I'm trying to write a script which runs various commands and outputs the result of each command into one column but I'm not able to get the output ot be displayed in colums.
#!/bin/bash
# Get GBP Neighbour NAMES
NEIGHBOR=$(vtysh -c 'show ip bgp neighbors' | grep Incoming | awk '{print $7}')
# Get IPs of BGP neighbours
IP=$(vtysh -c 'show ip bgp summary' | awk '{print $1}' | head -n -2 | tail -n +6)
# Get Up/Down time
TIME=$(vtysh -c 'show ip bgp summary' | awk '{print $9}' | head -n -2 | tail -n +6)
# Get State/PfxRcd
STATE=$(vtysh -c 'show ip bgp summary' | awk '{print $10}' | head -n -2 | tail -n +6)
How can I get the output to be separated in columns such as:
NEIGHBOR | IP | TIME | STATE
With paste command:
paste -d'|' <(echo "$NEIGHBOR ") <(echo "$IP") <(echo "$TIME") <(echo "$STATE")
Related
I have this command which returns an IP successfully:
user#laptop:~$ systeminfo.exe | sed -n '/Connection Name: vEthernet (WSL)/,+4p' | egrep --word-regexp '\[01\]:' | awk '{print $2}'
172.22.0.1
I am trying to concatenate and export an environmental variable DISPLAY using a script with this content:
LOCAL_IP=$(systeminfo.exe | sed -n '/Connection Name: vEthernet (WSL)/,+4p' | egrep --word-regexp '\[01\]:' | awk '{print $2}')
export DISPLAY=$LOCAL_IP:0
But after this script runs, DISPLAY doesn't look like expected:
user#laptop:~$ echo $DISPLAY
:02.22.0.1
I was expecting an answer 172.22.0.1:0. What went wrong?
LOCAL_IP appears to have a trailing \r; od -c <<< "${LOCAL_IP}" should show the value ending in a \r
One fix using parameter substitution:
$ export DISPLAY="${LOCAL_IP//$'\r'/}:0"
$ echo "${DISPLAY}"
172.22.0.1:0
Another option would be to add an additional pipe on the end of OP's current command, a couple ideas (dos2unix, tr -d '\r'); 3rd option modifies the awk script to remove the \r:
systeminfo.exe | sed -n '/Connection Name: vEthernet (WSL)/,+4p' | egrep --word-regexp '\[01\]:' | awk '{print $2}' | dos2unix
# or
systeminfo.exe | sed -n '/Connection Name: vEthernet (WSL)/,+4p' | egrep --word-regexp '\[01\]:' | awk '{print $2}' | tr -d '\r'
# or
systeminfo.exe | sed -n '/Connection Name: vEthernet (WSL)/,+4p' | egrep --word-regexp '\[01\]:' | awk '{gsub(/\r/,"");print $2}'
Another option would be to replace the sed/egrep/awk/tr with a single awk call. If OP wants to go this route I'd recommend asking a new question, making sure to provide the complete output from systeminfo.exe to better understand the parsing requirements.
I have 2 query which give me the results:
service
number of service
example:
root#:~/elo# cat test | grep name | grep -v expand | cut -c 22- | rev | cut -c 3- | rev
service1
service2
root#:~/elo# cat test | grep customfield | cut -c 31- | rev | cut -c 2- | rev
2.3.4
55.66
I want to connect first value from first query with first value from second query etc. In this example should be:
service1:2.3.4
service2:55.66
Without a sample file, it is hard to write a working example. But I see, both values are from the same text file and the same line. Therefore I would use awk to do it:
$ cat text
service1;some_other_text;2.3.4
service2;just_some_text;55.66
$awk -F ";" '{printf "%s:%s\n", $1, $3}' test
service1:2.3.4
For a JSON file, it would be easier if you can use jg (e.g. apt-get install jg):
$ cat test.json
[
{
"name": "service1",
"customfield_10090": "1.2.3"
},
{
"name": "service2",
"customfield_10090": "23.3.2"
}
]
$jq '.[] | .name + ":" + .customfield_10090' test.json | sed 's/"//g'
service1:1.2.3
service2:23.3.2
The sed is necessary to eliminate the quotes.
You can use paste:
paste -d: <(grep name test| grep -v expand | cut -c 22- | rev | cut -c 3- | rev) \
<(grep customfield test | cut -c 31- | rev | cut -c 2- | rev)
But there might be better ways. If the input is json, you can probably use jq for a shorter and more efficient solution.
I have a file, config.txt with many lines. One line is like this
address=
I am getting the ip address of the machine on which config.txt resides, with
ip addr | grep 'state UP' -A2 | tail -1 | awk '{print $2}' | cut -f1 -d'/'
That code is taken from a Stack Overflow answer.. The output I am getting is an IP address -
192.168.3.260
I would like to replace
address=
in config.txt with
address='192.168.3.260'
Is it possible to do it in one line, i.e.
ip addr | grep 'state UP' -A2 | tail -1 | awk '{print $2}' | cut -f1 -d'/' | <some sed command >
Using grep, cut and awk in a single pipeline is almost always a mistake, since awk can do everything grep can do, and then some. You can extract the IP address with a sed one-liner, like this:
ip addr | sed -n '/state UP/ {n;n;s/ *inet \(.*\)\/.*/\1/p}'
You can also use this approach to build the command you are looking for:
ip addr | sed -n "/state UP/ {n;n;s/ *inet \(.*\)\/.*/s|address=|\&'\1'|/p}"
which prints something like this:
s|address=|&'192.168.3.260'|
And then you can pipe that program to sed:
ip addr | sed -n "/state UP/ {n;n;s/ *inet \(.*\)\/.*/s|address=|\&'\1'|/p}" \
| sed -f - config.txt
sed -i 's/address=/address='$(ip addr | grep 'state UP' -A2 | tail -1 | awk '{print $2}' | cut -f1 -d'/')'/' filename
Where filename is the name of the file in question, the key here is to use indirection i.e. $(ip addr | grep 'state UP' -A2 | tail -1 | awk '{print $2}' | cut -f1 -d'/') and then use this in a sed command placing particular emphasis on the quotation marks. The indirection must side outside of the single quotation marks of the sed command.
I want to display network interface and their ip address in a table format using shell script. I have this code
#! /bin/bash
interface=$(ifconfig | cut -d ' ' -f1| tr '\n' ' ' | tee save.tmp)
ip=$(ifconfig | awk -F':' '/inet addr/&&!/127.0.0.1/{split($2,_," ");print _[1]}')
echo $interface
echo $ip
The output of this code is
eth0 vmnet1 vmnet8
10.30.10.226 192.168.142.1 192.168.3.1
I want like this
eth0 10.30.10.226
vmnet1 192.168.142.1
vmnet8 192.168.3.1
Thank you in advance
Rearrange it like this:
for iface in $(ifconfig | cut -d ' ' -f1| tr '\n' ' ')
do
addr=$(ip -o -4 addr list $iface | awk '{print $4}' | cut -d/ -f1)
printf "$iface\t$addr\n"
done
Here is my shell script (hope it helps) :
#!/bin/bash
clear
echo -e "+-----------+-----------------+\n| Interface | IP Address |\n+-----------+-----------------+"
for iface in $(ip -o -4 addr list | awk '{print $2}' | tr '\n' ' ')
do
ipaddr=$(ip -o -4 addr list $iface | awk '{print $4}' | cut -d/ -f1)
printf "|%10s | %-16s|\n" $iface $ipaddr
done
echo "+-----------+-----------------+"
Output:
+-----------+-----------------+
| Interface | IP Address |
+-----------+-----------------+
| lo | 127.0.0.1 |
| enp0s31f6 | 10.10.10.100 |
| wlp61s0 | 10.11.11.111 |
| tun0 | 10.20.20.200 |
+-----------+-----------------+
I want to generate list of users having malware in their public html
I am using avgscan for scanning,
/opt/avg/av/bin/avgscan -a -c --ignerrors --report=avoutput.txt
but it generates report like
/home/someuser/mail/info/cur/1395054106.H396740P84180,S=47470:2,S:/form_ident.rar Trojan horse Inject2.WPP
/home/someuser/public_html/__swift/files/attach_pq2ar348en1z435o5jhqy37de2xfb391 Trojan horse Zbot.BMI
I tried some thing but it didnt workout as list also have /backup folder which I don't want to be counted in list
I just need list of users, how to do?
#!/bin/bash
in="your_av_report file.txt" # in this case avoutput.txt
a=$(cat $in | grep -i "/mail/" | grep -v "/backup/" | cut -d'/' -f3 | awk '!a[$0]++' | uniq)
b=$cat $in | grep -i "/public_html/" | grep -v "/backup/" | cut -d'/' -f3 | awk '!a[$0]++' | uniq)
echo $a >>foo.txt
echo $b >>foo.txt
I hope it Helps :)