sed command containing variable not working - bash

I can't get the syntax for this command right... I need to change a variable in a file where the variable contains a path.
sessionFolderName=/session_`date '+%y%m%d'`_`date '+%H%M'`
sed "s/sessionFolder=.*/sessionFolder=/"$sessionFolder /home/pi/scripts/settings/settings.sh > tmp
mv tmp /home/pi/scripts/settings/settings.sh
However the result is:
sed: -e expression #1, char 35: unknown option to `s'

# You don't need to (and in your case, should not) invoke date command twice.
# Try running following in bash to see the problem.
# $ echo $(date '+%s')_$(sleep 1)_$(date '+%s')
# On a different note, it's better to use $(...) instead of backticks.
sessionFolderName="/session_$(date '+%y%m%d_%H%M')"
# You can use several other separators in sed.
# e.g. :, ;, #, #, _ and even a space
sed "s:sessionFolder=.*:sessionFolder=${sessionFolder}:" /home/pi/scripts/settings/settings.sh > tmp
mv tmp /home/pi/scripts/settings/settings.sh
Refer to this regarding using $() instead of backticks

The problem is with the / char in the start of your variable. This interrupts sed syntax:
[root# ~]# sed "s/sessionFolder=.*/${sessionFolderName}/" text
sed: -e expression #1, char 21: unknown option to `s'
[root# ~]# echo $sessionFolderName
/session_170824_0942
If you escape it using double backslash - \\, it works:
[root# ~]# sed "s/sessionFolder=.*/sessionFolder=\\${sessionFolderName}/" text
sessionFolder=/session_170824_0942

1) You need to escape the / in your input
2) modify the format of the sed command as shown below
sessionFolderName=\\/session_`date '+%y%m%d'`_`date '+%H%M'`
sed "s/sessionFolder=.*/sessionFolder="$sessionFolderName"/" /home/pi/scripts/settings/settings.sh > tmp

Related

How to add all special characters in variable for sed command

I have a variable called varname which have characters such as /,. etc. Requirement is to use it with sed command. This is what I've done.
echo Hello admin, please add , after you enter the image name
read -p varname
sed -i "s/my-images=/&$varname/" /home/myconfig
echo Image $varname has been added to the configuration. Thanks!!
/home/myconfig has
id=1
max-mb=1000
my-images=customimage
And required output is
id=1
max-mb=1000
my-images=mynewtext/version1,customimage
I am getting error while running this code and the error is : sed: -e expression #1, char 28: unknown option to `s'
Any help would be appreciated.
You could escape all /'s in your variable with a backslash \ (a literal \ must be escaped as \\):
sed -i "s/my-images=/&${varname//\//\\/}/" /home/myconfig
if you have entered text with slash (as I can see you have mynewtext/version...), it will recognized as finish s command.
You can try to use another character as separator in sed, like:
sed -i "s#my-images=#&$varname#" /home/myconfig

sed: Bad flag in substitute command '('

I'm trying to replace a placeholder ${SNIPPET} with the content of a js file. I struggle to understand the error I receive though.
sed -e "s/\${SNIPPET}/$(cat snippet.js)/" ../../handlebars/templates/bootstrap-template.hbs
Error: bad flag in substitute command: '('
Looking for a solution that could work cross-platform (OSX/Linux)
Using these test files
$ cat snippet.js
hello/(world)
$ cat template.hbs
foo
${SNIPPET}
bar
I can (kind of) replicate your error (I have GNU sed 4.2.2):
$ sed "s/\${SNIPPET}/$(cat snippet.js)/" template.hbs
sed: -e expression #1, char 20: unknown option to `s'
You can do this, which escapes slashes (which are the delimiter for the s/// command)
sed "s/\${SNIPPET}/$(sed 's,/,\\/,g' snippet.js)/" template.hbs
foo
hello/(world)
bar
Or, if the SNIPPET placeholder is on its own line like I have it, you can use other sed commands:
sed '/\${SNIPPET}/{
# read the file into the stream
r snippet.js
# delete SNIPPET line
d
}' template.hbs
foo
hello/(world)
bar
Yet another approach
j=$(<snippet.js) # read the file: `$(<...)` is a bash builtin for `$(cat ...)`
sed "s/\${SNIPPET}/${j//\//\\\/}/" template.hbs

Bash script sed

I am trying to use sed in bash script as follows:
#!/bin/bash
for i in `seq 1 10`;
do
j=$(($i-1))
OLD="-option_something something/string1_${j}.txt"
NEW="-option_somehting something/string1_${i}.txt"
sed -e "s/$OLD/$NEW/g" file_to_edit.txt
# sed -e "s/$OLD/$NEW/g" file_to_edit.txt > file_to_edit.txt.tmp && mv file_to_edit.txt.tmp file_to_edit.txt
done
But I keep getting following error:
sed: -e expression #1, char 71: unknown option tos'`
I tried the commented line as well, but it does not work too.
It works fine on command line. I do not know what is the problem in script.
Any suggestions? Thanks.
You have a / in the value of OLD and NEW, which is the same character you're using as the delimiter in your sed expression. So the final expression ends up looking like:
sed -e "s/-option_something something/string1_${j}.txt/-option_somehting something/string1_${i}.txt/g"
Do you see all the / in there? Consider instead:
sed -e "s|$OLD|$NEW|g" file_to_edit.txt
You can use any character as the delimiter for sed's s command.

Find and Replace string using sed gives error

I am using shell script. My requirement is to find and replace the string. The string contains "/" char as well. I am getting error sed: -e expression #1, char 18: unterminated `s' command. Can someone tell how should i replace the string which has "/"?
#!/bin/bash
...
search_string="../conf/TestSystem/Inst1.xml"
rep="Inst1/Instrument.xml"
sed -i 's|${line}|${rep}/g' MasterConfiguration.xml
I tried using another sed command but that one also gave error sed: -e expression #1, char 13: unknown option to `s'
sed -e "s/${line}/${rep}/g" MasterConfiguration.xml > tempfile
Whenever you deal with shell-variables you have to get them out of the "sed-string":
For example:
sed -e "s/"${line}"/"${rep}"/g" MasterConfiguration.xml > tempfile
Otherwise sed will treat the chars as-is and search for ${line} literally:
As you see, nothing happens here.
Furthermore, if your variables contain / you need to use another delimiter for sed. I tend to use ~ in such a case, but you're free to use other chars - just be consequent and don't mix them like in your first example-sed-command:
sed 's~'${line}'~'${rep}'/g' //WRONG
sed 's~'${line}'~'${rep}'~g' //RIGHT
Combine both and it will work:
You can try this sed,
sed -i "s#${line}#${rep}#g" MasterConfiguration.xml
Problem:
Instead you have,
sed -i "s|${line}|${rep}/g" MasterConfiguration.xml
It should be,
sed -i "s|${line}|${rep}|g" MasterConfiguration.xml
Syntax:
sed "s|pattern|replacement|g"

Using variable with sed

First of all i apologise in case this has been answered before but i couldn't solve my problem.
I need to search a pattern and then replace it with a line of text comprising of both text and variable.Btw i am using bash..
say
$var = "stacko.ver/rulz=" **Note: $var contain double quotes & = & a dot and /**
i want to so the follow
1.Search for ;te.xt = Note: The value to be search contain ; & = and a dot
2.Replace it with
textnum=$var
Of course $var should be replaced with its actual value
My attempts
sed -i "s/;te.xt =/textnum=$var/" file
sed -i "s/;te.xt =/textnum="$var"/" file
sed -i "s/";te.xt ="/"textnum=$var"/" file
None of these actually worked , either sed giving me an error or the value of $var not shown in file
Thanks for the help
Regards
Quoting doesn't help since this is a sed issue, not a bash issue. Just pick a sed s-expression delimiter that doesn't appear in your text:
sed -i "s|;te.xt =|textnum=$var|" file
You can pick any delimiter for s that doesn't appear in your input. sed -e 'streetlight' is a perfectly valid sed command.
I can see the error:
$ var="stacko.ver/rulz="
$ data="foo ;te.xt = bar"
$ sed "s/;te.xt =/textnum=$var/" <<< "$data"
sed: -e expression #1, char 31: unknown option to `s'
The problem is that $var contains a slash, so sed's s/// command is breaking. You need to pick a character that does not appear in $var
$ sed "s#;te.xt =#textnum=$var#" <<< "$data"
foo textnum=stacko.ver/rulz= bar
This can be hard -- what if slash and hash are in $var? Using bash, you can use ANSI-C quoting to use a control character that is unlikely to appear in your data, e.g.
$ sed $'s\037;te.xt =\037textnum=$var\037' <<< "$data"
foo textnum=stacko.ver/rulz= bar

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