I am planning to store data from multiple tables which has one to many JPA relationship. I am creating my Repository interface which extends from JPARepository. My question is If I want to save a data on Many sides of relationship (in the below scenario it's Tour) then shall I do with TourRepository or PersonRespository?
On a similar note Is it ideal to create individual repository classes for every JPA entities where data need to be stored? or any better way with limited repository classes the data store to database can be achieved?
#Entity
#Table(name="Person")
public class Person implements Serializable{
...
...
#OneToMany(mappedBy = "person")
private List<Tour> tours;
...
#Entity
#Table(name = "Tour")
public class Tour implements Serializable{
...
...
#ManyToOne
#JoinColumn(name = "PERSON_ID")
private Person person;
...
You have two independent entities. Person can exist without Tour and Tour can exist without Person. So you should have two repositories - for Person and Tour to store their data independently:
Tour tour1 = new Tour("tour1");
tourRepo.save(tour1);
Person person1 = new Person("person1");
person1.addTour(tour1);
personRepo.save(person1);
You chose the bidirectional one-to-many association so you have to use a 'helper' method like addTour to link both entities:
public Person addTour(Tour tour) {
tour.setPerson(this);
this.tours.add(tour);
return this;
}
Additional info: Best Practices for Many-To-One and One-To-Many Association Mappings
Add cascade to tours:
#OneToMany(mappedBy = "person", cascade = {CascadeType.PERSIST, CascadeType.MERGE})
private List<Tour> tours;
When you save person object, his tours will be saved automatically.
By the way, in Person class, you should have an addTour(...) utilities method like this:
// Person.java
public void addTour(Tour tour){
this.tours.add(tour);
tour.setPerson(this);
}
I would suggest you to use CascadeType.ALL on #OneToMany mapping in Person entity:
#OneToMany(mappedBy = "person",cascade = {CascadeType.ALL})
private List<Tour> tours;
And then create repository for person to save person object with the list of tours .
CascadeType.ALL means persistence will propagate all EntityManager operations like PERSIST, REMOVE, REFRESH, MERGE, DETACH to the relating entities.
Related
I have two tables joined with a OneToOne relationship, one side exists in the database. When I insert the other side I want the first side's foreign key column to update so that it knows about the relationship without having to do it manually. Is this possible.
Here's my simplified example, I am using #MappedSuperclass because I have some shared fields in most of my Entities I included it here just in case it's causing an issue.
The base entity
#MappedSuperclass
#Data
public abstract class BaseEntity {
//defines some common fields I have in all my entities such Id
}
Abstract Image class
#Entity
#Inheritance(strategy = InheritanceType.SINGLE_TABLE)
#DiscriminatorColumn(name = "dtype", discriminatorType = DiscriminatorType.STRING)
#Data
public abstract class Image extends BaseEntity {
//defines some other fields
public abstract UUID getTypeId();
}
UserProfilePhoto
#Entity
#Data
public class UserProfilePhoto extends Image {
#OneToOne(cascade = CascadeType.ALL, mappedBy = "userProfilePhoto")
private Profile profile;
#Override
public UUID getTypeId() {
return user.getId();
}
}
Profile
#Entity
public class Profile extends Base {
//defines some other fields
#OneToOne(fetch = FetchType.EAGER)
#JoinColumn()
private UserProfilePhoto profilePhoto;
}
I'm looking for the following behavior:
When UserProfilePhoto is saved to image table (with Profile ID) the corresponding ImageId is updated in Profile
When Profile is Deleted the corresponding UserProfilePhoto is deleted from image table.
When UserProfilePhoto is deleted Profile remains but the foreign key column is nulled.
From researching this I think it's possible but it's a matter of getting the annotations correct. I've tried different combinations with no luck. Is what I'm looking for even possible?
No, it is not possible the way you describe it.
Any bidirectional relationship in JPA is controlled exclusively by the side indicated by mappedBy, so you need to update that side in your code, in order to have it persisted.
You can do that by invoking the other side in the setter, or by editing the other side in the first place.
I have two entities Estate and PropertyTags in a Spring Boot application. The Estate entity has a many-to-many relationship with the PropertyTag (PropertyTag is also used by other entities)
This is the Estate entity:
#Entity
public class Estate{
#Id
private Long id;
.
.
#ManyToMany
private Set<PropertyTag> propertyTags;
.
.
// other properties
}
And the PropertyTag class:
#Entity
public class PropertyTag{
#Id
private Long id;
private String tagName;
// getters and setters
}
The above relationship created 3 database tables with one table for foreign keys of the relationship.
I need a repository method (or query) that will retrieve an Estate that will take and argument of an estate Id and property tag object.
I tried using the hibernate keywords as below:
public interface EstateRepository extends JpaRepository<Estate, Long> {
Optional<Estate> findByIdAndPropertyTagsContaining(Long estateId, PropertyTag childTag);
}
But that did not work.
I do not want to retrieve an estate via its ID and manually loop through its property tags to check if a tag exists in its collection. I feel this can be done with a query of the database
I am not so good at writing custom queries. I need help with the query to do that.
Thank you.
To get an Estate entity by the PropertyTag entity you can also just use the id of the PropertyTag and try
Optional<Estate> findByIdAndPropertyTags_Id(Long estateId, Long propertyTagId);
Which should return the Estate containing a tag with the given ID.
Containing is used for String searching
I am doing many to one mapping in hibernate. I am using the existing tables which I created earlier for one to many mapping (customer and order) but when I am trying to map and update those table I couldn't able to I don't know how should I processed? and I would like to insert the data meaning I would like to create some more orders using command line runner for that customer.
Could you please help me with this
Appreciate your help.
Mapping one-to-many and many-to-one association
Both associations are the same association seen from the perspective of the owing and subordinate entities and respectively.
Student one-to-many Address
Address many-to-one Student
#OneToMany annotation can be applied to a field or property value of "one" end entity class for a collection or an array representing the mapped "many" end of the association.
#ManyToONe relationship between two entities is by managing the FK(Foreign key) of the "one" end entity, as a column in the "many" entity table.
> **Bidirectional one-to-many using ```#JoinColumn```**
#Entity
public class Student{
#OneToMany(cascade = CasecadeType.ALL)
#JoinTable(name="Student_FK")
public set<Address> getAddress(){
return address;
}
}
One-to-Many side as the owing side, You have to remove the mappedBy element and set the #ManyToOne #JoinColumn as insertable and updatable to false. This Solution is not optimized and will produce some additional UPDATE Statement.
#Entity
public class Address{
#ManyToOne(cascade = CasecadeType.ALL)
#JoinColumn(name="STUDENT_FK", insertable = false, updatable = false)
public Student student;
}
For more details look at this link Link
Is it possible to publish two different repositories for the same JPA entity with Spring Data Rest?
I gave the two repositories different paths and rel-names, but only one of the two is available as REST endpoint.
The point why I'm having two repositories is, that one of them is an excerpt, showing only the basic fields of an entity.
The terrible part is not only that you can only have 1 spring data rest repository (#RepositoryRestResource) per Entity but also that if you have a regular JPA #Repository (like CrudRepository or PagingAndSorting) it will also interact with the spring data rest one (as the key in the map is the Entity itself).
Lost quite a few hours debugging random load of one or the other. I guess that if this is a hard limitation of spring data rest at least an Exception could be thrown if the key of the map is already there when trying to override the value.
The answer seems to be: There is only one repository possible per entity.
I ended up using the #Subselect to create a second immutable entity and bound that to the second JpaRepsotory and setting it to #RestResource(exported = false), that also encourages a separation of concerns.
Employee Example
#Entity
#Table(name = "employee")
public class Employee {
#Id
Long id
String name
...
}
#RestResource
public interface EmployeeRepository extends PagingAndSortingRepository<Employee, Long> {
}
#Entity
#Immutable
#Subselect(value = 'select id, name, salary from employee')
public class VEmployeeSummary {
#Id
Long id
...
}
#RestResource(exported = false)
public interface VEmployeeRepository extends JpaRepository<VEmployeeSummary, Long> {
}
Context
Two packages in the monolithic application had different requirements. One needed to expose the entities for the UI in a PagingAndSortingRepository including CRUD functions. The other was for an aggregating backend report component without paging but with sorting.
I know I could have filtered the results from the PagingAndSorting Repository after requesting Pageable.unpaged() but I just wanted a Basic JPA repository which returned List for some filters.
So, this does not directly answer the question, but may help solve the underlying issue.
You can only have one repository per entity... however, you can have multiple entities per table; thus, having multiple repositories per table.
In a bit of code I wrote, I had to create two entities... one with an auto-generated id and another with a preset id, but both pointing to the same table:
#Entity
#Table("line_item")
public class LineItemWithAutoId {
#Id
#GeneratedValue(generator = "system-uuid")
#GenericGenerator(name = "system-uuid", strategy = "uuid")
private String id;
...
}
#Entity
#Table("line_item")
public class LineItemWithPredefinedId {
#Id
private String id;
...
}
Then, I had a repository for each:
public interface LineItemWithoutId extends Repository<LineItemWithAutoId,String> {
...
}
public interface LineItemWithId extends Repository<LineItemWithPredefinedId,String> {
...
}
For the posted issue, you could have two entities. One would be the full entity, with getters and setters for everything. The other, would be the entity, where there are setters for everything, but only getters for the fields you want to make public. Does this make sense?
I use spring data jpa and i try to do a many to many unidirectional relation.
#Entity
public class Appartment {
...
#ManyToMany
private List<AppartmentFeatureOption> featureOption;
}
#Entity
public class AppartmentFeatureOption {
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
private Long appartmentFeatureOptionId;
private String name;
private BigDecimal value;
}
My database is created at run time, but i get this error
org.hibernate.DuplicateMappingException: Same physical table name [appartment_feature_option] references several logical table names: [AppartmentFeatureOption], [Appartment_AppartmentFeatureOption]
Any idea?
Edit with this code that work
#ManyToMany
#JoinTable(name="appartment_feautre_option_appartment", joinColumns=#JoinColumn(name="appartment_id"), inverseJoinColumns=#JoinColumn(name="appartment_feautre_option_id"))
private List<AppartmentFeatureOption> featureOption;
Is this is actually your real code, maybe the issue is that you are using a ManyToMany relationship between Appartment and AppartmentFeatureOption whereas there is no link to Appartment in the AppartmentFeatureOption.
From my understanding for one Appartment you want to have several AppartmentFeatureOption, which is a OneToMany relationship.