File upload with in Spring MVC without adding any additional parameter in controller method - spring

Question

I am using spring boot 2. My new task is file uploading. I already did it. But I am asked to do it without adding a additional parameter to controller method like #RequestParam("files") MultipartFile files[]. I want to get this from request instead of adding this parameter.
How can I solve this?
I am adding my current code following.
#RequestMapping(value="/uploadMultipleFiles", method=RequestMethod.POST)
public #ResponseBody String handleFileUpload( #RequestParam("files") MultipartFile files[]){
try {
String filePath="c:/temp/kk/";
StringBuffer result=new StringBuffer();
byte[] bytes=null;
result.append("Uploading of File(s) ");
for (int i=0;i<files.length;i++) {
if (!files[i].isEmpty()) {
bytes = files[i].getBytes();
BufferedOutputStream stream = new BufferedOutputStream(new FileOutputStream(new File(filePath+files[i].getOriginalFilename())));
stream.write(bytes);
stream.close();
result.append(files[i].getOriginalFilename() + " Ok. ") ;
}
else
result.append( files[i].getOriginalFilename() + " Failed. ");
}
return result.toString();
} catch (Exception e) {
return "Error Occured while uploading files." + " => " + e.getMessage();
}
}

Answer 1

You can get files from HttpRequest:
#RequestMapping(value="/uploadMultipleFiles", method=RequestMethod.POST)
public String handleFileUpload(HttpRequest request){
MultipartHttpServletRequest multipartRequest = (MultipartHttpServletRequest) request;
Map<String, MultipartFile> yourFiles = multipartRequest.getFileMap();
return "All is Ok!";
}

Answer 2

My sample code.
#RequestMapping(value = "/multiple/upload", method = RequestMethod.POST)
public #ResponseBody String test(#RequestParam(value = "files[]") List<MultipartFile> files,
HttpServletRequest req) {
MultipartFileWriter writer = new MultipartFileWriter();
String folderPath = "/file/";
for (MultipartFile file : files) {
writer.writeFile(file, folderPath, req);
}
return "success";
}