How to validate inner entities in Spring? - spring

I have a Spring MVC application with javax validation. Is there any way to validate inner entities existence, i.e. many-to-one relationship without marking inner class's id #NotNull and additional long field for FK?
#Entity
#Table
public class MyEntity {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private Long id;
#NotNull
private String name;
#ManyToOne
#JoinColumn(name = "my_inner_entity_id")
#NotNull
private MyInnerEntity innerEntity;
//#Column(name = "my_inner_entity_id") can't use it
//#NotNull
//private Long innerEntityId;
//setters and getters
}
#Entity
#Table
public class MyInnerEntity {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
//#NotNull can't use it
private Long id;
#NotNull
private Integer value;
#OneToMany(mappedBy = "innerEntity")
private Set<MyEntity> entities = new HashSet<>();
//setters and getters
}
#PostMapping
public MyEntity save(#RequestBody #Valid MyEntity entity) {
//save entity
}

Just add #Valid annotation to innerEntity property:
#Valid
#NotNull
#ManyToOne
private MyInnerEntity innerEntity;

Solved it by writing custom validator:
#Documented
#Constraint(validatedBy = InnerIdValidator.class)
#Target({ElementType.METHOD, ElementType.FIELD})
#Retention(RetentionPolicy.RUNTIME)
public #interface InnerId {
String message() default "entity with id is required";
Class<?>[] groups() default {};
Class<? extends Payload>[] payload() default {};
}
public class InnerIdValidator implements ConstraintValidator<InnerId, IdObject> {
#Override
public boolean isValid(IdObject idObject, ConstraintValidatorContext constraintValidatorContext) {
return idObject != null && idObject.getId() != null;
}
}

Related

how to properly design a controller and a jsp page for an entity that has three keys, two external and one internal?

I'm trying to make a Spring MVC application.I have 4 entities(Company,Pass_in_trip,Passenger,Trip) Pass_in_trip has 3 keys consisting of Passenger, Trip and Timestamp, I don't know how to properly issue a key and how to transfer it through the jsp page to the controller, and how to issue the controller itself, can anyone tell me?and also an interesting question is how to make a request to the database to search for a record using three keys.
Thanks
here's what I was able to write at the moment, see if there are any errors somewhere
#Entity
#Table(name="company")
public class Company implements Serializable {
#Id
#GeneratedValue(strategy = IDENTITY)
#Column(name="id_comp")
private int id_comp;
#Column(name="name")
private String name;
//Getters and Setters
#Entity
#Table (name="pass_in_trip")
public class Pass_in_trip implements Serializable {
#EmbeddedId
private KeysPass_in_trip key=new KeysPass_in_trip();
#Column(name="place")
private String place;
//Getters and Setters
#Embeddable
public class KeysPass_in_trip implements Serializable{
#NotNull
#JoinColumn(name="date")
private Timestamp date=new Timestamp(System.currentTimeMillis());
#OneToOne(cascade = CascadeType.ALL)
#JoinColumn(name = "id_psg")
private Passenger id_psg=new Passenger();
#OneToOne(cascade = CascadeType.ALL)
#JoinColumn(name = "trip_no" )
private Trip trip_no=new Trip();
//Getters and Setters
//#Override hashCode and equals
#Entity
#Table(name="passenger")
public class Passenger implements Serializable {
#Column(name="name")
private String name;
#NotNull
#Id
#Column(name="id_psg")
#GeneratedValue(strategy = IDENTITY)
private int id_psg;
//Getters and Setters
#Entity
#Table(name="trip")
public class Trip implements Serializable {
#NotNull
#Id
#Column(name="trip_no")
private int trip_no;
#ManyToOne(cascade = CascadeType.MERGE)
#JoinColumn(name = "id_comp")
private Company comp=new Company();
#Column(name="plane")
private String plane;
#Column(name="town_from")
private String town_from;
#Column(name="town_to")
private String town_to;
#Column(name="time_out")
private Timestamp time_out;
#Column(name="time_in")
private Timestamp time_in;
//Getters and Setters
Conroller
#Controller
#RequestMapping("/pass_in_trip/")
public class Aero_Controller_Pass_in_trip {
#Autowired
private Aero_DAO service;
public void setService(Aero_DAO service) {
this.service = service;
}
#RequestMapping(method=RequestMethod.GET)
public String list(Model uiModel) {
List <Pass_in_trip> pass_in_trip=service.findallPass_in_trip();
uiModel.addAttribute("pass_in_trip",pass_in_trip);
return "/pass_in_trip/list";
}
#PreAuthorize("hasRole('ROLE_Admin')")
#RequestMapping(value="delete/{id}",method=RequestMethod.GET)
public String delete(#PathVariable("id")int id, Model uiModel) {
if(service.findByIdPass_in_Trip(id)!=null)
service.delete_Pass_in_trip(id);
return "redirect:/pass_in_trip/";
}
#PreAuthorize("hasRole('ROLE_Admin')")
#RequestMapping(value="update/{id}",method=RequestMethod.GET)
public String updateform(#PathVariable("id")int id, Model uiModel) {
System.out.println("upform");
uiModel.addAttribute("pass_in_trip",service.findByIdPass_in_Trip(id));
System.out.println("upform2");
return "/pass_in_trip/edit";
}
#RequestMapping(value="update/0",method=RequestMethod.GET)
public String newform(Model uiModel) {
System.out.println("Привет!");
return "/pass_in_trip/edit";
}
#PreAuthorize("hasRole('ROLE_Admin')")
#RequestMapping(value="update/{id}",method = RequestMethod.POST)
public String update(Pass_in_trip pass_in_trip,BindingResult bindingResult,Model uiModel,HttpServletRequest httprervletrequest , RedirectAttributes redirectatributes) {
if (bindingResult.hasErrors()) {
uiModel.addAttribute("pass_in_trip", pass_in_trip);
return "pass_in_trip/update";}
service.save(pass_in_trip);
return "redirect:/pass_in_trip/";
}
}
List.jsp
interested in this part:
<s:authorize access="hasRole('ROLE_Admin')">
<td> To change </td>
<td> Delete </td>
</s:authorize>

Spring JPA - How can I make JpaRepository queries using an #Embedded property?

I'm trying to make a existsBy query using a property that comes from an embedded class, but I'm receiving "No property 'cpf' found for type 'Patient'".
The class Patient uses the Person class as embedded.
Person.java
#Embeddable
#Data
public class Person {
#Column(nullable = false, length = 11)
private String cpf;
#Column(name = "full_name", nullable = false, length = 60)
private String fullName;
#Column(nullable = false)
private String birthdate;
#Column(name = "email", nullable = true, length = 30)
private String emailAddress;
#Column(name = "cellphone_number", nullable = true, length = 11)
private String cellphoneNumber;
}
Patient.java
#Data
#Entity
#Table(name = "tb_patient")
public class Patient implements Serializable {
#Serial
private static final long serialVersionUID = 1L;
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
#Column(name = "patient_id")
private UUID id;
#Column
private LocalDateTime registrationDate;
#Embedded
private Person Person;
}
PatientController.java (part of)
#PostMapping
public ResponseEntity<Object> savePatient(#RequestBody Person person) {
if(patientService.existsByCpf(person.getCpf())) {
return ResponseEntity.status(HttpStatus.CONFLICT).body("CONFLICT: CPF number is already in use!");
}
var patientModel = new Patient();
BeanUtils.copyProperties(person, patientModel);
patientModel.setRegistrationDate(LocalDateTime.now(ZoneId.of("UTC")));
return ResponseEntity.status(HttpStatus.CREATED).body(patientService.save(patientModel));
}
PatientService.java (part of)
#Service
public class PatientService {
final PatientRepository patientRepository;
public PatientService(PatientRepository patientRepository) {
this.patientRepository = patientRepository;
}
public boolean existsByCpf(String cpf) {
return patientRepository.existsByCpf((cpf));
}
PatientRepository.java
#Repository
public interface PatientRepository extends JpaRepository<Patient, UUID> {
boolean existsByCpf(String cpf);
}
How can I pass the #Embedded properties to the #Repository?
You can try separate by _ embedded filed name and it's filed.
#Repository
public interface PatientRepository extends JpaRepository<Patient, UUID> {
boolean existsByPerson_Cpf(String cpf);
}

How Can I mapping DTOs using mapstruct?

I am tring to mapping entity datas to DTOs using mapstruct.
And with these sources, I could map id,title datas.
But the problem is.... I can not map userName using these sources.
How can I resolve this problem??
#Entity // DB와의 연결을 위하여
#Data // getter setter
public class Board {
#Id // id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private Long id;
#NotNull
#Size(min=2, max=30)
private String title;
#Length(min=20)
#Lob
#Column(columnDefinition="TEXT", nullable = false)
private String content;
#ManyToOne
#JoinColumn(name="userId", referencedColumnName = "id")
private User user;
}
#Builder
#AllArgsConstructor
#Data
public class BoardListDto {
private Long id;
private String title;
private String userName;
}
#Mapper(componentModel = "spring")
public interface BoardListMapper extends EntityMapper<BoardListDto, Board> {
#Override
#Mapping(target = "userName", source = "user.name.value")
List<BoardListDto> toDtos(List<Board> board);
}
public interface EntityMapper <D, E> {
E toEntity(D dto);
D toDto(E entity);
// Entity업데이트 시 null이 아닌 값만 업데이트 하도록 함.
#BeanMapping(nullValuePropertyMappingStrategy = NullValuePropertyMappingStrategy.IGNORE)
void updateFromDto(D dto, #MappingTarget E entity);
List<D> toDtos(List<E> entity);
}
no need to implement toDtos method for this. This code should be enough and Mapstruct will handle the rest alone.
#Mapper(componentModel = "spring")
public interface BoardListMapper extends EntityMapper<BoardListDto, Board> {
#Override
#Mapping(target = "userName", source = "user.name")
BoardListDto toDto(Board board);
}

AuditingEntityListener is not working for the entity that extends another abstract entity in spring jpa

I have used the #CreatedBy, #CreatedDate, #LastModifiedBy, and #LastModifiedDate annotation on their respective fields. By using #MappedSuperclass,#EntityListeners i able to persist above columns.
But this is not working for the below case:
#MappedSuperclass
#EntityListeners(AuditingEntityListener.class)
public abstract class Auditable<U> {
#CreatedBy
protected U createdBy;
#CreatedDate
#Temporal(TIMESTAMP)
protected Date creationDate;
#LastModifiedBy
protected U lastModifiedBy;
#LastModifiedDate
#Temporal(TIMESTAMP)
protected Date lastModifiedDate;
}
#Entity
#Table(name = "tabel1")
#PrimaryKeyJoinColumn(name = "ID")
class A extends B {
#Column(name = "NAME1", nullable = false)
private String name1;
#Column(name = "CONTENT1", nullable = false)
private String content1;
}
#Entity
#Table(name = "tabel2")
public abstract class B extends Auditable{
#Id
#GeneratedValue
#Column(name = "ID", nullable = false)
private int id;
#Column(name = "NAME", nullable = false)
private String name;
#Column(name = "CONTENT", nullable = false)
private String content;
}
AuditorAwareImpl.java
public class AuditorAwareImpl implements AuditorAware<String>
{
#Override
public Optional<String> getCurrentAuditor()
{
return Optional.ofNullable("Saravanan");
}
}
JpaAuditConfiguration.java
#Configuration
#EnableJpaAuditing(auditorAwareRef = "auditorProvider")
public class JpaAuditConfiguration
{
#Bean
public AuditorAware<String> auditorProvider()
{
return new AuditorAwareImpl();
}
}
In the case, Entity B is populated with audit columns. But Entity A is not. Is there a way to populate Entity A or did i missed anything here..??
I added #Entity annotation to your classes:
#Entity
public class A extends B {
#Id
#GeneratedValue
private Integer id;
private String name;
private String content;
}
#Entity
public class B extends Auditable<String> {
#Id
#GeneratedValue
private Integer id;
private String name;
private String content;
}
Persistence config class (for Spring Boot):
#Configuration
#EnableJpaAuditing
public class PersistenceConfig {
}
Everything works perfectly!

How to get specific inheritant entity using generic dao and service layer

Working on my spring mvc project I face following issu:
I have UnitAppUser, VStanAppUser and RjuAppUser entity classes which extend User entity. User entity stores some general informations. Rest of inheritant entities stores the references to the particular entities (UnitAppUser has a field Unit type, VStanAppUser has a VStan type so on).
Here is my parent User entity
#Entity
#Inheritance(strategy=InheritanceType.JOINED)
#Table(name="app_user")
public class User implements Serializable {
/**
*
*/
private static final long serialVersionUID = 6628717324563396999L;
#Id #GeneratedValue(strategy=GenerationType.IDENTITY)
private Integer id;
#NotEmpty
#Column(name="SSO_ID", unique=true, nullable=false)
private String ssoId;
#NotEmpty
#Column(name="PASSWORD", nullable=false)
private String password;
#NotEmpty
#Column(name="FIRST_NAME", nullable=false)
private String firstName;
#NotEmpty
#Column(name="LAST_NAME", nullable=false)
private String lastName;
#NotEmpty
#Column(name="EMAIL", nullable=false)
private String email;
}
Here's my child classes:
#Entity
#Table(name = "unit_app_user")
public class UnitAppUser extends User implements Serializable {
#JoinColumn(name = "UNITWORK", referencedColumnName = "ID")
#ManyToOne(optional = false)
private UnitDepart unitdepart;
public UnitDepart getWorkat() {
return unitdepart;
}
public void setWorkat(UnitDepart unitdepart) {
this.unitdepart = unitdepart;
}
}
#Entity
#Table(name="rju_app_user")
public class RjuAppUser extends User implements Serializable{
#JoinColumn(name = "workrju", referencedColumnName = "id")
#ManyToOne(optional = false)
private Rju rju;
public Rju getWorkat() {
return rju;
}
public void setWorkat(Rju rju) {
this.rju = rju;
}
}
and finally my VStan entity:
#Entity
#Table(name="vstan_app_user")
public class VstanAppUser extends User implements Serializable{
#JoinColumn(name = "WORKSTATION", referencedColumnName = "kod")
#ManyToOne(optional = false)
private Vstan vstan;
public Vstan getWorkat() {
return vstan;
}
public void setWorkat(Vstan vstan) {
this.vstan = vstan;
}
}
How to write generic dao and service to get specific entity?
As a result I should have something like this
userService.findBySSOId("somessoId").getWorkat() //should return UnitDepart, Rju or VStan

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