Is it possible to pass my subscription ID to a LUIS Dialog, rather than an attribute?
My application has this information on the database, and I need to pass it via a constructor, or another way.
Any sugestions?
Thank you.
The LuisDialog has a constructor that takes a LuisService(s). You can pass in a modelId and subscriptionId, and create the LuisModelAttribute dynamically:
public class LuisTestDialog : LuisDialog<object>
{
public LuisTestDialog(string modelId, string subscriptionId)
: base(new LuisService(new LuisModelAttribute(modelId, subscriptionId)))
{
}
}
Related
As per docs, kotlin var properties can be bind in ViewModel as
// Kotlin var property
class PersonVarViewModel(person: Person) : ViewModel() {
val name = bind { person.observable(Person::name) }
}
It seems like doesn't work.
How to solve this issue. IDE shows red underline bellow "bind"
but if i write
val name = bind(RoomType::name)
it shows no error. but updating the value using UI fields does'nt update the model value.
Please help
In your class declaration, use var person: Person.
person needs to be a member of the class, not just a parameter to the constructor. You can do this by declaring it var or val in the constructor parameters, or you can add a member field to the class the conventional way and assign it (probably using by property, but not sure if that's what you want)
class PersonVarViewModel(var person: Person) : ViewModel() {
val name = bind { person.observable(Person::name) }
}
For ItemViewModel ...
class PersonVarViewModel(var person: Person) : ItemViewModel<Person>() {
val name = bind { person.observable(Person::name) }
}
You need to make the ItemViewModel aware of the person instance, but also let it react to changes to the underlying item later. You need to assign the person you pass in to the item property of the ItemViewModel. This can be done by passing it in the constructor:
class PersonVarViewModel(person: Person) : ItemViewModel<Person>(person) {
val name = bind(Person::name)
}
Be aware that if you add this constructor, you can only use the that viewmodel with injection if you push it manually into scopes, since it can't be instantiated by the framework. You should therefore either add a noargs constructor as well, or simply omit the person parameter and assign to item after you create it.
If you update the value in the underlying person, it will only be visible in the view model if the value is observable. If not, you have to call rollback() to update changes from the person. You can call rollback for specific fields only.
If possible, use observable properties in your domain model objects to avoid such issues.
I'd like to configure a route that always returns a single entity.
The controller looks like:
class StatsController: ODataController {
public Stats Get() {
return new Stats();
}
}
The url to access it should be: GET ~/service-prefix/stats
All the options I've seen involve having to return IQueryable, or when returning a single entity, passing in a key in a form of ~/service-prefix/EntitySet(1)
Is there a way to achieve the above without having to return an IQueriable?
By default any action of the following forms should be reachable for your scenario:
Example:
public Stat Get([FromODataUri] int key) { }
or
public Stat Get#your-entity-name#([FromODataUri] int key) { }
To access a single object without needing to have an entityset, odata v4 introduces the concept of singletons.
From OData v4 spec:
A singleton allows addressing a single entity directly from the entity container without having to know its key, and without requiring an entity set.
More info:
Use Singleton to define your special entity
ODataLib for OData v4: Singletons and Containment
I believe Singleton could meet your requirement, but it is not implemented in WebApi. Fortunately, there is another option: unbound function. Just follow this sample: http://aspnet.codeplex.com/SourceControl/latest#Samples/WebApi/OData/v4/ODataFunctionSample/.
There is a method in ProductsController:
[HttpGet]
[ODataRoute("GetSalesTaxRate(state={state})")]
public IHttpActionResult GetSalesTaxRate([FromODataUri] string state)
{
return Ok(GetRate(state));
}
It is requested through this URL: ~/service-prefix/GetSalesTaxReate(state='WA') and is very close to your scenario. The only thing you need to do is to remove the parameter of the function:
[HttpGet]
[ODataRoute("GetStats()")]
public IHttpActionResult GetStats()
{
return Ok(new Stats());
}
Now you can request ~/sevice-prefix/GetStats().
i'm new to WebAPI and had a few qeustion to custom method calling.
So, im working with Entity Framework and created a WebAPI with basic CRUD methods.
But now i want to add some custom methods, is it possible to call arrays as parameters? And when yes, how?
This is my method:
public void AddRoles(Guid userid, Guid[] roleids)
So how it is possible to call this method through webapi?
I tryed it with
http://localhost:60690/api/MyController/AddRoles...
And is it possible to call void method? What is the response?
thanks and greetings,
Joerg
http://localhost:60690/api/MyController/AddRoles?userid=<user id guid here>&roleids=<guid1 here>&roleids=<guid2 here>...
As for the void method, of course it is possible, response will be with 200 code and empty body.
For GET you can refer to the following SO question:
How to pass an array of integers to ASP.NET Web API?
If you want to try to use POST then continue to read:
You should create a DTO for your parameters like such:
public class AddRoleModel
{
Guid UserId { get; set; }
Guid[] RoleIds { get; set; }
}
Change your method to accept accept POST and your new AddRoleModel DTO instead of the two different parameters like so:
[HttpPost]
public void AddRoles(AddRoleModel model)
{
...
}
And POST the json for that model to the method
json could look like this:
{
UserId: "{guid}",
RoleIds: ["{some guid}", "{some other guid}"]
}
How do I pass a whole model via html.actionlink or using any other method except form submission? Is there any way or tips for it?
Though it's not advisable in complex cases, you can still do that!
public class QueryViewModel
{
public string Search { get; set; }
public string Category { get; set; }
public int Page { get; set; }
}
// just for testing
#{
var queryViewModel = new QueryViewModel
{
Search = "routing",
Category = "mvc",
Page = 23
};
}
#Html.ActionLink("Looking for something", "SearchAction", "SearchController"
queryViewModel, null);
This will generate an action link with href like this,
/SearchController/SearchAction?Search=routing&Category=mvc&Page=23
Here will be your action,
public ViewResult SearchAction(QueryViewModel query)
{
...
}
No, you cannot pass entire complex objects with links or forms. You have a couple of possible approaches that you could take:
Include each individual property of the object as query string parameters (or input fields if you are using a form) so that the default model binder is able to reconstruct the object back in the controller action
Pass only an id as query string parameter (or input field if you are using a form) and have the controller action use this id to retrieve the actual object from some data store
Use session
You could use javascript to detect a click on the link, serialize the form (or whatever data you want to pass) and append it to your request parameters. This should achieve what you're looking to achieve...
I am working with a Spring MVC project and I can't figure out how to change the String representation of a Model in the Views.
I have a Customer model that has a ONE_TO_MANY relationship with a WorkOrder model. On the workorders/show.jspx the Customer is displayed as a String that is the first and last name, email address, and phone number concatenated.
How do I change this? I thought I could just change the toString method on the Customer, but that didn't work.
One solution would be to change/push-in show() to WorkOrderController to map a rendered-view-tag to what you would like to see.
#RequestMapping(value = "/{id}", produces = "text/html")
public String show(
#PathVariable("id") Long id,
Model uiModel)
{
final WorkOrder workOrder = WorkOrder.findWorkOrder(id);
uiModel.addAttribute("workOrder", workOrder);
uiModel.addAttribute("itemId", id);
// Everything but this next line is just ripped out from the aspectJ/roo stuff.
// Write a method that returns a formatted string for the customer name,
// and a customer accessor for WorkOrder.
uiModel.addAttribute("customerDisplay", workOrder.getCustomer().getDisplayName());
return "workorders/show";
}
Put/define a label in your i18n/application.properties file for customerDisplay.
Then in your show.jspx, you can access the mapping with something like... (The trick is similar for other views.)
<field:display field="customerDisplay" id="s_your_package_path_model_WorkOrder_customerDisplay" object="${workorder}" z="user-managed" />
I'm new to Roo, so I'd love to see a better answer.
We found a good solution. There are toString() methods for all the models in ApplicationConversionServiceFactoryBean_Roo_ConversionService.aj
You can just push the method for the Model you want into ApplicationConversionServiceFactoryBean.java and modify it. In my case I added this:
public Converter<Customer, String> getCustomerToStringConverter() {
return new org.springframework.core.convert.converter.Converter<com.eg.egmedia.bizapp.model.Customer, java.lang.String>() {
public String convert(Customer customer) {
return new StringBuilder().append(customer.getId()).append(' ').append(customer.getFirstName()).append(' ').append(customer.getLastName()).toString();
}
};
}
Spring uses this for all the view pages so this will change the String representation of your model across your whole app!