for VM in $VM_LIST;do
ssh 10.0.0.163 "mkdir $ROOT$VM`date +%F`"
ssh 10.0.0.163 'find -name "$VM.vmx" | xargs grep -r vmdk >/vmkd.list | cat /vmkd.list | awk -F\" '{print $2}' | while read list; do find -name "$list" ;done'
done
I have a problem with this expression - awk -F\" '{print $2}', it broke my code
awk: cmd. line:1: Unexpected end of string
What can I do with that???
You could use here doc
for VM in $VM_LIST;do
ssh 10.0.0.163 /bin/sh <<"eocmd"
mkdir $ROOT$VM`date +%F`
find -name "$VM.vmx" |
xargs grep -r vmdk >/vmkd.list |
cat /vmkd.list |
awk -F\" '{print $2}' |
while read list; do
find -name "$list"
done
eocmd
done
Related
This is part of my script
#!/bin/bash
echo "ls /SomeFolder | grep $1 | xargs cat | grep something | grep .txt | awk '{print $2}' | sed 's/;$//';" >> script2.sh
This echos everything nicely into my script except $1 and $2. Instead of that it outputs the input of those variables but i want it to literally read "$1" and "$2". Help?
Escape it:
echo "ls /SomeFolder | grep \$1 | xargs cat | grep something | grep .txt | awk '{print \$2}' | sed 's/;\$//';" >> script2.sh
Quote it:
echo "ls /SomeFolder | grep "'$'"1 | xargs cat | grep something | grep .txt | awk '{print "'$'"2}' | sed 's/;"'$'"//';" >> script2.sh
or like this:
echo 'ls /SomeFolder | grep $1 | xargs cat | grep something | grep .txt | awk '\''{print $2}'\'' | sed '\''s/;$//'\'';' >> script2.sh
Use quoted here document:
cat << 'EOF' >> script2.sh
ls /SomeFolder | grep $1 | xargs cat | grep something | grep .txt | awk '{print $2}' | sed 's/;$//';
EOF
Basically you want to prevent expansion, ie. take the string literaly. You may want to read bashfaq quotes
First, you'd never write this (see https://mywiki.wooledge.org/ParsingLs, http://porkmail.org/era/unix/award.html and you don't need greps+seds+pipes when you're using awk):
ls /SomeFolder | grep $1 | xargs cat | grep something | grep .txt | awk '{print $2}' | sed 's/;$//'`
you'd write this instead:
find /SomeFolder -mindepth 1 -maxdepth 1 -type f -name "*$1*" -exec \
awk '/something/ && /.txt/{sub(/;$/,"",$2); print $2}' {} +
or if you prefer using print | xargs instead of -exec:
find /SomeFolder -mindepth 1 -maxdepth 1 -type f -name "*$1*" -print0 |
xargs -0 awk '/something/ && /.txt/{sub(/;$/,"",$2); print $2}'
and now to append that script to a file would be:
cat <<'EOF' >> script2.sh
find /SomeFolder -mindepth 1 -maxdepth 1 -type f -name "*$1*" -print0 |
xargs -0 awk '/something/ && /.txt/{sub(/;$/,"",$2); print $2}'
EOF
Btw, if you want the . in .txt to be treated literally instead of as a regexp metachar meaning "any character" then you should be using \.txt instead of .txt.
I am trying to store multiple string in for loop but it giving me unwanted answer.
My code is :
#!/bin/bash
declare -a arr=("ps -ef | grep icsmpgum | grep $USER | grep -v grep | awk '{print $9,$8}' | awk '{print $1}'")
for i in "${arr[#]}"
do
echo "$i"
done
The output of
ps -ef | grep icsmpgum | grep $USER | grep -v grep | awk '{print $9,$8}' | awk '{print $1}'
is :
icsmpgum
ABC
DEF
I want to refer to these 3 string values in for loop but after applying for loop as mention above it giving me output as :
Output :
ps -ef | grep icsmpgum | grep tsaprm1 | grep -v grep | awk '{print ,}' | awk '{print }'
How should I store these string values in variables ?
You need to use a command substitution, rather than quoting the command:
arr=( $(ps -ef | grep icsmpgum | grep $USER | grep -v grep | awk '{print $9,$8}' | awk '{print $1}') )
I suspect that this will work but there's a lot of further tidying up to be done; all the filtering that you want to do is possible in one call to awk:
arr=( $(ps -ef | awk -v user="$USER" '!/awk/ && /icsmpgum/ && $0 ~ user { print $9 }') )
As mentioned in the comments, there are potential risks to building an array like this (e.g. glob characters such as * would be expanded and you would end up with extra values in the array). A safer option would be to use a process substitution:
read -ra arr < <(ps -ef | awk -v user="$USER" '!/awk/ && /icsmpgum/ && $0 ~ user { print $9 }')
I've got the following bash code:
md5sum -c checksum.md5 2>&1 | grep FAILED | awk '{print $1}' | sed 's/:$// > /tmp/check.tmp
awk '{system("wget http://example.com/"$1"")}' /tmp/check.tmp
How can I use awk without a temp file?
Something like
files=`md5sum -c checksum.md5 2>&1 | grep FAILED | awk '{print $1}' | sed 's/:$//`
awk '{system("wget http://example.com/"$1"")}' $files
You can simplify the whole command to this:
md5sum -c checksum.md5 2>&1 |\
awk -F'[:/]' '/FAILED/{system("wget http://example.com/"$(NF-1))}'
wget has a switch -i that can come in handy:
md5sum -c checksum.md5 2>&1 | \
sed -n '/FAILED$/ { s/: FAILED$//; s!^!http://example.com/!; p; }' | \
wget -i
Like this:
awk '{system("wget http://example.com/"$1"")}' <<< $files
I am trying to open some files as awk's output; the command is:
grep "formatDate\s=" "js/components/" | awk '{print $1}' | awk -F ":" '/1/ {print $1}'
and it (seems to) work correctly.
If I try to open that output as vim's tabs, like this:
vim -p ${ grep "formatDate\s=" "js/components/" | awk '{print $1}' | awk -F ":" '/1/ {print $1}' }
then I get:
-bash: ${ grep "formatDate\s=" "js/components/" | awk '{print $1}' | awk -F ":" '/1/ {print $1}' }: bad substitution
Any help? Thanks.
The way to execute a command is $(), whereas you are using ${}.
Hence, this should work:
vim -p $(grep "formatDate\s=" "js/components/" | awk '{print $1}' | awk -F ":" '/1/ {print $1}')
Is there a way to hide xfce4-panel from command line. If no any other solutions how to hide it from terminal ?
Regards,
Levon
I got here wondering the same. Apparently there is no direct command, but it's pretty straightforward to write a shell script:
INFO=$(xwininfo -name xfce4-panel)
STATE=$(echo "$INFO" | grep "Map State:" | head -n1 | awk -F: '{print $2}' | xargs)
WID=$(echo "$INFO" | grep "Window id:" | head -n1 | awk -F: '{print $3}' | awk '{print $1}')
if test "$STATE" = "IsViewable"; then
xdotool windowminimize "$WID"
else
xdotool windowmap "$WID"
fi