The background of my problem is that I want to extract the video data of Motion Photos (taken by my Samsung S7). Manually it is easy but time consuming. Just open the .jpg file in a HexEditor and extract all data after the line "MotionPhoto_Data". The first part is the image and the second part is the video.
My current code is
im = 'test.jpg'
with open(im, 'rb') as fin:
data = fin.read()
data_latin = data.decode('latin1')
fin.close()
position = data_latin.find('MotionPhoto_Data')
data_pic = data[:position]
data_mpg = data[position:]
My problem now is that I can´t figure out how to save these strings in a way that data_pic is saved as a working jpg and data_mpg as a working video.
I tried
with open('test_pic.jpg', 'a') as fin:
fin.write(str(data_pic))
fin.close()
But this didn´t worked. I think there is a basic issue on how I try to handle/save my data but I can´t figure out how to fix this.
I assume you use python 3 as it is tagged that way.
You should not decode with 'data.decode('latin1'). It is binary data.
data = fin.read()
Then later write it also as binary data:
with open('test_pic.jpg', 'ab') as fout:
fout.write(data_pic)
fout.close()
Related
I'm experimenting with pysox and trying to simply convert a WAV file to GSM.
I'm currently using the following approach which works just fine:
infile = pysox.CSoxStream("input_file.wav")
outfile = pysox.CSoxStream('output_file.gsm','w',infile.get_signal())
chain = pysox.CEffectsChain(infile, outfile)
chain.flow_effects()
outfile.close()
I wonder if there's a better/builtin way without using effects (as i'm not applying any effects) .
thanks in advance
I found that i actually must use libsox effect as i'm changing the rate :
chain.add_effect(pysox.CEffect("rate", ["8k"]))
Without adding this line the output appears in slow motion (since my original file can have different rate)
Using python 3.4 in linux and windows, I'm trying to create qr code images from a list of string objects. I don't want to just store the image as a file because the list of strings may change frequently. I want to then tile all the objects and display the resulting image on screen for the user to scan with a barcode scanner. For the user to know which code to scan I need to add some text to the qr code image.
I can create the list of image objects correctly and they are in a list and calling .show on these objects displays them properly but I don't know how to treat these objects as a file object to open them. The object that is given to the open function, (img_list[0] in my case), in my add_text_to_img needs to support read, seek and tell methods. When I try this as is I get an attribute error. I've tried BytesIO and StringIO but I get an error message that Image.open does not support buffer interface. Maybe I am not doing that part correctly.
I'm sure there are several ways to do this, but what is the best way to open in memory objects as a file object?
from io import BytesIO
import qrcode
from PIL import ImageFont, ImageDraw, Image
def make_qr_image_list(code_list):
"""
:param code_list: a list of string objects to encode into QR code image
:return: a list of image or some type of other data objects
"""
img_list = []
for item in code_list:
qr = qrcode.QRCode(
version=None,
error_correction=qrcode.ERROR_CORRECT_L,
box_size=4,
border=10
)
qr.add_data(item)
qr_image = qr.make_image(fit=True)
img_list.append(qr_image)
return img_list
def add_text_to_img(text_list, img_list):
"""
While I was working on this, I am only saving the first image. Once
it's working, I'll save the rest of the images to a list.
:param text_list: a list of strings to add to the corresponding image.
:param img_list: the list containing the images already created from
the text_list
:return:
"""
base = Image.open(img_list[0])
# img = Image.frombytes(mode='P', size=(164,164), data=img_list[0])
text_img = Image.new('RGBA', base.size, (255,255,255,0))
font = ImageFont.truetype('sans-serif.ttf', 10)
draw = ImageDraw.Draw(text_img)
draw.text((0,-20),text_list[0], (0,0,255,128), font=font)
# include some method to save the images after the text
# has been added here. Shouldn't actually save to a file.
# Should be saved to memory/img_list
output = Image.alpha_composite(base,text_img)
output.show()
if __name__ == '__main__':
test_list = ['AlGaN','n-AlGaN','p-AlGaN','MQW','LED AlN-AlGaN']
image_list = make_qr_image_list(test_list)
add_text_to_img(test_list, image_list)
im = image_list[0]
im.save('/my_save_path/test_image.png')
im.show()
Edit: I've been using python for about a year and I feel like this is a pretty common thing to do but I'm not even sure that I'm looking up/searching for the right terms. What topics would you search for to answer this? If anyone can post a link or two to what I need to read up on regarding this, that would be very appreciated.
You already have PIL image objects; qr.make_image() returns the (a wrapper around) the right type of object and you do not need to open them again.
As such, all you need to do is:
base = img_list[0]
and go from there.
You do need to match image modes when compositing; QR codes are black-and-white images (mode 1), so either convert that or use the same mode in your text_img image object. The Image.alpha_composite() operation does require that both images have an alpha channel. Converting the base is easy:
base = img_list[0].convert('RGBA')
I am trying to read a RAW16 image in MATLAB. After going through another question here on StackOverflow, I figured I could read it like reading a file and then doing some simple matrix transposes. However, I am running into a weird problem. The image below is what I am getting. I do not understand why this overlap exists and am not entirely sure how to solve the issue. Could someone help?
Code:
fin = fopen('raw13.raw','r');
ima = fread(fin, [col*2 row],'uint8');
temp = zeros(col,row);
j=1;
for i=1:2:col*2-1
temp(j,:) = ima(i,:) + ima(i+1,:)*2^8; %The first element is the lower 8bits and the second element is the higher 8bits
j = j+1;
end
imshow(temp',[0 2^16-1])
In case anyone is having the same problem as me.
It seems the .RAW file that I obtained was somehow corrupted. Using a lower version of the FlyCapture program resulted in a better RAW file and the code that I used worked like a charm
I use col*3 in line 3 and line 5, then it displays the image well.
but i use 8 bit raw image form pointgray camera,and i dont know 'imshow(temp',[0 2^16-1])' would work...
I have a folder of jpg files and I want to make them into a movie. I am using this script:
% Create video out of list of jpgs
clear
clc
% Folder with all the image files you want to create a movie from, choose this folder using:
ImagesFolder = uigetdir;
% Verify that all the images are in the correct time order, this could be useful if you were using any kind of time lapse photography. We can do that by using dir to map our images and create a structure with information on each file.
jpegFiles = dir(strcat(ImagesFolder,'\*.jpg'));
% Sort by date from the datenum information.
S = [jpegFiles(:).datenum];
[S,S] = sort(S);
jpegFilesS = jpegFiles(S);
% The sub-structures within jpegFilesS is now sorted in ascending time order.
% Notice that datenum is a serial date number, for example, if you would like to get the time difference in hours between two images you need to subtract their datenum values and multiply by 1440.
% Create a VideoWriter object, in order to write video data to an .avi file using a jpeg compression.
VideoFile = strcat(ImagesFolder,'\MyVideo');
writerObj = VideoWriter(VideoFile);
% Define the video frames per second speed (fps)
fps = 1;
writerObj.FrameRate = fps;
% Open file for writing video data
open(writerObj);
% Running over all the files, converting them to movie frames using im2frame and writing the video data to file using writeVideo
for t = 1:length(jpegFilesS)
Frame = imread(strcat(ImagesFolder,'\',jpegFilesS(t).name));
writeVideo(writerObj,im2frame(Frame));
end
% Close the file after writing the video data
close(writerObj);
(Courtesy of http://imageprocessingblog.com/how-to-create-a-video-from-image-files/)
But it gives me this error:
Warning: No video frames were written to this file. The file may be invalid.
> In VideoWriter.VideoWriter>VideoWriter.close at 289
In Movie_jpgCompilation at 37
I'm sure my jpg files are fine, and they are in the folder I specify. What is the problem?
(This is my first post ever, so I hope it helps).
If you're on Linux, don't the backslashes need to be forward slashes? When I ran it on my Mac, my jpegFiles was an empty Struct. When I changed them around it worked:
% Create video out of list of jpgs
clear
clc
% Folder with all the image files you want to create a movie from, choose this folder using:
ImagesFolder = uigetdir;
% Verify that all the images are in the correct time order, this could be useful if you were using any kind of time lapse photography. We can do that by using dir to map our images and create a structure with information on each file.
jpegFiles = dir(strcat(ImagesFolder,'/*.jpg'));
% Sort by date from the datenum information.
S = [jpegFiles(:).datenum];
[S,S] = sort(S);
jpegFilesS = jpegFiles(S);
% The sub-structures within jpegFilesS is now sorted in ascending time order.
% Notice that datenum is a serial date number, for example, if you would like to get the time difference in hours between two images you need to subtract their datenum values and multiply by 1440.
% Create a VideoWriter object, in order to write video data to an .avi file using a jpeg compression.
VideoFile = strcat(ImagesFolder,'/MyVideo.avi');
writerObj = VideoWriter(VideoFile);
% Define the video frames per second speed (fps)
fps = 1;
writerObj.FrameRate = fps;
% Open file for writing video data
open(writerObj);
% Running over all the files, converting them to movie frames using im2frame and writing the video data to file using writeVideo
for t = 1:length(jpegFilesS)
Frame = imread(strcat(ImagesFolder,'/',jpegFilesS(t).name));
writeVideo(writerObj,im2frame(Frame));
end
% Close the file after writing the video data
close(writerObj);
Edit: You can also use filesep so that the file separator is OS-specific. http://www.mathworks.com/help/matlab/ref/filesep.html
It would be simpler to use Windows Movie Maker [windows] or iMovie [mac]. For your purposes though you should use PowerPoint.
This problem has bugged me for a while.
I have a jpeg file that is 34.6 kilobytes. Let's call it Image A. Using Ruby, when I copy each line of Image A to a newly created file, called Image B, it is copied exactly. It is exactly the same size as Image A and is accessible.
Here is the code I used:
image_a = File.open('image_a.jpg', 'r')
image_b = File.open('image_b.jpg', 'w+')
image_a.each_line do |l|
image_b.write(l)
end
image_a.close
image_b.close
This code generates a perfect copy of image_a into image_b.
When I try to copy Image A into Image B, byte by byte, it copies successfully but the file size is 88.9 kilobytes rather than the 34.6 kilobytes. I can't access Image B. My mac system alerted me it may be damaged or is using a file format that isn't recognized.
The related code:
//same as before
image_a.each_byte do |b|
image_b.write(b)
end
//same as before
Why is Image B, when copied into byte by byte, larger than Image A? Why is it also damaged in some way, shape, or form? Why is Image A the same size as B, when copied line by line, and accessible?
My guess is the problem is an encoding issue. If so, Why does encoding format matter when copying byte by byte if they translate into the correct code points? Are code points jumbled up into each other so the parser is unable to differentiate between them?
Do \s and \n matter? It seems like it. I did some more research and I found that Image A had 128 lines of code whereas Image B had only one line.
Thanks for reading!
IO#each_byte iterates over bytes (aka Integers). IO#write, however, takes a string as an argument. So it converts the integer to a string via to_s.
Given the first byte in your image is 2551, you'd write the string "255" into image_b. This is why your image_b gets larger. You write number-strings into it.
Try the following when writing back bytes:
image_a.each_byte do |l|
image_b.write l.chr
end
1 As #stefan pointed out jpeg images start with FF D8. So the first byte is 255.