I have a doubt in Oracle SQl, I have to pick the earliest record based on date ranges. I have table A with
NAME.A SHOPNO YEAR.A shop key
XX 123 2013 1
YY 345 2013 2
I have table b with two columns .
SHOPNO NUMBER.B NAME.B INSERT_DATE.B
1 987 ZZ 7/13/2013
2 456 ZZ 12/1/2013
My resulting output should be
NAME.A SHOPNO YEAR.A NUMBER.B NAME.B
XX 123 2013 987 ZZ
Please let me know how it can be achieved in oracle sql
See this answer from a duplicate question for a more efficient solution using rank(). But here's the basic/simple way to do what you want.
select a.name, a.shopno, a.year, b.number, b.name
from a
join b on a.shopno = b.shopno
and b.insert_date = (select min(insert_date) from b b2
where b2.shopno = b.shopno);
Related
I have a table abc as:
acc subgroup
720V A
720V A
720V A
720V A
111 C
222 D
333 E
My expected output is:
acc subgroup
720V A
111 C
222 D
333 E
Since 720V A is duplicate i want to delete all three duplicate data and only want one data in my table.
So,i tried
DELETE FROM (
select t.*,rownum rn from abc t where acc='720V') where rn>1;
So,I get error as:
ORA-01732: data manipulation operation not legal on this view
How i can get my expected output?
Your table seems to be lacking a primary key column, which is a big problem here. Assuming there actually is a primary key column PK, we can try using ROW_NUMBER to identify any "duplictes":
DELETE
FROM abc t1
WHERE pk IN (SELECT pk
FROM (
SELECT t.pk, ROW_NUMBER() OVER (PARTITION BY acc, subgroup ORDER BY pk) rn
FROM abc t) x
WHERE rn > 1
);
Note that if you can live with keeping your original data, then the most expedient thing to do might be to create a distinct view:
CREATE VIEW abc_view AS
SELECT DISTINCT acc, subgroup
FROM abc;
I did search the forum before posting this and found some topics which were close to the same issue but I still had questions so am posting it here.
EMP_ID SEQ_NR NAME
874830 3 JOHN
874830 4 JOE
874830 21 MIKE
874830 22 BILL
874830 23 ROBERT
874830 24 STEVE
874830 25 JERRY
My output should look like this.
EMP ID SEQ3NAME SEQ4NAME SEQ21NAME SEQ22NAME SEQ23NAME SEQ24NAME SEQ25NAME
874830 JOHN JOE MIKE BILL ROBERT STEVE JERRY
SELECT A.EMP_ID
,A.NAME SEQ3NAME
,B.NAME SEQ4NAME
FROM AC_XXXX_CONTACT A
INNER JOIN AC_XXXX_CONTACT B ON A.EMP_ID = B.EMP_ID
WHERE A.SEQ_NR = '03' AND B.SEQ_NR = '04'
AND B.EMP_ID = '874830';
The above query helped me get the below results.
EMP_ID SEQ3NAME SEQ4NAME
874830 JOHN JOE
My question is to get all the fields(i.e till seq nr = 25) should I be joining the table 5 more times.
Is there a better way to get the results ?
I m querying against the Oracle DB
Thanks for your help.
New Requirement
New Input
STU-ID SEM CRS-NBR
12345 1 100
12345 1 110
12345 2 200
New Output
stu-id crs1 crs2
12345 100 200
12345 110
Not tested since you didn't provide test data (from table AC_XXXX):
(using Oracle 11 PIVOT clause)
select *
from ( select emp_id, seq_nr, name
from ac_xxxx
where emp_id = '874830' )
pivot ( max(name) for seq_nr in (3 as seq3name, 4 as seq4name, 21 as seq21name,
22 as seq22name, 23 as seq23name, 24 as seq24name, 25 as seq25name)
)
;
For Oracle 10 or earlier, pivoting was done "by hand", like so:
select max(emp_id) as emp_id, -- Corrected based on comment from OP
max(case when seq_nr = 3 then name end) as seq3name,
max(case when seq_nr = 4 then name end) as seq4name,
-- etc. (similar expressions for the other seq_nr)
from ac_xxxx
where emp_id = '874830'
;
Or, emp_id doesn't need to be within max() if we add group by emp_id - which then will work even without the WHERE clause, for a different but related question.
I have two tables affiliation and customer, in that i have data like this
aff_id From_cus_id
------ -----------
1 10
2 20
3 30
4 40
5 50
cust_id cust_aff_id
------- -------
10
20
30
40
50
i need to update data for cust_aff_id column from affiliation table which is aff_id like below
cust_id cust_aff_id
------- -------
10 1
20 2
30 3
40 4
50 5
could u please give reply if anyone knows......
Oracle doesn't have an UPDATE with join syntax, but you can use a subquery instead:
UPDATE customer
SET customer.cust_aff_id =
(SELECT aff_id FROM affiliation WHERE From_cus_id = customer.cust_id)
merge into customer t2
using affiliation t1 on (t1.From_cus_id =t2.cust_id )
WHEN MATCHED THEN
update set t2.cust_aff_id = t1.aff_id
;
Here is an update with join syntax. This, quite reasonably, works only if from_cus_id is primary key in the first table and cust_id is foreign key in the second table, referencing the first table. Without these conditions, the requirement doesn't make much sense in the first place anyway... but Oracle requires that these constraints be stated explicitly in the tables. This is also reasonable on Oracle's part IMO.
update
( select t1.aff_id, t2.cust_aff_id
from affiliation t1 join customer t2 on t2.cust_id = t1.from_cus_id) j
set j.cust_aff_id = j.aff_id;
I need to analyse abnormal returns for an event study on mergers and acquisitions.
** I would like to analyse abnormal returns to acquirers by using event windows. Basically I would like to extract the prices for the acquirers using -1 (the day before the announcement date), announcement date, and +1 (the day after the announcement date).**
I have two different datasets to extract information from.
The first is a dataset with all the merger and acquisition information that has the information in the following format:
DealNO AcquirerNO TargetNO AnnouncementDate
123 abcd Cfgg 22/12/2010
222 qwert cddfgf 26/12/1998
In addition, I have a 2nd dataset which has all the prices.
ISINnumber Date Price
abcd 21/12/2010 10
abcd 22/12/2010 11
abcd 23/12/2010 11
abcd 24/12/2010 12
qwert 20/12/1998 20
qwert 21/12/1998 20
qwert 22/12/1998 21
qwert 23/12/1998 21
qwert 24/12/1998 21
qwert 25/12/1998 22
qwert 26/12/1998 21
qwert 27/12/1998 23
ISIN number is the same as acquirer no, and that is the matching code.
In the end I would like to have a database something like this:
DealNO AcquirerNO TargetNO AnnouncementDate Acquirerprice(-1day) Acquireeprice(0day) Acquirerprice(+1day)
123 abcd Cfgg 22/12/2010 10 11 12
222 qwert cddfgf 26/12/1998 22 21 23
Do you know how I can get this?
I'd prefer to use sas to run the code, but if you are familiar with any other programs that can get the data like this, please let me know.
Thank you in advance ^_^.
This can be done quite easily with PROC SQL and joining the PRICE dataset three times. Try this (assuming data set names of ANNOUCE and PRICE):
Warning: untested code
%let day='21DEC2010'd;
proc sql;
create table RESULT as
select a.dealno,
a.acquirerno,
a.targetno,
a.annoucementdate,
p.price as acquirerprice_prev,
c.price as acquirerprice_cur,
n.price as acquirerprice_next
from ANNOUCE a
left join (select * from PRICE where date = &day-1) p on a.acquirerno = p.isinumber
left join (select * from PRICE where date = &day) c on a.acquirerno = c.isinumber
left join (select * from PRICE where date = &day+1) n on a.acquirerno = n.isinumber
;
quit;
Let's say I have table data similar to the following:
123456 John Doe 1 Green 2001
234567 Jane Doe 1 Yellow 2001
234567 Jane Doe 2 Red 2001
345678 Jim Doe 1 Red 2001
What I am attempting to do is only isolate the records for Jane Doe based upon the fact that she has more than one row in this table. (More that one sequence number)
I cannot isolate based upon ID, names, colors, years, etc...
The number 1 in the sequence tells me that is the first record and I need to be able to display that record, as well as the number 2 record -- The change record.
If the table is called users, and the fields called ID, fname, lname, seq_no, color, date. How would I write the code to select only records that have more than one row in this table? For Example:
I want the query to display this only based upon the existence of the multiple rows:
234567 Jane Doe 1 Yellow 2001
234567 Jane Doe 2 Red 2001
In PL/SQL
First, to find the IDs for records with multiple rows you would use:
SELECT ID FROM table GROUP BY ID HAVING COUNT(*) > 1
So you could get all the records for all those people with
SELECT * FROM table WHERE ID IN (SELECT ID FROM table GROUP BY ID HAVING COUNT(*) > 1)
If you know that the second sequence ID will always be "2" and that the "2" record will never be deleted, you might find something like:
SELECT * FROM table WHERE ID IN (SELECT ID FROM table WHERE SequenceID = 2)
to be faster, but you better be sure the requirements are guaranteed to be met in your database (and you would want a compound index on (SequenceID, ID)).
Try something like the following. It's a single tablescan, as opposed to 2 like the others.
SELECT * FROM (
SELECT t1.*, COUNT(name) OVER (PARTITION BY name) mycount FROM TABLE t1
)
WHERE mycount >1;
INNER JOIN
JOIN:
SELECT u1.ID, u1.fname, u1.lname, u1.seq_no, u1.color, u1.date
FROM users u1 JOIN users u2 ON (u1.ID = u2.ID and u2.seq_no = 2)
WHERE:
SELECT u1.ID, u1.fname, u1.lname, u1.seq_no, u1.color, u1.date
FROM users u1, thetable u2
WHERE
u1.ID = u2.ID AND
u2.seq_no = 2
Check out the HAVING clause for a summary query. You can specify stuff like
HAVING COUNT(*) >= 2
and so forth.