I am trying to pass 2 different columns from my sql table to my view ,so that i can show them.
My controller is:
$interface = DB::table("users")->distinct()->get(['name']);
$interfac = DB::table("users")->distinct()->get(['email']);
view()->share('users',compact('interface','interfac'));
My view is :
#foreach ($users as $key => $value)
<tr>
<td>{{ $value->name }}</td>
<td>{{ $value->email }}</td>
</tr>
But this is not working while passing the two variables.If i pass one it is working but passing two is not working.thanks.
Controller
$users = DB::table('users')->get();
return view('users', compact('users'));
Related
I have two tables. One employees and one timesheets
I would like to have correct name at the result but different ID. If you see the result I have the same name everywhere.
How can make the code to fixed my challenge?
Thank you.
In controller I have this code
$profile = ['no' => Auth::user()->no];
$timesheets = Timesheet::where($profile)->select('*')->orderBy('created_at','DESC')->get();
foreach ($timesheets as $employee) {
$emp = ['identification' => $employee->identification];
$oneemployee = Employees::where($emp)->select('*')->orderBy('created_at','DESC')->get();
}
return view('contractor.employees.timesheets', compact('timesheets', 'oneemployee'));
and in blade I have
#foreach ($timesheets as $row1)
<tr>
<td>#</td>
#foreach ($oneemployee as $row2)
<td>{{ $row2->fname}}</td>
<td>{{ $row2->lname}}</td>
#endforeach
<td>{{ $row1->identification}}</td>
<td>{{ $row1->week}}</td>
<td>{{ $row1->year}}</td>
</tr>
#endforeach
According to your commit, I suggest the following solution
If you want dispay timesheet with employees you can use eager loading.
For example:
In your controller:
$profile = ['no' => Auth::user()->no];
$timesheets = Timesheet::where($profile)->with("employees")->select('*')->orderBy('created_at','DESC')->get();
return view('contractor.employees.timesheets', compact('timesheets'));
In your Timesheet model add hasOne relation to Employee:
public function employee(){
return $this->hasOne(Employee::class,'identification','identification')
}
And your view:
#foreach ($timesheets as $timesheet)
<tr>
<td>#</td>
<td>{{ $timesheet->employee->fname}}</td>
<td>{{ $timesheet->employee->lname}}</td>
<td>{{ $timesheet->identification}}</td>
<td>{{ $timesheet->week}}</td>
<td>{{ $timesheet->year}}</td>
</tr>
#endforeach
I have an sql table knowledgebase like so
id , categoryid, title
id
categoryid
title
1
1
apple
2
1
fb
3
2
google
4
2
DB
5
3
Reebok
In my laravel blade, I am trying to create a tree view to look like the following
-1
--apple
--FB
-2
--google
--DB
-3
--Reebok
My controller does a basic query and returns the entire table to the view. I am a newbie to laravel so far, I can get a basic table to work like
#foreach($knowledgebase as $key => $value)
<tr>
<td>{!! $knowledgebase ->id !!}</td>
<td>{!! $knowledgebase ->title!!}</td>
<td>{!! $knowledgebase ->categoryid !!}</td>
</tr>
#endforeach
How would I iterate categroyid column , display first category and all child titles and then move on to the next categoryid.
Update
public function show($id) {
//get article
$knowledgebase = \App\Models\Knowledgebase::Where('knowledgebase_slug', request('knowledgebase_slug'))->first();
return view('knowledgebase', compact('knowledgebase'));
}
You will need to retrieve in controller the categories before ($categories)
#foreach($categories as $category)
<tr>
<td>{{ $category->id }}</td>
<td>{{ $category->title}}</td>
<td>{{ $category->categoryid }}</td>
</tr>
#endforeach
Anyways, I managed to solve this by adding a function children in my model. So in my Model added
public function children(){
return $this->hasMany('App\Models\Knowledgebase', 'categoryid');
}
After this, I simply called it as a foreach inside my foreach
#foreach($categories as $category)
<li>{{ $category->title}}</li>
#if($category->children)
#foreach($category->children as $child)
<ul>
<li class="pl-3"> {{ $child->title}} </li>
</ul>
#endforeach
#endif
#endforeach
I wrote a query to pass parameter from view to controller, and I got this error:
Undefined property: Illuminate\Database\MySqlConnection::$username
View Passing the parameter
<td width="25%"><a class="btn btn-info" href="{{ route('gamesListDetail',$game->id) }}">{{ $game->name }}</a></td>
Receiving Controller
public function gamesListDetail($id = null)
{
$gamelists = DB::table("platform_games")
->select("platform_games.id", "platform_games.username","game_player.game_id")
->join("game_player","game_player.game_id","=","platform_games.id")
->where('platform_games.id',$id)
->take(5);
return view('soccerrave.games.gamesListDetail', compact('gamelists'));
}
Receiving View
<tbody>
#foreach($gamelists as $key => $gamelist)
<tr>
<td>{{ ++$key }}</td>
<td>{{ $gamelist->username }}</td>
</tr>
#endforeach
<tr>
<td colspan="8">
{{ $gamelists->links() }}
</td>
</tr>
</tbody>
I expect the view to display top 5 data based on the parameter. But I got this error:
Undefined property: Illuminate\Database\MySqlConnection::$username
Documentation says:
skip / take
To limit the number of results returned from the query, or to skip a
given number of results in the query, you may use the skip and take
methods:
$users = DB::table('users')->skip(10)->take(5)->get();
So by example we see that after take method there must be get() call.
So fix Your code:
public function gamesListDetail($id = null)
{
$gamelists = DB::table("platform_games")
->select(
"platform_games.id",
"platform_games.username",
"game_player.game_id"
)
->join(
"game_player",
"game_player.game_id", "=", "platform_games.id"
)
->where('platform_games.id', $id)
->take(5)
->get(); // this one is required
return view('soccerrave.games.gamesListDetail', compact('gamelists'));
}
I want to display two variable data on same view in a foreach loop
public function getWalletList()
{
$data = Data::orderBy('id','desc')->get()->toArray();
$user_ids = array_column($data, 'id');
$user_data = User::whereIn('id',$user_ids)->get()->toArray();
$d= array('data'=>$data,'user'=>$user_data);
return view('wallet_list', compact('d'));
}
So how to diplay data on laravel blade template
#foreach($d as $value)
<tr>
<td>{{$value['wallet']['name']}}</td>
<td>{{$value->user_id}}</td>
<td>{{$value->price}}</td>
<td>{{$value->price}}</td>
<td>{{$value->updated_at}}</td>
</tr>
#endforeach
why dont you use two foreach ?
#foreach($d as $value)
<tr>
<td>{{$value['wallet']['name']}}</td>
<td>{{$value->user_id}}</td>
<td>{{$value->price}}</td>
<td>{{$value->price}}</td>
<td>{{$value->updated_at}}</td>
</tr>
#endforeach
#foreach($b as $value)
<tr>
<td>{{$value['wallet']['name']}}</td>
<td>{{$value->user_id}}</td>
<td>{{$value->price}}</td>
<td>{{$value->price}}</td>
<td>{{$value->updated_at}}</td>
<tr>
#endforeach
I have a for each loop to iterate over the collection of records. It has the user_id, but not the other user credentials. I created another collection of user. How do I include this in my iteration?
Controller
public function index(Request $request, $id)
{
$thoughts = Thought::where('id', $id)->orderBy('created_at', 'desc')->paginate(100)->get();
$user = User::where('id', $thoughts->user_id);
return view('backend.pages.thought_list', compact('thoughts, user'));
}
View
#foreach ($thoughts as $thought)
<tr>
<td class="col-md-1">{{ $user->username}} <span class="user_id_thought">ID - {{ $user->user_id}}</span></td>
<td class="col-md-1">{{ $thought->response }}</td>
<td>{{ $thought->thought_type }}</td>
<td>{{ $thought->id }}</td>
</tr>
#endforeach
How do I display my users variable in the loop. Or is there a better way of doing this.
Eager Loading is the perfect use case for your requirement in my opinion.
e.g.
$thoughts = Thought::with('user')->get();
foreach ($thoughts as $thought) {
echo $thought->user->name;
}
For more details see: https://laravel.com/docs/5.6/eloquent-relationships#eager-loading