javax.servlet.ServletException: Circular view path [login] - spring

Question

I am new to Spring Boot and want to add the Spring Security module to my previous project. I followed this link. My Spring Boot version is 1.5.6.RELEASE.
Here is the security configuration
#Configuration
#EnableWebSecurity
public class WebSecurityConfig extends WebSecurityConfigurerAdapter {
#Override
protected void configure(HttpSecurity http) throws Exception {
http
.authorizeRequests()
.antMatchers("/", "/home").permitAll()
.anyRequest().authenticated()
.and()
.formLogin()
.loginPage("/login")
.permitAll()
.and()
.logout()
.permitAll();
}
#Autowired
public void configureGlobal(AuthenticationManagerBuilder auth) throws Exception {
auth
.inMemoryAuthentication()
.withUser("user").password("password").roles("USER");
}
}
Here is the MVC configuration:
#Configuration
public class MvcConfig extends WebMvcConfigurerAdapter {
#Override
public void addViewControllers(ViewControllerRegistry registry) {
registry.addViewController("/home").setViewName("home");
registry.addViewController("/").setViewName("home");
registry.addViewController("/hello").setViewName("hello");
registry.addViewController("/login").setViewName("login");
}
I can ensure that home.html, hello.html and login.html are located in resources/templates/. As I added the Spring Security part to a previous project, I also has an controller that handles jpa request
#Controller
#RequestMapping("/test/pgsql")
public class TestPostgreSQLController {
#Autowired
private CustomerRepository customerRepository;
#RequestMapping("/save")
public #ResponseBody
String process() {
customerRepository.save(new Customer("Neo", "Chan"));
customerRepository.save(new Customer("Luke", "Liu"));
customerRepository.save(new Customer("Ran", "Guo"));
customerRepository.save(new Customer("Joey", "Chen"));
customerRepository.save(new Customer("Larry", "Huang"));
return "Done";
}
#RequestMapping("/findbyid")
public #ResponseBody String findById(#RequestParam("id") long id) {
String result = "";
result = customerRepository.findOne(id).toString();
return result;
}
#RequestMapping("/find")
public #ResponseBody String find(#RequestParam("lastname") String lastName) {
String results = "";
for (Customer bauer : customerRepository.findCustomersByLastName(lastName)) {
System.out.println(bauer.toString());
results = results + bauer.toString() + "<br>";
}
return results;
}
}
the pom.xml is like this
<dependency>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-data-jpa</artifactId>
</dependency>
<dependency>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-web</artifactId>
</dependency>
<dependency>
<groupId>org.postgresql</groupId>
<artifactId>postgresql</artifactId>
<scope>runtime</scope>
</dependency>
<dependency>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-test</artifactId>
<scope>test</scope>
</dependency>
<dependency>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-security</artifactId>
</dependency>
I build the project as jar package. When I visit the localhost:8080/home or localhost:8080/login address. It throws the following exception:
javax.servlet.ServletException: Circular view path [login]: would dispatch back to the current handler URL [/login] again. Check your ViewResolver setup! (Hint: This may be the result of an unspecified view, due to default view name generation.)
Any suggestion? Thanks in advance.

Answer 1

I had the same problem. Problem is related with pom file, you should add Thymeleaf dependency and code will start works.
<dependency>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-thymeleaf</artifactId>
</dependency>

Answer 2

It's long time after this question been asked but I found the answer here]
try to add registry.addViewController("/login").setViewName("login.html");
that work for me hope it helps1