $v0, 4
#la $a0, 0($t1)
#syscall
#addi $t1, $t1, 6
#addi $t0, $t0, -1
#j InfoLoop
################################### INTEGER PRINT WORKING
li $v0, 1 # this will print out the integers
lw $a0, 0($t2) # we have to load the world that is found in the address of $t2
syscall
addi $t2,$t2, 4 # this will increment the array
addi $t0, $t0, -1 ## this will fix our counter
j InfoLoop
InfoLoopDone:
lw $ra, 0($sp)
lw $t0, 4($sp)
add $sp, $sp, 8
jr $ra
################################
# BUBBLE SORT
################################
buble_sort:
#a0=address of table
#a1=sizeof table
add $t0,$zero,$zero #counter1( i )=0
loop1:
addi $t0,$t0,1 #i++
bgt $t0,$a1,endloop1 #if t0 > a1 break;
add $t1,$a1,$zero #counter2=size=6
loop2:
bge $t0,$t1,loop1 #j < = i
#slt $t3,$t1,$t0
#bne $t3,$zero,loop1
addi $t1,$t1,-1 #j--
mul $t4,$t1,4 #t4+a0=table[j]
addi $t3,$t4,-4 #t3+a0=table[j-1]
add $t7,$t4,$a2 #t7=table[j]
add $t8,$t3,$a2 #t8=table[j-1]
lw $t5,0($t7)
lw $t6,0($t8)
bgt $t5,$t6,loop2
#switch t5,t6
sw $t5,0($t8)
sw $t6,0($t7)
j loop2
endloop1:
jr $ra
Your problem is in the statement before calling your bubble sort routine:
la $a1, numStocks
It will load the address where the number of stocks are saved, not the number of stocks itself.
You should change it with
lw $a1, numStocks

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