I have a test suite (jUnit, Selenium, Cucumber) Maven project.
I need to be able to run the tests from the command line, passing in different properties files as arguments to diversify the test cases. How can I do this?
I currently have a properties reader that has a path to a shared properties folder concatenated with a variable that holds the name of a given properties file. I'm wondering if that can be parameterized for use with a Maven command in the CLI?
I've been researching this for awhile and have found many questions that sound similar to what I'm trying to achieve, but none of the answers have been applicable to my situation/what I'm trying to do. Any advice, ideas, or resources given will be greatly appreciated.
You can simply pass java properties to Maven:
$ mvn clean test -Dmyproperty=some-property-file.properties
Then you can access the property in your test:
#Test
public void test() {
String propertyFile = System.getProperty("myproperty");
assertEquals("some-property-file.properties", propertyFile);
}
Related
I'm using a TestNG framework for my automation project.
While running from command line i'm giving the following command.
mvn clean test -Dtest=Login,OpenImage,Logout
By running the above command it the order of execution was Login->Logout->OpenImage (may be in alphabetical order).
Can anyone help me how to run tests in the given order.
Note: As per my requirement I need to run my tests in the above way it self.
If it was through testNG.xml file then i guess preserve-order will work.
can anyone help me on this.....!!!!!
Thank you in advance..
First why do you need to run tests in a particula order because units should never rely on a particular order. But your question looks like more an integration tests.
If you need to run in order defined dependencies between the tests
#Test
public void serverStartedOk() {}
#Test(dependsOnMethods = { "serverStartedOk" })
public void method1() {}
The above defines the order that serverStartedOk will run before method1..based on the dependsOnMethods...
I have a SpringBoot application where I have application.properties file outside of project (it's not in usual place src/main/resources).
While building application with gradle clean build, it fails as code is not able to find properties files.
I have tried many command to pass vm args, gradle opts but its not working.
gradle clean build -Djvmargs="-Dspring.config.location=/users/home/dev/application.properties" //not working
It fails on test phase when it creates Spring application context and not able to substitute property placeholders. If I skip test as gradle clean build -x test it works.
Though I can run the app with java -jar api.jar --spring.config.location=file:/users/home/dev/application.properties
Please help how I can pass spring.config.location=/users/home/dev/application.properties in gradle build using command line so that build runs with all Junit tests
If I were you, I would not get involved the actual properties to junit test. So I would create a test properties for the project under src/test/resources/application-test.properties and in junit test I would load the test properties.
Example:
#RunWith(SpringRunner.class)
#SpringBootTest(classes = MyProperties.class)
#TestPropertySource("classpath:application-test.properties")
public class MyTestExample{
#Test
public void myTest() throws Exception {
...
}
}
System properties for running Gradle are not automatically passed on to the testing framework. I presume this is to isolate the tests as much as possible so differences in the environment will not lead to differences in the outcome, unless explicitly configured that way.
If you look at the Gradle API for the Test task, you can see that you can configure system properties through through the systemProperty method on the task (Groovy DSL):
test {
systemProperty "spring.config.location", "/path/to/my/configuration/repository/application.properties"
}
If you also want to read a system property from the Gradle command line and then pass that the test, you have to read it from Gradle first, e.g. as a project property, and then pass that value to the test:
test {
if (project.hasProperty('testconfig')) {
systemProperty 'spring.config.location', project.getProperty('testconfig')
}
}
Run it with gradle -Ptestconfig="/path/to/my/configuration/repository/application.properties" build
However, I would discourage using system properties on the build command line if you can avoid it. At the very least, it will annoy you greatly in the long run. If the configuration file can be in different locations on different machines (depending on where you have checkout out the repository and if it is not in the same relative path to your Spring Boot repository), you may want to specify it in a personal gradle.properties file instead.
I think there is a misunderstanding.
spring.config.location is used at runtime
As you validated:
java -jar api.jar --spring.config.location=file:/users/home/dev/application.properties
spring.config.location is used or required at runtime, not at build time.
When your spring boot app is building, an application.properties is required. An approach could be use an src/main/resources/application.properties with template values, but at runtime you will ignore it spring.config.location=file...
For unit tests
In this case as #nikos-bob said, you must use another properties, commonly inside of your src/test/resources
Environment variables instead external properties
We don't want to have hardcoded values in our main git repository src/main/resources/application.properties so the first idea is use an external properties. But this file must be stored in another git repository (equal to main repository ) or manually created.
Spring and other frameworks give us an alternative: Use environment variables.
So instead of manually external creation of application.properties or store it in our git repository, your spring boot app always must have an application.properties but with environment variables:
spring.datasource.url=jdbc:oracle:thin:#${DATABASE_HOST}:${DATABASE_PORT}:${DATABASE_SID}
spring.datasource.username=${DATABASE_USER}
spring.datasource.password=${DATABASE_PASSWORD}
spring.mail.host = ${MAIL_HOST}
spring.mail.username =${MAIL_USERNAME}
spring.mail.password =${MAIL_PASSWORD}
Advantages:
No manually creation of application.properties allowing us a more easy devops automations
No spring.config.location=file.. is required
I am building an automation framework to test a web application in 2 separate environments namely stage and test.
I am storing environment variables like "user_names" and "application_URL" which are unique to the environments in a property file which is read by the test scripts.
Since I have two different environments, i want to execute the same tests in both of them by having two separate profiles of environment variables files.
I have first environment properties file as below:-
browser = Chrome
admin_Url = https://stage-some-website/login
Username = adminuser1
Password = adminuserpw1
DatabaseURl=""
DatabasePasswords=""
This file is read by below base case which will initialize the browsers and read this property file.
public static WebDriver driver;
public static Properties read_propertyFile;
String PropertyFilePath = "\\src\\test\\java\\com\\resources\\Environment.properties";
If i make another property file for second environment, how can i use it ?
Can i parameterize which property file is being read by the base case and pass the filename or environment name in the command that executes the maven project ?
I want to run the SOAPUI project xmls using Gradle script. The GRADLE script should read the project xmls from soapuiInputs.properties file and run automatically all. Please guide me step by step how to create Gradle script to run the SOAPUI projects in Linux server.
Note: We use SOAPUI version 5.1.2.
Probably the simple way is to call the SOAPUI testrunner directly from gradle as Exec task, like you can do from cli.
In gradle you can define the follow tasks (Note that I try it on windows but to do the same on linux as you ask simply you've to change the paths):
// define exec path
class SoapUITask extends Exec {
String soapUIExecutable = 'C:/some_path/SoapUI-5.2.1/bin/testrunner.bat'
String soapUIArgs = ''
public SoapUITask(){
super()
this.setExecutable(soapUIExecutable)
}
public void setSoapUIArgs(String soapUIArgs) {
this.args = "$soapUIArgs".trim().split(" ") as List
}
}
// execute SOAPUI
task executeSOAPUI(type: SoapUITask){
// simply pass the project path as argument,
// note that the extra " are needed
soapUIArgs = '"C:/location/of/project.xml"'
}
To run this task use gradle executeSOAPUI.
This task simply runs a SOAPUI project, however testrunner supports more parameters which you can pass to soapUIArgs string in executeSOAPUI task, take a look here.
Instead of this if you want to deal with more complex testing there is a gradle plugin to launch SOAPUI project, take a look on it here
Hope this helps,
I am very new to JMeter
I am trying to use Junit Request sampler in JMeter.In my project we have a class called PayloadProcessorTest.java. from these class methods i am calling some other class methods.It has lot of dependencies
How can i create jar file for PayloadProcessorTest.java with dependencies
I saw many examples for JMeter with Junit Request sampler. But, those all examples are independent classes
Can any one please help me
There are several ways of creating a .jar file:
Using Maven
Using Ant
Using Eclipse
.jar files are basically ZIP archives so you can just compile your PayloadProcessorTest.java and put resulting PayloadProcessorTest.class into /lib/junit/test.jar file keeping package structure. After restart JMeter will pick up the class. Don't forget to add any 3rd-party jars used in PayloadProcessorTest (if any) to JMeter classpath. For more information check out How to Use JUnit With JMeter guide.
If you want to get the dependencies with Maven you can run
mvn install dependency:copy-dependencies, which will create a folder inside your target folder called 'dependency' filled with the dependencies. To speed this up you can add the command as External Tool in Eclipse using Run > External Tools > External Tools Configurations.
Or if you want to use Eclipse you can choose File > Export > Java > Runnable JAR file and select the option 'Copy required libraries into a sub folder next to the generated JAR'. However to do this you will need to add a main class, and run it once as a Java Application before trying to export. The Main class can be empty or not.
package test;
public class Main {
public static void main(String[] args) {
}
}
Really, it depends what packaging capabilities you have.
You need to compile your classes in one or more jars, and then put them in the %JMETER_HOME%/lib/ext folder.
Or use maven to do it all for you.