ansible expression to use with with_item - ansible

Question

I have a variable, more specifically it's the result (registered in a variable with register:) of a set_fact task using with_item, let's named it myvar, and to simply, I only display the relevant part of it.
{
"msg": "All items completed",
"results": [
{
"item": "item1",
"stdout_lines": [
[
"result line 1",
"result line 2"
]
]
},
{
"item": "item2",
"stdout_lines": [
[
"result line 1"
]
]
}
]
}
I need to run a task for each "result line X" that will include in the command the value of "item" and the "result line X" value
I'm not sure how to do this.
if I do
- debug:
msg: "{{ item.item }} , {{ item | json_query('stdout_lines[0][*]') | list }}"
with_items: "{{ myvar | json_query('results[*]') }}"
The following would output
item1 ; [u'result line 1',u'result line 2']
item2 ; [u'result line 1']
I have both all stdout_lines entries on the same line. so the split of the stdout_lines should happen in the with_item expression
But here I don't find how I could "fetch" all the stdout_lines of all results and at the same time keep the "item" value.

Answer 1

If you'd have flat stdout_lines, you could just do with_subelements.
In your case, you need to spice it with JMESPath a bit:
---
- hosts: localhost
gather_facts: no
vars:
myvar:
"results": [
{
"item": "item1",
"stdout_lines": [
[
"result line 1",
"result line 2"
]
]
},
{
"item": "item2",
"stdout_lines": [
[
"result line 1"
]
]
}
]
tasks:
- command: echo {{ item.0.name }} {{ item.1 }}
with_subelements:
- "{{ myvar.results | json_query('[].{name:item,lines:stdout_lines[]}') }}"
- lines