Using Laravel eloquent how do I make a query like this:
select * from branches where user_id =(select id from users where name ='sara' )
Assuming that you have a user relationship in your Branch model you could use whereHas:
$branches = Branch::whereHas('user', function ($query) {
$query->where('name', 'sara');
})->get();
Update
If you're using v8.57.0 or above, you can now use the whereRelation() method instead:
Branch::whereRelation('user', 'name', 'sara')->get();
$id = Users::select('id')->where('name','sara')->first();
$barnches = branches::where('id',$id)->get();
Here Users and branches are models , first is using for 1 row and get for many rows
I would split it into two queries. First getting the id, then getting the list. Expecting your models to be called "User" and "Branches"
$user = User::where('name', 'sara');
$id = $user->id;
$branches = Branch::where('id', $id);
This site may help you Link
Try this.
$name = 'sara';
$results = BranchModel::whereIn("user_id", function ($query) use ($name) {
$query->select("id")
->from((new UserModel)->getTable())
->where("name", $name);
})->get();
You can use this:
$users = User::whereName("sara")->get()->pluck('id');
Branch::whereIn('user_id',$users)->get();
Related
I want to filter replies based on query parameter passed, query parameters can be post_id, comment_id and array of reply_ids all can be optional and can be used as combination
$query = Post::where('user_id', auth()->id());
if ( isset($data['reply_ids']) ) {
$query = $query->with('posts.comments.replies')->whereHas('posts.comments.replies', function($query) use ($data){
$query->whereIn('id', $data['reply_ids']);
});
}
Now, if I want to filter again with comment authors, that is on comments table, if I want to add filters of post author, that will be on posts table, how I can add those conditional, and still that will be optional?
Just add another if statements below. Those will be optional, sice you define your $query before your first filtering action.
I needed to use another eager loading with so that the query will be build on all the combination selected, so the final code will be something like
$query = Post::where('user_id', auth()->id());
if ( isset($data['reply_ids']) ) {
$query = $query->with('posts.comments.replies')->whereHas('posts.comments.replies', function($query) use ($data){
$query->whereIn('id', $data['reply_ids']);
});
}
$query = $query->with(['posts' => function($query){ $query->where('status', 'pending'); }])
$query->get()
Trying to get this query to work in eloquent
A user can be in multiple teams however I want to generate a list of users NOT in a specific team. The following SQL query works if executed directly but would like to make it cleaner by converting it to eloquent
SELECT * FROM users LEFT JOIN team_members ON team_members.member_id = users.id WHERE NOT EXISTS ( SELECT * FROM team_members WHERE team_members.member_id = users.id AND team_members.team_id = $team_id )
This should provide a list of all the users that are not members of team $team_id
This is a guess ad you do not give much info on your Eloqent models but here is a hint of where to go:
User::doesnthave('teamMembers', function($builder) use($team_id){
return $builder->where('team_members.team_id');
});
That is assuming you have a "User" model with a "teamMembers" relationship setup on it
You may have a closer look in the Laravel docs for doesntHave
Laravel 5.8
Let's assume you have model name "User.php"
& there is method name "teamMembers" in it.
Basic
$users = User::doesntHave('teamMembers')->get();
Advance
use Illuminate\Database\Eloquent\Builder;
$users = User::whereDoesntHave('teamMembers', function (Builder $query) {
$query->where('id', '=', {your_value});
})->get();
You can find details description in this link >>
https://laravel.com/docs/5.8/eloquent-relationships#querying-relationship-absence
Laravel 5.2
Example:
DB::table('users')
->whereExists(function ($query) {
$query->select(DB::raw(1))
->from('orders')
->whereRaw('orders.user_id = users.id');
})
->get();
Check this link for advance where clause:
https://laravel.com/docs/5.2/queries#advanced-where-clauses
You can use below example
$list = User::leftJoin('users', 'users.id', '=', 'team_members.member_id')
->whereNotExists(function ($query) use ($team_id) {
$query->from('team_members')
->whereRaw('team_members.member_id = users.id')
->where('team_members.team_id', '=', $team_id);
})
->get();
I am learning larvel 5.6 so I am trying to retrieve number of messages that have id larger than last_seen_id in pivot table
I have user table which have the default columns generated by:
php artisan make:auth
and messages tables which have the following columns:
id, from, message_content, group_id
and the group table have the columns:
id,type
now there is many to many relation between the users and groups table through the custom pivot table which have the columns:
group_id,user_id,last_id_seen
now if I want to retrieve the messages which belong to same group and have larger id than last_id_seen in the pivot table how to do it?
I think you are looking for something like this:
$groupId = 1; // set to whatever you want
$lastSeenId = \Auth::user()->groups()
->where('group_id', $groupId)
->first()->pivot->last_id_seen;
$messages = Message::where('id', '>', $lastSeenId)->get();
A more robust version, which does not fail when your user does not have an entry for the group yet, would be:
$groupId = 1; // set to whatever you want
$group = \Auth::user()->groups()->where('group_id', $groupId)->first();
$lastSeenId = $group ? $group->pivot->last_id_seen : null;
$messages = Message::when($lastSeenId, function($query, $id) {
$query->where('id', '>', $id);
})->get();
Note: normally you'd use optional() in the second snippet, but Laravel 5.2 does not come with this helper...
If you want both the count() of the results and the results themselves, you can store the query in a variable and perform two queries with it. You then don't have to rewrite the same query twice:
$groupId = 1; // set to whatever you want
$group = \Auth::user()->groups()->where('group_id', $groupId)->first();
$lastSeenId = $group ? $group->pivot->last_id_seen : null;
$query = Message::when($lastSeenId, function($query, $id) {
$query->where('id', '>', $id);
});
$count = $query->count();
$messages = $query->get();
i have three table in mysql:
1-users
table of users
2-projects
table of project
3-project_user
there is id and project_id and user_id for relation
there is two model : user and project
the relation between these table are belongsToMany
when a project create maybe one project define for two person
NOW how can i show the project of each person?
Assuming you properly defined your relationships, do
$users = User::with('projects')->get();
//show each user projects
foreach($users as $user) {
echo $user->projects;
}
//Getting project users
$projects = Project::with('users')->get();
This will give you projects list, in each list you can see which user has access or not.
Updates
Taking project with specified user_id
$projects = Project::with(['users' => function ($query) use ($user_id) {
$query->where('user_id', '=', $user_id);
}])->get();
New code
Or try to to get the user
$user = User::with('projects')->where('id', $user_id)->first();
Or via projects, constraining by user_id
$projects = Project::with('users')->whereHas('users', function ($query) use ($user_id) {
$query->where($user_id);
})->get();
the way i solve it:
//save user_id
$user_id = $request->id;
//select in project_user where user_id = $user_id
$project_user = DB::table('project_user')->where('user_id', '=', $user_id)->get();
//create an empty array
$p_id = array();
//fill empty array with project_id
foreach($project_user as $pro) {
$p_id[] = $pro->project_id;
}
//select code and id in project table where id = one of that [$p_id] array
$data = Project::select('code','id')->whereIn('id', $p_id)->get();
//return your data in json
return response()->json($data);
As far as I understood your question, you want to query Project as per user_id. Here is how you do it.
Project::with('users')->whereHas('users', function ($query) use ($user_id_array) {
$query->whereIn('id',$user_id_array);
})->get();
This will give you projects whose user_id are from $user_id_array. Let me know if you need any further help.
I have a code:
$response = $this->posts
->where('author_id', '=', 1)
->with(array('postComments' => function($query) {
$query->where('comment_type', '=', 1);
}))
->orderBy('created_at', 'DESC')
->limit($itemno)
->get();
And when I logged this query with:
$queries = \DB::getQueryLog();
$last_query = end($queries);
\Log::info($last_query);
In log file I see follow:
"select * from `post_comments` where `post_comments`.`post_id` in (?, ?, ?, ?) and `comment_type` <> ?"
Why is the question mark for comment_type in the query?
Update #1:
I replaced current code with following and I get what I want. But I'm not sure it is OK. Maybe exists many better, nicer solution.
$response = $this->posts
->where('author_id', '=', 1)
->join('post_comments', 'post_comments.post_id', '=', 'posts.id')
->where('comment_type', '=', 1)
->orderBy('created_at', 'DESC')
->limit($itemno)
->get();
Behind the scene the PDO is being used and it's the way that PDO does as a prepared query, for example check this:
$title = 'Laravel%';
$author = 'John%';
$sql = "SELECT * FROM books WHERE title like ? AND author like ? ";
$q = $conn->prepare($sql);
$q->execute(array($title,$author));
In the run time during the execution of the query by execute() the ? marks will be replaced with value passed execute(array(...)). Laravel/Eloquent uses PDO and it's normal behavior in PDO (PHP Data Objects). There is another way that used in PDO, which is named parameter/placeholder like :totle is used instead of ?. Read more about it in the given link, it's another topic. Also check this answer.
Update: On the run time the ? marks will be replaced with value you supplied, so ? will be replaced with 1. Also this query is the relational query, the second part after the first query has done loading the ids from the posts table. To see all the query logs, try this instead:
$queries = \DB::getQueryLog();
dd($queries);
You may check the last two queries to debug the queries for the following call:
$response = $this->posts
->where('author_id', '=', 1)
->with(array('postComments' => function($query) {
$query->where('comment_type', '=', 1);
}))
->orderBy('created_at', 'DESC')
->limit($itemno)
->get();
Update after clarification:
You may use something like this if you have setup relation in your Posts model:
// $this->posts->with(...) is similar to Posts::with(...)
// if you are calling it directly without repository class
$this->posts->with(array('comments' =. function($q) {
$q->where('comment_type', 1);
}))
->orderBy('created_at', 'DESC')->limit($itemno)->get();
To make it working you need to declare the relationship in your Posts (Try to use singular name Post if possible) model:
public function comments()
{
return $this->hasmany('Comment');
}
Your Comment model should be like this:
class Comment extends Eloquent {
protected $table = 'post_comments';
}