GNU make: Why target is always running? - makefile

Below is the example makefile.
If syn output is not changed, ila shall not run.
Don't understand why ila is always running.
DEBUG_FILE = ./debug/debug.txt
INPUTS0 = syn.tcl
OUTPUTS0 = syn.out
OUTPUT_ILA = $(DEBUG_FILE)
############################################################################
#
# Dependencies / rules
#
############################################################################
ifdef DEBUG_FILE
all: ila
else
all: syn
endif
## Synthesis
$(OUTPUTS0): $(INPUTS0)
echo "Synthesis Process."
touch $(OUTPUTS0)
$(OUTPUT_ILA): $(OUTPUTS0)
echo "Debug Probe Insertion."
touch $(OUTPUT_ILA)
syn: $(OUTPUTS0)
ila: $(OUTPUT_ILA)
First run:
-> make
echo "Synthesis Process."
Synthesis Process.
touch syn.out
echo "Debug Probe Insertion."
Debug Probe Insertion.
Second run:
-> make
echo "Debug Probe Insertion."
Debug Probe Insertion.
Because $(OUTPUT_ILA) should be newer than $(OUTPUTS0). I'm not expecting ila is running at second time.

You don't create a file ila. The make assumes you want create a file ila which should newer than $(OUTPUT_ILA).

Are you still having a problem with this?
I cannot reproduce this error. For me, the $(OUTPUT_ILA) recipe runs only the first time. (or if syn.out or syn.tcl are updated)
My guess is that you were deleting the debug.txt file in between runs.
Note that you can use the trace and debug flags to more easily determine why make tries to remake certain targets. (You will get a lot of extraneous output about searching for implict rules, unless you also disable built-in rules with the third flag you see below.)
Run this:
make --trace -d --no-builtin-rules
or
make --trace -d --no-builtin-rules [<TARGET>]

Related

How to change the return value of a `make` command

I have a number of makefiles that build and run tests. I would like to create a script that makes each one and notes whether the tests passed or failed. Though I can determine test status within each make file, I am having trouble finding a way to communicate that status to the caller of the make command.
My first thought is to somehow affect the return value of the make command, though this does not seem possible. Can I do this? Is there some other form of communication I can use to express the test status to the bash script that will be calling make? Perhaps by using environment variables?
Thanks
Edit: It seems that I cannot set the return code for make, so for the time being I will have to make the tests, run them in the calling script instead of the makefile, note the results, and then manually run a make clean. I appreciate everyone's assistance.
Make will only return one of the following according to the source
#define MAKE_SUCCESS 0
#define MAKE_TROUBLE 1
#define MAKE_FAILURE 2
MAKE_SUCCESS and MAKE_FAILURE should be self-explanatory; MAKE_TROUBLE is only returned when running make with the -q option.
That's pretty much all you get from make, there doesn't seem to be any way to set the return code.
The default behavior of make is to return failure and abandon any remaining targets if something failed.
for directory in */; do
if ( cd "$directory" && make ); then
echo "$0: Make in $directory succeeded" >&2
else
echo "$0: Make in $directory failed" >&2
fi
done
Simply ensure each test leaves its result in a file unique to that test. Least friction will be to create test.pass if thes test passes, otherwise create test.fail. At the end of the test run gather up all the files and generate a report.
This scheme has two advantages that I can see:
You can run the tests in parallel (You do us the -jn flag, don't you? (hint: it's the whole point of make))
You can use the result files to record whether the test needs to be re-run (standard culling of work (hint: this is nearly the whole point of make))
Assuming the tests are called test-blah where blah is any string, and that you have a list of tests in ${tests} (after all, you have just built them, so it's not an unreasonable assumption).
A sketch:
fail = ${#:%.pass=%.fail}
test-passes := $(addsuffix .pass,${tests})
${test-passes}: test-%.pass: test-%
rm -f ${fail}
touch $#
$* || mv $# ${fail}
.PHONY: all
all: ${test-passes}
all:
# Count the .pass files, and the .fail files
echo '$(words $(wildcard *.pass)) passes'
echo '$(words $(wildcard *.fail)) failures'
In more detail:
test-passes := $(addsuffix .pass,${tests})
If ${tests} contains test-1 test-2 (say), then ${test-passes} will be test-1.pass test-2.pass
${test-passes}: test-%.pass: test-%
You've just gotta love static pattern rules.
This says that the file test-1.pass depends on the file test-1. Similarly for test-2.pass.
If test-1.pass does not exist, or is older than the executable test-1, then make will run the recipe.
rm -f ${fail}
${fail} expands to the target with pass replaced by fail, or test-1.fail in this case. The -f ensures the rm returns no error in the case that the file does not exist.
touch $# — create the .pass file
$< || mv $# ${fail}
Here we run the executable
If it returns success, our work is finished
If it fails, the output file is deleted, and test-1.fail is put in its place
Either way, make sees no error
.PHONY: all — The all target is symbolic and is not a file
all: ${test-passes}
Before we run the recipe for all, we build and run all the tests
echo '$(words $(wildcard *.pass)) passes'
Before passing the text to the shell, make expands $(wildcard) into a list of pass files, and then counts the files with $(words). The shell gets the command echo 4 passes (say)
You run this with
$ make -j9 all
Make will keep 9 jobs running at once — lovely if you have 8 CPUs.

Getting gmake to complete a recipe early

I know this has been asked before, but none of the solutions I've found work for me because they're anti-DRY.
I have a number of targets that depend on things that can't readily be timestamped -- such as files copied from another system. What I'd like to be able to do is list dependencies in a variable, like nobuild=this,that, and have those targets be assumed to be up-to-date. Since I have a lot of these, I don't want to ifdef around each one; what would be pseudocodibly preferable would be something like
ignorable-target: dependencies
$(call ifnobuild,$#)
.. rest of normal build steps ..
where the ifnobuild macro expanded to some sort of exit-from-this-recipe-with-success gmake instruction if ignorable-target was mentioned in the nobuild variable.
I also don't want to get into multi-line continued shell commands in order to defer the conditional to the recipe itself; I want to be able to tell make "Assume these targets are up-to-date and don't try to build them," so I can test other aspects with the local copies already obtained from the problematic recipes.
There isn't any sort of exit-recipe-with-success mechanism in gmake, is there?
[Edited to hopefully make the situation more clear.]
Here's an example. Targets remote1 and remote2 each involve using ssh to do something time-consuming on a remote system, and then copying the results locally. Target local1 is built locally, and isn't a time sink. target-under-work depends on all three of the above.
local1: local1.c Makefile
remote1: local1
scp local1 remote-host:/tmp/
ssh remote-host /tmp/local1 some-args # takes a long time
scp remote-host:/tmp/local1.out remote1
remote2: local1
scp local1 other-host:/tmp/
ssh other-host /tmp/local1 other-args # takes a long time
scp other-host:/tmp/local1.out remote2
target-under-work: local1 remote1 remote2
do-something-with remote1,remote2
Now, when I just run make target-under-work, it's going to run the recipes for remote1 and remote2. However, the local copies of those files are 'good enough' for my testing, so I don't want them run every time. Once things go into production, they will be run every time, but while I'm developing target-under-work, I just want to use the copies already built, and I can rebuild them daily (or whatever) for the necessary testing granularity.
The above is over-simplified; there are multiple steps and targets that depend on remote1 and/or remote2. I see how I can get the effect I want by making them order-only prerequisites -- but that would mean changing the dependency list of every target that has them as prerequisites, rather than making a single change to remote1 and remote2 so I can use some variable from the command line to tell their recipes 'pretend this has been built, don't actually build it if there's already a copy.'
I hope this makes my question more clear.
No, this early exit make feature does not exist.
Note that your problem is probably under-specified because you don't explain what behaviour you want when a slow target does not exist yet.
Let's assume that the slow targets listed in nobuild shall be rebuilt if and only if they don't exist. Instead of using make functions to early exit their recipe you could use make functions to "hide" their list of prerequisites. This way, if they already exist, they will not be rebuilt, even if they are outdated. The only subtlety is that you will need the second expansion to use the $# automatic variable in the lists of prerequisites. In the following example slow (your remoteX) depends on fast1 (your local1). fast2 (your target-under-work) depends on fast1 and slow:
host> cat Makefile
# Expands as empty string if $(1) exists and
# listed in $(nobuild). Else expands as $(2).
# $(1): target
# $(2): prerequisites
define HIDE_IF_NOBUILD
$(if $(wildcard $(1)),$(if $(filter $(1),$(nobuild)),,$(2)),$(2))
endef
nobuild :=
fast1:
#echo 'build $#'
#touch $#
fast2: fast1 slow
#echo 'build $#'
#touch $#
.SECONDEXPANSION:
slow: $$(call HIDE_IF_NOBUILD,$$#,fast1)
#echo 'build $#'
#touch $#
# Case 1: slow target not listed in nobuild and not existing
host> rm -f slow; touch fast1; make fast2
build slow
build fast2
# Case 2: slow target not listed in nobuild and existing and outdated
host> touch slow; sleep 2; touch fast1; make fast2
build slow
build fast2
# Case 3: slow target listed in nobuild and not existing
host> rm -f slow; touch fast1; make nobuild="slow" fast2
build slow
build fast2
# Case 4: slow target listed in nobuild and existing and outdated
host> touch slow; sleep 2; touch fast1; make nobuild="slow" fast2
build fast2

Why a makefile target is always run?

Makefile:
OUTPUT_ILA = "path/file"
all: syn ila opt ...
$(OUTPUT_SYN): $(INPUT_SYN)
#echo "syn"
...
$(OUTPUT_ILA): $(OUTPUT_SYN)
#echo "ila"
...
$(OUTPUT_OPT): $(INPUT_OPT)
#echo "opt"
...
syn: $(OUTPUT_SYN)
ila: $(OUTPUT_ILA)
opt: $(OUTPUT_OPT)
...
Don't understand why step ila is always run. When $(OUTPUT_SYN) is unchanged and ila run before, make still runs ila step.
The expected behavior is ila to only run when, in the first step, $(OUTPUT_SYN) is changed. If $(OUTPUT_SYN) is unchanged, it shall skip ila and run opt.
How to debug and fix this?
Since you don't provide any information about what the value of the variables are, or the what the recipes do, there's little we can tell you about why.
However, note that if the target of a recipe does not exist then the recipe is always run (it has to be, since make cannot determine if it's out of date or not). So, if your recipe for the $(OUTPUT_ILA) target does not create the file named by the variable OUTPUT_ILA (whatever that expands to) then this recipe will always be run.
Put another way, you should make sure that the recipe updates the file specified by the automatic variable $#, if you want it to work properly.

OpenCobol Makefile

I am trying to compile an OpenCobol program using make. I am always getting "make: Nothing to be done for test1.cob". Here is my makefile. I had put a TAB before cobc. But still I am getting that message. Please help.
Thanks.
COBCWARN = -W
%: %.cob
cobc $(COBCWARN) -free -x $^ -o $#
And here is my cobol program.
IDENTIFICATION DIVISION.
PROGRAM-ID. TEST1.
PROCEDURE DIVISION.
DISPLAY 'Hello world!'.
STOP RUN.
Your makefile contains no actual targets. You have defined only a pattern rule which tells make how to build targets that match the pattern. But make doesn't go looking for targets out on the filesystem that could match the pattern, it only checks the pattern against targets that have been specifically requested.
You don't have any specific targets (files) listed in your makefile, so the only way make can know about a target is if you give the target to be built on the command line.
You are running this command from within vim, using the % special token, which expands to the name of the file currently being edited. That means you are running the command:
make test1.cob
because you are editing the file test1.cob. So, you are telling make "please try to create the target (file) test1.cob". But, that file already exists (it's the file you're writing). So make says "nothing to do".
If you run make and ask it to create the target you really want created, it will work:
make test1
Now the file test1 doesn't exist, and make can find a pattern rule that knows how to build it, so make will run that rule.
Alternatively, you can edit your makefile to add the specific target, like this:
COBCWARN = -W
test1: test1.cob
%: %.cob
cobc $(COBCWARN) -free -x $^ -o $#
Then you can run make with no arguments at all. Without any command line arguments, make will look in the makefile for explicit targets and find test1 as the first one. It sees that there is a rule (the pattern rule) that matches that target, so it will build that target.
UPDATE
If you want to allow a simple command make to build multiple programs, write your makefile like this:
COBCWARN = -W
all: test1 test2 test3
.PHONY: all
%: %.cob
cobc $(COBCWARN) -free -x $^ -o $#
Now from vim you can just say :!make and that's it.
If you run make with no arguments then it will find the first explicit target in the makefile and build that. In this example the first target is all, and its prerequisites are the possible programs to build. To build each one make sees that it can apply the pattern rule, and so it will do so (if the .cob file has been modified since the last time the program was built).

make: disable parallel execution of some targets

I have a compile job where linking is taking a lot of IO work. We have around a dozen of cores so we run make -j13, but when it comes to linking the 6 targets, I'd like those to be done in a round robin way. I thought about making one depend on the next but I think this would break the individual targets. Any ideas how to solve this small issue?
make itself doesn't provide a mechanism to request "N of these, but no more than M of those at a time".
You might try using the sem command from the GNU parallel package in the recipe of your linker rules. Its documentation has an example of ensuring only one instance of a tool runs at once. In your example, you would allow make to start up to 13 sems at a time, but only one of those at a time will run the linker, while the others block.
The downside is that you could get into a situation where 5 of your make's 13 job slots are tied up with instances of sem that are all waiting for a linker process to finish. Depending on the structure of your build, that might mean some wasted CPU time. Still beats 6 linkers thrashing the disk at once, though :-)
You should specify that your six targets cannot be built in parallel. Add a line like this to your makefile:
.NOTPARALLEL: target1 target2 target3 target4 target5 target6
For more information look here https://www.gnu.org/software/make/manual/html_node/Parallel-Disable.html.
I've stumbled upon a hacky solution:
For each recipe it runs, Make does two things: it expands variables/functions in the recipe, and then runs the shell commands.
Since the first step can read/write the global variables, it seems to be done synchronously.
So if you run all your shell commands during the first step (using $(shell )), no other recipe will be able to start while they're running.
E.g. consider this makefile:
all: a b
a:
sleep 1
b:
sleep 1
time make -j2 reports 1 second.
But if you rewrite it to this:
# A string of all single-letter Make flags, without spaces.
override single_letter_makeflags = $(filter-out -%,$(firstword $(MAKEFLAGS)))
ifneq ($(findstring n,$(single_letter_makeflags)),)
# See below.
override safe_shell = $(info Would run shell command: $1)
else ifeq ($(filter --trace,$(MAKEFLAGS)),)
# Same as `$(shell ...)`, but triggers a error on failure.
override safe_shell = $(shell $1)$(if $(filter-out 0,$(.SHELLSTATUS)),$(error Unable to execute `$1`, exit code $(.SHELLSTATUS)))
else
# Same functions but with logging.
override safe_shell = $(info Shell command: $1)$(shell $1)$(if $(filter-out 0,$(.SHELLSTATUS)),$(error Unable to execute `$1`, exit code $(>
endif
# Same as `safe_shell`, but discards the output and expands to nothing.
override safe_shell_exec = $(call,$(call safe_shell,$1))
all: a b
a:
$(call safe_shell_exec,sleep 1)
#true
b:
$(call safe_shell_exec,sleep 1)
#true
time make -j2 now reports 2 seconds.
Here, #true does nothing, and suppresses Nothing to be done for ?? output.
There are some problems with this approach though. One is that all output is discarded unless redirected to file or stderr...
It won't break individual targets.
You can create any number of (:) rules for a target, as long as only one of them has an actual recipe for building it. This appears to be a good use case for that.

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