I have folder "destination/" and inside the destination folder, it contains executable grade1. My current directory is "destination/"
I'm Trying to run
for i in FILES/*; do ./grade1 $i done
Which it keep says
./grade1 no such file or directory
Weird part is that, when I just copy the code to command line and run it, it works fine. Problem only arises when I do it in shell script
I don't think that grade1 really is in your current working directory, as you claim. I suggest that you verify this also check the permissions of your executable. Extend your code to
echo current directory is $PWD
ls -l grade1
for i in FILES/*; do ./grade1 $i done
This should reveal the source of your problem.
One simple way to fix this problem might be to start using FULL path of grade1 executable file
for i in FILES/*; do {FULL_PATH}/grade1 $i done
Related
I am on Windows.
I have a script file named basics.sh and here is what it contains:
cd opt-out-exam/abduvosid_malikov/IT
mkdir made_by_my_script
cd made_by_my_script
echo "Hello World" > hello.txt
so basically, basics.sh script file is responsible to:
go to folder opt-out-exam/abduvosid_malikov/IT
make a directory made_by_my_script
create hello.txt file with content Hello World
Right now. to execute this basics.sh script, I am going to IT folder and writing this command in the terminal:
./basics.sh
In order to execute this basics.sh script, is it compulsory for me to go to IT folder
OR
is it possible to execute this script file even if I am staying in another folder (lets say currently working directory is opt-out-exam)
The first line is a change directory command followed by a relative path, not absolute. In such cases, it is important where you run the script. (An absolute path would start with the filesystem root, i. e. /.)
If you run this script from a directory (I wouldn't call it a folder in this context) where the relative path opt-out-exam/abduvosid_malikov/IT does not exist, it won't cd into it. But it will make a new directory without any problem, it will also create the file and write a line into it.
So only the first line will fail if it's run somewhere else.
UPD: As Gordon Davisson pointed out, this means that you want to check whether the directory change actually took place or not.
Below is my .sh file
sh summaryByClient.sh $1 - takes around 10 mins to fetch the required data
mv summary.html ~/public_html/chats/ - **this is not happening**
exit 0
I do not understand why mv summary.html ~/public_html/chats/ this is not working inside .sh file, However I am able to mv separately using the same above command.
Could you be running into the issue from this answer with expanding the user's home directory? What happens if you write your script like this:
#!/bin/bash
# Other tasks to retrieve summary.html done here
mv ./summary.html $HOME/public_html/chats/
exit 0
Also, it's always a good idea to check whether the destination directory exists before a mv command. Examples are shown in this answer
I am very new to bash and using .sh files. I am trying to run the program aescrypt by calling it in a .sh file as follows (aescrypt is in the same directory as the .sh file) :
./aescrypt -e -p password file.txt
It throws the following error:
./aescrypt no such file or directory
Am I doing it wrong?
ps- I realy don't want to add it to the PATH variable as I will be using this on more than one computer that resets every day.
The location of the script is irrelevant. The thing that matters is the working directory of the process executing the script. The simplest solution really is to add aescrypt to a standard location like /bin or /usr/bin. If neither of those is acceptable, perhaps /usr/local/bin is an option. Otherwise, just use the full path of aescrypt in your script. Either hard code it, or if it is in the same directory as the script, try:
$(dirname $0)/aescrypt ...
(Note that hardcoding is more reliable, but less flexible. If you move the executable, the script will break. But using dirname will break if the script changes directory during execution.)
how about if you call the program like ./aescrypt.sh, thats the way to call an .sh programm througt the terminal
First off all, you have also to change the permissions of the file to make it executable, the way to make that is to write in the terminal, the command:
sudo chmod 765 aescrypt.sh
For that you have to be located where the file is
I am new to unix and am practicing a simple script to unzip a load of files within a specified directory. I need the program to move the zipped file into another folder when it is done unzipping it (I called this oldzipped folder). For simplicity, I have removed the part of the code unzipping the file and currently have the program working for a specific file rather than the *tar.7z file extention. For some reason, the mv statement is not working. Unix is saying the following when I try to run the script. Could someone give me a hand with this? Again, I know this is the long way of doing things, but I want practice writing a script. Please be nice, as I am very new to Unix :(
unzip5: line 14: [ASDE0002.tar.7z]: command not found
#!~/bin/bash
# My program to try to unzip several files with ending of tar.7z
# I have inserted the ability to enter the directory where you want this to be done
echo "What file location is required for unzipping?"
read dirloc
cd $dirloc
mkdir oldzippedfiles
for directory in $dirloc
do
if
[ASDE0002.tar.7z]
then
mv -f ASDE0002.tar.7z $dirloc/oldzippedfiles
fi
done
echo "unzipping of file is complete"
exit 0
[ is the name of a (sometimes built-in) command which accepts arguments. As such you need to put a space after it as you would when invoking any other program. Also, you need a test. For example, to determine if the file exists and is a file, you need to use -f:
if [ -f ASDE0002.tar.7z ]
then
mv -f ASDE0002.tar.7z $dirloc/oldzippedfiles
fi
Here are some other possible tests.
First off I am very very new to shell scripting. I am trying to write a script that takes in one parameter and then copies a folder in a different directory naming it using the parameter. This is the current code that I have:
#!/bin/sh
cd /var/www/html/fbplugin/chrome
sudo mkdir temp/$1
sudo cp -rf "/var/www/html/fbplugin/chrome/fbplugin" "/var/www/html/fbplugin/chrome/temp/$1"
When I run this code it says can't cd to /var/www/html/fbplugin/chrome. I'm not sure why it is saying this because I know the directory exists. I have copied the line directly and it works in terminal. If anyone could help me out that would be great.
If it matters in order to run the script I am typing "sh build.sh"
If that directory really exists, then you must have executed that script with a different user (cron, webserver, etc).
Check the rights for that directory.
I don't know why you're getting the error about cd, but it looks like you could just use absolute paths throughout. That would solve the larger problem of the script working correctly.