combine Date and Time into a DateTime from api response - ruby

What is the efficient way to combine Date and Time (strings) into a single DateTime? i am using football-api in response i am getting time attribute in "08:50" these format and date attribute "01.01.2018" these format. I want to save in database 2018-01-01 08:50:00 format in date field.
a = match["formatted_date"].to_date.strftime("%Y, %m, %d")
y = a[0..3].to_i
m = a[6..7].to_i
d = a[10..11].to_i
date = Date.new(y, m, d).to_datetime + Time.parse(match["time"]).seconds_since_midnight.seconds

Related

Unable to process Timeseries data in PIG

I have timeseries data eg: 2018-10-12 01:25:37 and extracted date(2018-10-12) and time(1:25:37) from timestamp. Now requirement is to filter the time values based on a particular condition(eg:filter the time value with another bag's atom, which contains time data(hh:mm:ss)). The PIG has no 'TIME' datatype for time(hh:mm:ss) type data.
What datatype is required to load 'time' data values in PIG?
To extract date (year, month,hr's, minutes etc). used these function
For year: GetYear()
For month: GetMonth()
For day: GetDay()
For hour: GetHour()
For minute: GetMinute()
date.txt
2018-10-12 11:15:43
2018-10-12 12:25:12
A = load 'date.txt' as (in:chararray);
B = foreach A generate ToDate(in,'yyyy-MM-dd HH:mm:ss') as (dt:DateTime);
C = foreach B {
year = GetYear(dt);
month = GetMonth(dt);
day = GetDay(dt);
hour = GetHour(dt);
minute = GetMinute(dt);
//finally you can concatenate year month and day or hour, time using CONCAT function
};

Fetch date and time in xamarin forms

I have to fetch hours and minutes from time format I am getting from the system however it is showing me error like int month= moment.Month;
DateTime productDate = DateTime.Now;
string twentyFourHourFormatHour =int.Parse(productDate.ToString("HH")).ToString();
Not picking up productdate when trying to store it in string (line 2)
DateTime has properties to expose all of the data you need. There is no need to do elaborate string manipulation.
DateTime date = DateTime.Now();
int hour = date.Hour;
int minute = date.Minute;

Swift DateFormatter Extract Time

I've been trying to return a date with just Time. I tried DateFormatter, but will always retrieve a full date for some reason.
//Declare Date Formatter 1
let dateFormatter1 = DateFormatter()
dateFormatter1.dateFormat = "yyyy-MM-dd HH:mm:ss"
//Declare Date Formatter 2
let dateFormatter2 = DateFormatter()
dateFormatter2.dateFormat = "hh:mm"
//Retrieve date and set to proper date for DateFormatter
var date: Date = dateFormatter1.date(from: "2017-11-28 10:47:30")!
//Set String date to time format with dateFormatter2
let dateString = dateFormatter2.string(from: item)
//Reseting dateFormatter1 for to only use time (could be ambiguous)
dateFormatter1.dateFormat = "hh:mm"
//Set date to Date
date = dateFormatter1.date(from: dateString)!
print("String: \(dateString)")
print("Date: \(date)")
Output:
String: 10:47
Date: 2000-01-01 15:47:00 +0000
- timeIntervalSinceReferenceDate : -31565580.0
I want the Date: to be 10:47
Is this even possible?
No, it is not possible. The Variable date is of type Date which has full date information within it. When showing it in string format you can convert it as you want, but while storing in the variable of type Date it stores the full information.

How to find date lies in which week of month

Suppose I have a date in year-month-day format. Say "2015-02-12". Now I want to find that in which week this date lies. I mean 12 lies in 2nd week of Funerary. I want if I fo something like
LocalDate date = 2015-02-12;
date.getWeekOfMoth should gives me 2 because 2 lies in 2nd week of February. How can i do it ?
Thanks
Edit
Hi, I am so sorry. I should replied you before you asked. I tried with the following code
String input = "2015-01-31";
SimpleDateFormat df = new SimpleDateFormat("w");
Date date = df.parse(input);
Calendar cal = Calendar.getInstance();
cal.setTime(date);
int week = cal.get(Calendar.WEEK_OF_MONTH);
System.out.println(week);
It prints 2.
While when I check with the following code
String valuee="2015-01-31";
Date currentDate =new SimpleDateFormat("yyyy-MM-dd").parse(valuee);
System.out.println(new SimpleDateFormat("w").format(currentDate));
It prints 5.
Try this one. Remember to feed it with your date format and string with this date as input.
SimpleDateFormat df = new SimpleDateFormat(format);
Date date = df.parse(input);
Calendar cal = Calendar.getInstance();
cal.setTime(date);
int week = cal.get(Calendar.WEEK_OF_MONTH);

Date format in D3.js

I have a column (date) in csv which stores the date in "2003-02-01"(y-m-d). I would like to format the date in month and year like Apr 2003. how do i do that?
var format = d3.time.format("%m-%Y");
data.forEach(function(d,i) {
d.date = format(d.date);
});
I am getting the following error Error: TypeError: n.getFullYear is not a function Line: 5
the csv file contains values:
200,300,400,288,123,2003-01-01
300,700,600,388,500,2003-02-01
what is the issue here?
Javascript doesn't automatically recognize the values in the CSV file as dates, just reading them in as strings. d3's time functions make it pretty easy to convert them to datetime objects:
> parseDate = d3.time.format("%Y-%m-%d").parse
> parseDate('2003-01-01')
Wed Jan 01 2003 00:00:00 GMT-0600 (Central Standard Time)
To format the dates like you want, we need to go the other way, from a date object to a string:
> formatDate = d3.time.format("%b-%Y")
> formatDate(parseDate('2003-01-01'))
"Jan-2003"
I would recommend representing your dates within your program with date objects and only formatting them as strings when you need to display them.
D3 version 4 has different time methods now.
https://keithpblog.org/post/upgrading-d3-from-v3-to-v4/
https://github.com/d3/d3/blob/master/CHANGES.md
Your source date
var d = {created_time : "2018-01-15T12:37:30+0000"}
The structure of that date = %Y-%m-%dT%H:%M:%S%Z
I search google with "2018-01-15T12:37:30+0000" and it's suggestions provided the date structure string. Handy.
Create a timeParser to convert(parse) your date string into a date object
var parseDate = d3.utcParse("%Y-%m-%dT%H:%M:%S%Z")
//parseDate(d.created_time)
Now create a time formatter to return a formated date string for displaying.
var formatDate = d3.timeFormat("%b-%Y")
return formatDate(parseDate(d.created_time))
i.e.
Jan-1970
from Adam answer, here is a small helper function to convert a time string from a format to another:
var formatTime = function(input, formatInput, formatOutput){
var dateParse = d3.time.format(formatInput).parse;
var dateFormat = d3.time.format(formatOutput);
return dateFormat(dateParse(input));
};
use:
formatTime("2003-01-01", "%Y-%m-%d", "%b-%Y");
// output -> "Jan-2003"
if you are getting date lets say in variable " d = (e.g: '2003-03-01')" in string format then,
var monthNameFormat = d3.time.format("%b-%Y");
return monthNameFormat(new Date(d));
this will result date in "Jan-2003" format.
In D3Js v3, this worked for me:
var s = "2018-11-01T19:37:55Z";
d3.time.format("%Y-%m-%dT%H:%M:%SZ").parse(s);
// Thu Nov 01 2018 19:37:55 GMT-0700 (Pacific Daylight Time)

Resources