Run a bash command and split the output by line not by space - bash

Question

I want to run the following command and get the output in the variable splited in an array by line not by space:
files=$( hdfs dfs -ls -R $hdfsDir)
So the output I get is the following: echo $files
drwxr-xr-x - pepeuser supergroup 0 2016-05-27 15:03 /user/some/kpi/2015/01/02 -rw-r--r-- 3 pepeuser supergroup 55107934 2016-05-27 15:02 /user/some/kpi/2015/01/02/part-00000902148 -rw-r--r-- 3 pepeuser supergroup 49225279 2016-05-27 15:02 /user/some/kpi/2015/01/02/part-00001902148
When I do a for in $files in stead of getting the full line on each., I get the column in stead of the line. It prints like the following:
drwxr-xr-x
-
pepeuser
supergroup
and what I need on the for to print like this:
drwxr-xr-x - pepeuser supergroup 0 2016-05-27 15:03 /user/some/kpi/2015/01/02
-rw-r--r-- 3 pepeuser supergroup 55107934 2016-05-27 15:02 /user/some/kpi/2015/01/02/part-00000902148
-rw-r--r-- 3 pepeuser supergroup 49225279 2016-05-27 15:02 /user/some/kpi/2015/01/02/part-00001902148

Answer 1

If you have bash 4, you can use readarray:
readarray -t files < <(hdfs dfs -ls -R "$hdfsDir")
Otherwise, use read -a to read into an array. IFS=$'\n' sets the field separator to newlines and -d '' tells it to keep reading until it hits a NUL character: effectively, that means it'll read to EOF.
IFS=$'\n' read -d '' -r -a files < <(hdfs dfs -ls -R "$hdfsDir")
You can verify that the array is populated correctly with something like:
printf '[%s]\n' "${files[#]}"
And can loop over the array with:
for file in "${files[#]}"; do
echo "$file"
done