I have a directory, lets say DirA. There is a subdirectory called DirB and some files in DirA. Now, when I use the Gradle task to delete only the subdirectory (DirB), it is deleting the files also. I don't want it to delete the files. Can anyone please help me achieve this?
task deleteFolder(type: Delete){
delete "full path of subdirectory relative to build.gradle location"
}
With the following structure:
.
└── dira
├── a
├── b
├── c
└── dirb
and script:
task clearDirA(type: Delete) {
delete project.file('dira/dirb')
}
Related
I encountered a problem with gradle project structure. I have a task that needs to be realized and some tests are meant to be executed to check whether my project structure is correct and the tasks in gradle execute correctly. However I think I misunderstood instruction a bit and I'm wondering whether I can do something with my current folders structure or If I will have to rewrite the whole project. My current project structure looks like this:
main-repo-folder/
├── docker-related-file
├── rootProject
│ ├── sub-project-1
│ ├── build(output from tasks is created here)
│ ├── build.gradle
│ ├── sub-project-2
│ ├── gradle
│ ├── gradlew
│ ├── gradlew.bat
│ ├── settings.gradle
│ └── src
As you can see, the root project is a directory inside a repo. In order for my tests to execute I think the repo itself must be a root folder (or act as one) because the tests seem to be trying executing there. And here is my question, is it possible to add f.e settings.gradle file in main-repo-folder (at the same level as rootProject folder) to "point" gradle to build from rootProject and treat that folder as the root?(I mean f.e if I call gradle clean build task_name in main-repo-folder I want to make gradle execute it as I would be in rootProject folder)
I've tried to find some information but I'm at the path of learning gradle and I don't know if it is even possible :/ .
Rename main-repo-folder/rootProject to main-repo-folder.
I am creating a script.sh file that creates a Test.swift file and adds it into a Xcode project. However, I would like to know if there is a way to add this file to Xcode (in the project.pbxproj file) from this script? Instead of doing it manually in Xcode (Add files to Project...).
Thank you
3/05 Update
I tried #Johnykutty answer, here is my current Xcode project before executing the ruby script:
I have already generated a A folder with a Sample.swift file located in test, but these files are not linked to my Xcode project yet:
Now here is the script that I'm executing:
require 'xcodeproj'
project_path = '../TestCodeProjTest.xcodeproj'
project = Xcodeproj::Project.open(project_path)
file_group = project["TestCodeProjTest"]["test"]
file_group.new_file("#{project.project_dir}/TestCodeProjTest/test/A")
project.save()
This almost works fine, except that it creates a folder reference instead of a group, and it doesn't link it to my target:
Hence the content of Sample.swift is unreachable.
Its hard to achieve by bash. But really easy if you use Ruby and xcodeproj gem from Cocoapods
Consider you have file structure like
├── GeneratedFiles
│ └── Sample1.swift
├── MyProject
│ ├── AppDelegate.swift
│ ├── ... all other files
│ ├── SceneDelegate.swift
│ └── ViewController.swift
├── MyProject.xcodeproj
│ ├── project.pbxproj
│ ├── .....
└── add_file.rb
Then you can add files like
require 'xcodeproj'
project_path = 'MyProject.xcodeproj'
project = Xcodeproj::Project.open(project_path)
file_group = project["MyProject"]
file_group.new_file("../GeneratedFiles/Sample1.swift")
project.save()
UPDATE:
project["MyProject"] returns a file group which is a group named MyProject in the root of the project, you can select another group inside MyProject by file_group = project["MyProject"]["MyGroup"]
Then the generated file path should be either related to that group like file_group.new_file("../../GeneratedFiles/Sample1.swift") or full path like file_group.new_file("#{project.project_dir}/GeneratedFiles/Sample1.swift")
More details about Xcodeproj here
I want to include a specific version of Gradle in the project folder so that when I use the Gradle wrapper it doesn't download it from the remote repository.
I downloaded the version of Gradle I need (gradle-4.0-bin.zip) and I put that zip fine inside of gradle/wrapper/ folder of the project (created with the gradle wrapper command).
Then I edited the gradle-wrapper.properties file in this way:
distributionUrl=file:///Users/pathj/to/the/project/gradle/wrapper/gradle-4.0-bin.zip
But when I run the first command, such as gradle task it returns:
What went wrong: A problem occurred configuring root project '03-gradle-wrapper-local'.
java.io.FileNotFoundException: /Users/myself/.gradle/wrapper/dists/gradle-4.0-bin/3p92xsbhik5vmig8i90n16yxc/gradle-4.0/lib/plugins/gradle-diagnostics-4.0.jar
(No such file or directory)
How do I tell Gradle to get the zip file from the current project folder, with a relative path, instead of downloading it, and to use that zip file to create a wrapper to be used in my builds?
Apart from storing gradle wrapper locally make sense or not it is possible. I assume that gradle-4.0-rc-3-bin distro is used.
Here is the project structure:
.
├── gradle
│ └── wrapper
│ ├── gradle-4.0-rc-3-bin.zip
│ ├── gradle-wrapper.jar
│ └── gradle-wrapper.properties
├── gradlew
└── gradlew.bat
And here the content of gradle-wrapper.properties:
distributionBase=PROJECT
distributionPath=gradle
zipStoreBase=GRADLE_USER_HOME
zipStorePath=wrapper/dists
distributionUrl=gradle-4.0-rc-3-bin.zip
Since wrapper files will be downloaded to the project dir adding gradle/gradle-4.0-rc-3-bin to SCM ignore file is recommended.
Demo can be found here.
Hi I am newbie to gradle script, I am trying to copy directory to root directory of war file, but I ended up copying only the contents of the folder to root directory, but I want the whole directory structure with parent directory also to be copied.
Folder structure to copy
polymer-client
├── file1.txt
├── index.html
Gradle script
apply plugin: 'war'
war {
archiveName = 'WebDeployment.war'
from 'polymer-client'
}
Generated folder structure
WebDeployment
├── WEB-INF
├── META-INF
├── file1.txt
├── index.html
Expected folder structure
WebDeployment
├── WEB-INF
├── META-INF
├── polymer-client
├── file1.txt
├── index.html
Please let me know, how to get it done with gradle script.
You can try to do it with into as follows:
apply plugin: 'war'
war {
archiveName = 'WebDeployment.war'
into 'polymer-client', {
from 'polymer-client'
}
}
It should create the polymer-client subdirectory within war-archive and copy all the content of the polymer-client directory into it.
I am trying to copy a file in gradle and rename it at the same time, where the new name of the file should be dependent of the name of the subfolder it was in.
My file structure looks like this for example:
├── apk
│ └── app-envTest-normalBuild-release.apk
├── logs
│ └── manifest-merger-envTest-normalBuild-release-report.txt
└── mapping
└── envTestNormalBuild
└── release
├── dump.txt
├── mapping.txt
├── seeds.txt
└── usage.txt
I'd like to copy the mapping.txt and rename it. The new name should be mapping-envTestNormalBuild.txt - i.e. should include the name of the subdirectory it was released in.
Can someone tell me if/how this is possible using the gradle copy+rename feature?
I have seen that the reverse is possible, i.e. copying a file like foo-bar.txt to a directory/path foo/bar.txt and similar.
You can try e.g.:
task clean {
doLast {
project.file('dest').deleteDir()
}
}
task cp(type: Copy) {
dependsOn clean
from 'mapping/envTestNormalBuild/release'
into 'dest'
include 'mapping.txt'
eachFile { fcp ->
fcp.name = "$fcp.file.parentFile.parentFile.name-$fcp.name"
}
}
A demo can be found here.