How to get the job_id of the user_id linked to the employee_id
user_id_job = fields.Char(? string='User Job')
i just got the answer
<t t-foreach="request.env['hr.employee'].search([('user_id', '=', user.id)])" t-as="obj">
<t t-esc="obj.job_id.name"/>
</t>
Related
I have 3 table
1- planes = name, description
2- presidents = id , p_name
3- plane_president = plane_id , president_id
how to join planes with presidents and plane_president?
$planes = Plane::join('plane_president', 'planes.id', '=', 'plane_president.plane_id')
->join('presidents', 'presidents.id', '=', 'plane_president.president_id');
error:
SQLSTATE[23000]: Integrity constraint violation: 1052 Column 'id' in order clause is ambiguous (SQL: select * from `planes` inner join `plane_president` on `planes`.`id` = `plane_president`.`plane_id` inner join `presidents` on `presidents`.`id` = `plane_president`.`president_id` order by `id` asc limit 10 offset 0)
plane_president is a pivot table for president and planes, you can declare the relationship at the Plane.php model:
public function presidents()
{
return $this->belongsToMany(
President::class,
'plane_president',
'plane_id',
'president_id');
}
and use it like:
plane->presidents;
when you want to retrieve the presidents for a particular plane in a controller.
You have 2 columns named id as the error says it is ambiguous.
order by id asc limit 10 offset 0 here you aren't specifying by which column to order planes.id or presidents.id
I have three tables in laravel, one is a middle table :
CREATE TABLE orders( id INT(10) PRIMARY KEY NOT NULL AUTO_INCREMENT, order_number VARCHAR(100) NOT NULL );
CREATE TABLE products( id INT(10) PRIMARY KEY NOT NULL AUTO_INCREMENT, title VARCHAR(100) NOT NULL );
CREATE TABLE orders_products ( order_id INT(10) NOT NULL, product_id INT(10) NOT NULL );
I want to retrive the top two orders which have common products, the higher number is irrelevant here,
What counts is that orderC which has 5 orders, 1,3,4,5,7 and orderF which have also 1,2,3,4,5,6,8 so they have 1,3,4,5 in common, this is what I want to have, even if others have one 2,7,9,12,13,15,17,23 and other 2,4,6,8,9,11,12,14,15,16,17 that is not what I want, but the ones have the most products in common
Many Thanks
This is giving inaccurate results:
$orders =
DB::table('orders')
->select('orders.id as ordid', 'orders.order_number as order_number',
DB::raw('COUNT(orders_products.product_id) as counter' ) )
->join('orders_products', 'orders.id', '=', 'orders_products.order_id')
->join('products as prod1', 'prod1.id', '=',
'orders_products.product_id')
->join('products as prod2', 'prod1.id', '=', 'prod2.id')
->groupBy( 'orders.order_number')
->orderByRaw('MAX(orders_products.product_id) DESC')
->limit(2)
->get();
To get the orders with the highest amount of products, you need to use HAVING clause and a subquery to get desired results.
The query below works like this:
First, a subquery (with a nested subquery) finds the highest amount of products in a single order - the highest_amount value
Then a wrapping query finds all orders, that have as many products in order as the highest amount from a subquery.
It would look something like this:
SELECT
orders.id as ordid,
orders.order_number as order_number,
COUNT(orders_products.product_id) as counter
FROM orders
JOIN orders_products ON orders.id = orders_products.order_id
JOIN products ON products.id = orders_products.product_id
GROUP BY orders.order_number
HAVING COUNT(orders_products.product_id) >= (
SELECT MAX(products_in_order) as highest_amount FROM (
SELECT COUNT(orders_products.product_id) as products_in_order
FROM orders
JOIN orders_products ON orders.id = orders_products.order_id
JOIN products ON products.id = orders_products.product_id
GROUP BY orders.order_number
) top_amounts
)
I tested it in this SQL fiddle - it works as expected (you get all orders with the most products - 3 in this case)
I have 3 tables, the 1st has a FK from the 2nd, and the 2nd has a FK from the 3rd:
Table 1: [admin_demandas]
-------------------------
id_demanda| projec_id
-------------------------
Table 2: [admin_projec]
-------------------------
id_projec | sub_id
-------------------------
Table 3: [admin_sub]
-------------------------
id_sub | name
-------------------------
What I need is to get the 'name' from Table 3 but starting with the Model of the table 1.
I was trying something like this:
$data = AdminDemanda::select([
'id_demanda',
'admin_projec.sub_id AS sub_id',
'admin_sub.name AS name',])
->join('admin_projec', 'admin_demandas.projec_id', '=', 'admin_projec.id_projec')
->join('admin_sub', 'admin_projec.sub_id', '=', 'admin_sub.id_sub')
->get();
return Datatables::of($data)->make(true);
I've done my Datatables with only 1 JOIN (2 tables) but not sure how to do those 2 JOIN (3 tables). I got this error:
[Err] 1054 - Unknown column 'admin_projec.sub_id' in 'on clause'
What should I modify in my query?
Should I need to use query builder instead Eloquent, with a DB::raw() query?
Solved with this:
Inner join between three tables in mysql
it was simple... now in case anyone need it, my Datatable query is:
$datos = AdminDemanda::select([
'id_demanda',
'admin_dis.nombre AS nombre_dist',
'admin_sub.nombre AS nombre_subes',
'mes AS mes_demanda',
'admin_sistemas.nombre AS nombre_sistema',
'admin_demandas.demanda_mwh AS mwh'])
->join('admin_projec', 'admin_demandas.proyeccion_demanda_id', '=', 'admin_projec.id_proyeccion_demanda')
->join('admin_sub', 'admin_projec.subestacion_id', '=', 'admin_sub.id_subestacion')
->join('admin_dis', 'admin_projec.dist_id', '=', 'admin_dis.id_dist')
->join('admin_sistemas', 'admin_projec.sistema_id', '=', 'admin_sistemas.id_sistema')
->get();
You should edit your models
By exemple in AdminSub model
public function projec(){
return $this->hasMany(AdminProjec::class , 'sub_id');
}
You should be able to do
\AdminSub::first()->projec();
And continue by editing your AdminProjec model with the same kind of relationship
public function demandas(){
return $this->hasMany(AdminDemandas::class , 'projec_id');
}
And now you could try
//I do not remember which one will works
\AdminSub::first()->projec()->first()->demandas()->name
//or
\AdminSub::first()->projec()->first()->demandas()->get()->name
I have 2 tables that I want to connect
table1:
id
name
table2_id
table_2:
id
name
table1 is connected with table2
When I try to select table1 and the connected row from table2 it works, but because the row names id and name are the same, it overwrites the values of table1.
How can I connect table1 with table2 and get a table1 with this rows in laravel:
id
name
table2_id
table2_name
Review the laravel documentation regarding relationships - If you set up your models as outlined here https://laravel.com/docs/5.3/eloquent-relationships you will be able to call the table2 like:
$result = Table1::find(1)->table2;
However to get the result you want you can use the ->select( function
DB::table('users')->select('name', 'email as user_email')->get();
https://laravel.com/docs/5.2/queries#selects
Something like this
public function scopetable1($query,$id){
return $query = DB::table('table1')
->select('table1.id as id','table1.name as name','table2.id as table2_id', 'table2.name as table2_name' )
->where('table1.id', '=', $id)
->leftJoin('table2', 'table1.table2_id', '=', 'table2.id')
->get();
}
I am trying to to get latest record having the same id. For example
I have table
ID | Created_at
1 |2016-04-26
1 |2016-04-20
1 |2016-04-18
2 |2016-04-27
2 |2016-04-19
I want to get result like this
ID | Created_at
1 |2016-04-26
2 |2016-04-27
How do I do this in Laravel? I was only able to order the record by descending order. Don't know how to pick the latest record of each ID. Thank you.
Try using Collections service from laravel , and use last() method. Example:
$data = ModelName::all();
$last_data_object = collect($data)->last();
//try to see the object using var_dump()
var_dump($last_data_object);
I get it from https://laravel.com/docs/5.2/collections#method-last
You can try with whereRaw to getting last records in groupBy laravel
$data = Table::whereRaw('Created_at IN (select MAX(Created_at) FROM table GROUP BY ID)')->get();
Try it this way, it will give you the max grouped ID which will be the latest:
SELECT MAX(ID), Created_at
FROM table
GROUP BY ID, Created_at
Thank you everyone for help. I was able to solve this by
DB::raw("SELECT ID,created_at FROM <table name> a WHERE created_at=(SELECT max(created_at) FROM <table name> b WHERE a.ID=b.ID)
DB::raw('SELECT * FROM `test` WHERE 1 GROUP BY `ID` ORDER BY `Created_at` ASC');
Try this
Include the directive Db
$id = DB::table('your_table')->orderBy('id', 'desc')->value('id');
If you have user_id.
$id = DB::table('your_table')->where('user_id', $user_id)->orderBy('id', 'desc')->value('id');