I wish to write a bash script such that it launches Symfony built-in Web Server, hence Firefox. The following simple minded script fails because - I am not sure how to describe it by the correct jargon - the shell gets busy by the first task. I guess it is simple, but I am newbie on this. Thanks.
#!/bin/bash
cd /var/www/mySymfonyProj
php bin/console server:run localhost:8080
/usr/bin/firefox http://localhost:8080
(moved comment to answer in order to "resolve" the question).
Add an & after the 4th line of the script to run that process in the background - the shell will launch that process, and move onto the next line (but will wait for the 5th line's command to finish).
At the end of the script, you may want to call wait to wait for the server to terminate, if that's desired.
#!/bin/bash
cd /var/www/mySymfonyProj
php bin/console server:run localhost:8080 &
/usr/bin/firefox http://localhost:8080
wait
For more information on job control, look at this source. It doesn't cover everything useful, but it covers a fair amount.
I'd mention that $! returns the PID of the process just executed, so you can keep track of the PIDs of various background tasks then use wait to delay until they've returned - that's often useful.
Related
I need to have a bash script triggered and run, but part of the script requires Apache to restart. This obviously kills the script from continuing. I can't move the restarts in the script to the end
I have tried to run the bash scrip though a php script using shell_exec() in a GNU screen session to keep it going but that doesn't work. as soon as Apache goes down the script stops.
There has to be a way to do this but I'm not seeing it.
How I can accomplish this?
Does nohup do the job?
nohup is a POSIX command which means "no hang up". Its purpose is to execute a command such that it ignores the HUP (hangup) signal and therefore does not stop when the user logs out.
Output that would normally go to the terminal goes to a file called nohup.out, if it has not already been redirected.
https://en.wikipedia.org/wiki/Nohup
I need to develop a client and server program with using sockets. My program should get port number from the command line. I saw an example which says "myprogram 2454 &".
I wonder what that & (ampersand) means there.
It means to start the process in the background. http://tldp.org/LDP/abs/html/x9644.html so that you may continue to use your shell session to run other programs. You can then use fg to "foreground" your process again.
The ampersand (&) means that you want to run myprogram in background. This is normally used when you want to stay on your command-prompt and continue the work on the same session.
Example
somescript &
will run the somescript shell script in background. You will get the prompt back on the next line. If you run somescript without & then the prompt may not appear back because somescript may take more time.
The best way is to run it in background with no hangups, in which case even of you loose your connection to the host the process keeps running on the UNIX or Linux host.
For example
nohup somescript &
the jobs command will display the jobs running in background.
Ive got a script that takes a quite a long time to run, as it has to handle many thousands of files. I want to make this script as fool proof as possible. To this end, I want to check if the user ran the script using nohup and '&'. E.x.
me#myHost:/home/me/bin $ nohup doAlotOfStuff.sh &. I want to make 100% sure the script was run with nohup and '&', because its a very painful recovery process if the script dies in the middle for whatever reason.
How can I check those two key paramaters inside the script itself? and if they are missing, how can I stop the script before it gets any farther, and complain to the user that they ran the script wrong? Better yet, is there way I can force the script to run in nohup &?
Edit: the server enviornment is AIX 7.1
The ps utility can get the process state. The process state code will contain the character + when running in foreground. Absence of + means code is running in background.
However, it will be hard to tell whether the background script was invoked using nohup. It's also almost impossible to rely on the presence of nohup.out as output can be redirected by user elsewhere at will.
There are 2 ways to accomplish what you want to do. Either bail out and warn the user or automatically restart the script in background.
#!/bin/bash
local mypid=$$
if [[ $(ps -o stat= -p $mypid) =~ "+" ]]; then
echo Running in foreground.
exec nohup $0 "$#" &
exit
fi
# the rest of the script
...
In this code, if the process has a state code +, it will print a warning then restart the process in background. If the process was started in the background, it will just proceed to the rest of the code.
If you prefer to bailout and just warn the user, you can remove the exec line. Note that the exit is not needed after exec. I left it there just in case you choose to remove the exec line.
One good way to find if a script is logging to nohup, is to first check that the nohup.out exists, and then to echo to it and ensure that you can read it there. For example:
echo "complextag"
if ( $(cat nohup.out | grep "complextag" ) != "complextag" );then
# various commands complaining to the user, then exiting
fi
This works because if the script's stdout is going to nohup.out, where they should be going (or whatever out file you specified), then when you echo that phrase, it should be appended to the file nohup.out. If it doesn't appear there, then the script was nut run using nohup and you can scold them, perhaps by using a wall command on a temporary broadcast file. (if you want me to elaborate on that I can).
As for being run in the background, if it's not running you should know by checking nohup.
I just wrote my first bash script to start some redis instances on a development server. While it is mostly working, the last opened redis instance is blocking the active terminal – though I have the trailing & sign and the other started instances aren't blocking the terminal. How would I push them all to the background?
Here's the script:
#!/bin/bash
REDIS=(6379 6380 6381 6382 6383 6390 6391 6392 6393)
for i in "${REDIS[#]}"
do
:
redis-server --port $i &
done
It sounds like your terminal is not actually blocked, your prompt just got overwritten. It's a purely cosmetic issue. Due to the way terminals work, bash doesn't know to redraw it so it looks like the command is in the foreground.
Run the script again, and blindly type lsEnter. You'll probably see that the shell responds as normal, even though you can't see the prompt.
You can alternatively just hit Enter to get bash to redraw the prompt.
I have a master-workers architecture where the number of workers is growing on a weekly basis. I can no longer be expected to ssh or remote console into each machine to kill the worker, do a source control sync, and restart. I would like to be able to have the master place a message out on the network that tells each machine to sync and restart.
That's where I hit a roadblock. If I were using any sane platform, I could just do:
exec('ruby', __FILE__)
...and be done. However, I did the following test:
p Process.pid
sleep 1
exec('ruby', __FILE__)
...and on Windows, I get one ruby instance for each call to exec. None of them die until I hit ^C on the window in question. On every platform I tried this on, it is executing the new version of the file each time, which I have verified this by making simple edits to the test script while the test marched along.
The reason I'm printing the pid is to double-check the behavior I'm seeing. On windows, I am getting a different pid with each execution - which I would expect, considering that I am seeing a new process in the task manager for each run. The mac is behaving correctly: the pid is the same for every system call and I have verified with dtrace that each run is trigging a call to the execve syscall.
So, in short, is there a way to get a windows ruby script to restart its execution so it will be running any code - including itself - that has changed during its execution? Please note that this is not a rails application, though it does use activerecord.
After trying a number of solutions (including the one submitted by Byron Whitlock, which ultimately put me onto the path to a satisfactory end) I settled upon:
IO.popen("start cmd /C ruby.exe #{$0} #{ARGV.join(' ')}")
sleep 5
I found that if I didn't sleep at all after the popen, and just exited, the spawn would frequently (>50% of the time) fail. This is not cross-platform obviously, so in order to have the same behavior on the mac:
IO.popen("xterm -e \"ruby blah blah blah\"&")
The classic way to restart a program is to write another one that does it for you. so you spawn a process to restart.exe <args>, then die or exit; restart.exe waits until the calling script is no longer running, then starts the script again.