How to extract substring data from Json response using JMeter - jmeter

My Json response is:
"return":"/info?booking=KD6YGS4L8I"
Now I want to extract value after "=" (ex:"KD6YGS4L8I").
I used Regular Expression extractor:
- Regular Expression: "return":"(.+?)"
- Template: $1$
- Match No: -1
And output is:
"return":"/info?booking=KD6YGS4L8I"
Now I want to get string KD6YGS4L8I.

You can use the following regular expression: booking=(.+?)", with template $1$. Match Number (n) depends on your needs:
n > 0: matches the given occurence number,
n == 0: matches a random occurence,
n < 0: matches all occurences, and organizes them with subvariables.
See Regular Expression Extractor on JMeter website.
I suggest you to take a look at the following guides:
Regular Expressions,
how to use JMeter Regexp Extractor.

Add a Beanshell sampler as a sibling to your Regular Expression Extractor with the below code:
//Assuming your regular expression extractor variable is RegExpResult
String regExpResponse= ${RegExpResult};
String[] result= regExpResponse.split("=");
result[1].replaceAll("\"", "");
vars.put("BookingValue",result[1]);
Now BookingValue variable contains - KD6YGS4L8I
You can find the same issue been resolved in stackoverflow:
JMeter - using substring on a user variable
Hope this helps! :)

Related

From the regular expression extractor using -1 for getting all matches, and from that how to choose the last one as a match in jmeter

Whatever may to the total number of matching outcomes
If your variable is a use __V for getting last occurrence using
${__V(a_${a_matchNr})}
or __evalVar
${__evalVar(a_${a_matchNr})}
a_matchNr return last number
refName_matchNr - the number of matches found; could be 0
As per Regular Expression Extractor documentation:
If the match number is set to a negative number, then all the possible matches in the sampler data are processed. The variables are set as follows:
refName_matchNr - the number of matches found; could be 0
refName_n, where n = 1, 2, 3 etc. - the strings as generated by the template
refName_n_gm, where m=0, 1, 2 - the groups for match n
refName - always set to the default value
refName_gn - not set
So the total number of matches is being stored in ${refName_matchNr} JMeter Variable
If you want to get the last match dynamically you can use __V() function like:
${__V(refName_${refName_matchNr})}
Replace refName with your own JMeter Variable reference name
More information: Here’s What to Do to Combine Multiple JMeter Variables

How to return single value from list after filter using JSON Path extractor?

Using the below example test url for reference i want to return only one value from the result.
http://jsonpath.herokuapp.com/?path=$..book[?(#.price%20%3C=%20$[%27expensive%27])]
Tried by applying [:1] at the end it doesn't work
The easiest option is just playing with "Match No" field of the JSON Extractor:
-1 - you will get both matches
inexpensive_1={"category":"reference","title":"Sayings of the Century","author":"Nigel Rees","price":8.95}
inexpensive_2={"category":"fiction","title":"Moby Dick","author":"Herman Melville","price":8.99,"isbn":"0-553-21311-3"}
inexpensive_matchNr=2
1 - you will get first match
inexpensive={"category":"reference","title":"Sayings of the Century","author":"Nigel Rees","price":8.95}
2 - you will get second match:
inexpensive={"category":"fiction","title":"Moby Dick","author":"Herman Melville","price":8.99,"isbn":"0-553-21311-3"}
0 - you will get random match
Or alternatively you can go for JSON JMESPath Extractor which has pipe expressions:
store.book[?price<`10`] | [0]

Jmeter - Regular expression extractor - multiple random variable

Jmeter 2.9
I am using Regex Extractor to extractor to extract a list of ids from a response message and write them to a variable idList.
Using beanshell, I want to extract multiple random items from the list.
If n is my random position in the list, then I am trying to extract the value from the idList using
String id = "${idList_" + n + "}";
s = ${__V(id)};
If n is 7 then this returns ${idList_7} rather than the value at idList_7.
I have also tried
String id = "idList_" + n;
s = ${__V(id)};
but this returns idList_7 rather than the value.
I have also tried using *__eval*.
Can yo help please?
You need to call a pre-defined variable vars
For example if you have a variable called idList_7 which contains some value you can access the value using following Beanshell code
String s = vars.get("idList_7");
or if you want to use concatenation
int seven = 7;
String s = vars.get("idLst_" + seven);
See How to use Beanshell guide for more detailed explanation on JMeter components which are exposed to Beanshell.

regular expression in ruby Regexp

I'm using ruby 1.9.2
string = "asufasu isaubfusabiu safbsua fbisaufb sa {{hello}} uasdhfa s asuibfisubibas {{manish}} erieroi"
Now I have to find {{anyword}}
How many times it will come and the name with curly braces.
After reading Regexp
I am using
/{{[a-z]}}/.match(string)
but it return nil everytime.
You need to apend a * to the [a-z] pattern to tell it to match any number of letters inside the {s, and then use scan to get all occurrences of the match in the string:
string.scan(/{{[a-z]*}}/)
=> ["{{hello}}", "{{manish}}"]
To get the number of times matches occur, just take the size of the resulting array:
string.scan(/{{[a-z]*}}/).size
=> 2
The regular expression matching web application Rubular can be an incredibly helpful tool for doing realtime regular expression parsing.

Ruby - replacing string via gsub and regexp

How can I replace the string 'nEEdle' to get the following result:
"haystackhaystacknEEdlehaystack" -> "haystackhaystack<b>nEEdle</b>haystack"
In my application I have the search parameter only in lowercase, so I want to take the last regexp result ($~) and use it as the replacement string. The following approach doesn't work:
n = "needle"
haystack.gsub(/#{n}/i, "<b>#{$~}</b>")
Any hints?
Try:
heystack.g­sub(/#{n}/­i, '<b>\0</b>')

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