As my first exploration in D3.js,there is a datefield in the csv defined as '01/12/2016'.how to convert this to a proper d3.TimeFormat ?
Your Format is DD/MM/YYYY(01/12/2016)
Use the Following d3 time Format
var parseDate = d3.time.format("%d/%m/%Y").parse;
parseDate('YOUR DATE FORMAT');
Related
I have really simple date as string as ISO const mytDate = '2021-10-24T16:00:00.000Z' and I want to format it like format(new Date(myDate), 'yyyy-MM-dd HH:mm:ss') but new Date() cause that it convert it to my local timezone and I do not want it. I would like to take this string date and just format it as it is.
Is there a solution ?
Cheers!
I made a chart on d3js and on my Xaxis I have some months to show. My time parsing function d3.timeParse("%Y-%m") returns me only months like 'January , February'.
But I would like to get these months in this format : 'Jan-2019, Feb-2019'. What can I do pls?
You could use the abbreviated month(%b) specifier string to get the abbreviated/shortform month names.
If you want the dates to be formatted as Jan-2019, and Feb-2019, you can do the following:
const formatMonth = d3.timeFormat('%b-%Y');
const date = new Date(2014, 1, 1);
console.log(formatMonth(date));
<script src="https://cdnjs.cloudflare.com/ajax/libs/d3/5.7.0/d3.min.js"></script>
You may read find the supported specifier formats for d3.timeParse over here.
I am new to D3.js. I have a date string like "01 DEC 2017". I need to fetch year from it. I am using time format. It's returning null. What is wrong in my code ? Advance thanks for any help.
My code :
d.date = d3.time.format("%Y-%m-%d").parse("01 DEC 2017").getFullYear();
How can I convert this date :
Dec 30, 2013
in the format 'YYYY-MM-DD' in hive :
2013-12-30
I can do explode and concat to match with given format but converting Dec to 12 is problem.
The UDF is the way to go in hive or impala, but if you have an ETL defined before loading data in HDFS, suggest let the ETL carry out the date conversion. It is important to store dates in format YYYY-MM-DD in order to leverage the TO_DATE() in hive or impala
If all your date is in this format then you can write a UDF which reads that column as string,
then converts the date to a given format. Something like this:
public String convertDate(String dt2) throws ParseException{
SimpleDateFormat incommingDateFormat = new SimpleDateFormat("MMM dd, yyyy");
SimpleDateFormat convertedDateFormat = new SimpleDateFormat("yyyy-MM-dd");
Date dt = incommingDateFormat.parse(dt2);
return convertedDateFormat.format(dt);
}
Hope this helps...!!!
How can I concatenate the values of two datetimepicker?
DateTimePicker1 - this is for the the DATE mm/dd/yyyy
DateTimePicker2 - this is for the the TIME hh:mm:ss
I want a value of ... mm/dd/yyy hh:mm:ss in one variable, how can I do that?
One easy way would be
DateTime dt = new DateTime(dtp1.Year, dtp1.Month, dtp1.Day, dtp2.Hour, dtp2.Minute, dtp2.Second);
Please check the order of the parameters, I am writing from memory.
Here dtp1 is a DateTime object from the first datetime picker.