Bash text file editing/modifying - bash

Question

I have a text file that I am trying to modify. I am taking the input file that has lines of the form of
(y+1/4,-x+1/2,z+3/4)
and trying to change it to
0 1 0 -1 0 0 0 0 1 1 / 4 1 / 2 3 / 4
I currently can get to this point
0 1 0 1/4 -1 0 0 1/2 0 0 1 3/4
using
#!bin/bash
filename="227.dat"
sed -i 's/(/ /g' $filename
sed -i 's/)//g' $filename
sed -i 's/,/ /g' $filename
sed -i 's/-x/-1 0 0/g' $filename
sed -i 's/x/ 1 0 0/g' $filename
sed -i 's/-y/ 0 -1 0/g' $filename
sed -i 's/y/ 0 1 0/g' $filename
sed -i 's/-z/ 0 0 -1/g' $filename
sed -i 's/z/ 0 0 1/g' $filename
sed -i '/+/! s/$/ 0 \/ 1 0 \/ 1 0 \/ 1/' $filename
while ((i++)); read -r line; do
if [[ $line == *[+]* ]]
then
sed -i 's/+/ /g' $filename
echo $i
fi
done < "$filename"
The reason for the echo $i was to see that it correctly gives the line number and I thought perhaps I could use it for commands on those specific lines. I am doing this conversion as the code we use in creating crystal structures needs the vector notation with fractions at the end, not the x,y,z notation. I already know this is not the "prettiest" or simplest solution, but I am very new to all of this and it's what I have been able to piece together so far. Any suggestions?

Answer 1

Here's an approach that may simplify the parsing. Read each line into an array using IFS set to all possible delimiters and characters you don't care about:
while IFS=$'\(\)+,' read -ra line; do
for i in 1 3 5; do
case "${line[$i]}" in
x) printf "%s\t%s\t%s\t" 1 0 0 ;;
y) printf "%s\t%s\t%s\t" 0 1 0 ;;
z) printf "%s\t%s\t%s\t" 0 0 1 ;;
-x) printf "%s\t%s\t%s\t" -1 0 0 ;;
-y) printf "%s\t%s\t%s\t" 0 -1 0 ;;
-z) printf "%s\t%s\t%s\t" 0 0 -1 ;;
esac
done
for i in 2 4 6; do
printf "%s\t" "${line[$i]}"
done
echo
done < "$filename"

Answer 2

#!/usr/bin/env bash
filename="227.dat"
re='[(]y[+]([[:digit:]/]+),-x[+]([[:digit:]/]+),z[+]([[:digit:]/]+)[)]';
while IFS= read -r line; do
if [[ $line =~ $re ]]; then
printf '\t%s' \
0 1 0 \
-1 0 0 \
0 0 1 \
"${BASH_REMATCH[1]}" \
"${BASH_REMATCH[2]}" \
"${BASH_REMATCH[3]}";
printf '\n';
else
echo "ERROR: $line does not match $re" 1>&2;
fi;
done <"$filename"
...given, your input, returns:
0 1 0 -1 0 0 0 0 1 1/4 1/2 3/4
...which as far as I can tell is correct.
A more complex approach, making unfounded extrapolations (given the lack of detail and exemplars in the question itself), might look like:
#!/usr/bin/env bash
while IFS='(),' read -a pieces; do
declare -A vars=( [x]=1 [y]=1 [z]=1 [x_sigil]='' [y_sigil]='' [z_sigil]='' )
for piece in "${pieces[#]}"; do
# 1 2 3 4
if [[ $piece =~ (-?)([xyz])([+]([[:digit:]/]+))? ]]; then
if [[ ${BASH_REMATCH[4]} ]]; then # only if there *are* digits
vars[${BASH_REMATCH[2]}]=${BASH_REMATCH[4]} # ...then store them.
fi
vars[${BASH_REMATCH[2]}_sigil]=${BASH_REMATCH[1]} # store - if applicable
fi
done
printf '\t%s' \
"0" "${vars[x_sigil]}1" 0 \
"${vars[y_sigil]}1" 0 0 \
0 0 "${vars[z_sigil]}1" \
"${vars[y]}" "${vars[x]}" "${vars[z]}"
printf '\n'
done
Given the sample inputs provided in a comment on this answer, output is:
0 1 0 1 0 0 0 0 1 1 1 1
0 1 0 1 0 0 0 0 1 1 1 1
0 1 0 1 0 0 0 0 1 1 1 1
0 1 0 1 0 0 0 0 -1 3/4 1/4 1/2
0 1 0 -1 0 0 0 0 1 1/2 3/4 1/4
0 -1 0 1 0 0 0 0 1 1/4 1/2 3/4
0 -1 0 -1 0 0 0 0 -1 1 1 1
0 -1 0 -1 0 0 0 0 -1 1 1 1
0 -1 0 -1 0 0 0 0 -1 1 1 1
0 -1 0 -1 0 0 0 0 1 1/4 3/4 1/2
0 -1 0 1 0 0 0 0 -1 1/2 1/4 3/4
0 1 0 -1 0 0 0 0 -1 3/4 1/2 1/4
0 -1 0 -1 0 0 0 0 1 1/4 3/4 1/2
0 -1 0 -1 0 0 0 0 1 1/4 3/4 1/2
0 -1 0 -1 0 0 0 0 1 1/4 3/4 1/2
0 -1 0 -1 0 0 0 0 -1 1 1 1
0 -1 0 1 0 0 0 0 1 1/4 1/2 3/4
0 1 0 -1 0 0 0 0 1 1/2 3/4 1/4
0 1 0 1 0 0 0 0 -1 3/4 1/4 1/2
0 1 0 1 0 0 0 0 -1 3/4 1/4 1/2
0 1 0 1 0 0 0 0 -1 3/4 1/4 1/2
0 1 0 1 0 0 0 0 1 1 1 1
0 1 0 -1 0 0 0 0 -1 3/4 1/2 1/4
0 -1 0 1 0 0 0 0 -1 1/2 1/4 3/4
0 -1 0 1 0 0 0 0 -1 1/2 1/4 3/4
0 -1 0 1 0 0 0 0 -1 1/2 1/4 3/4
0 -1 0 1 0 0 0 0 -1 1/2 1/4 3/4
0 -1 0 1 0 0 0 0 1 1/4 1/2 3/4