I have a string "20171110" and I want this to be converted to Date format yyyy-mm-dd of date datatype in Pentaho Data Integration. I tried using select values and calculator but nothing worked. Please suggest.
First, change the String field into date type by using Select values (Metadata Tab). In this case, we use yyyyMMdd as a date format.
After that, drop the 2nd Select values to migrate yyyyMMdd format into yyyy-mm-dd.
And see the result
Related
I am getting timestamp format as '01-APR-21 12.02.00.496677000 AM' from oracle, I want to change the format to load data into sql server column with datatype as datetime.
Current Input: '01-APR-21 12.02.00.496677000 AM'
Expected Output : 2021-04-01 12:02:00.496
I need to write the code in oracle to change timestamp format
Thanks
Neha
A TIMESTAMP is a binary data format consisting of 7-20 bytes (century, year-of-century, month, day, hour, minute, second, up to 6 bytes for fractional seconds and up to 7 bytes for time zone information); it does NOT have a format.
Why am I seeing the TIMESTAMP with a format?
You are seeing it with a format because whatever user interface you are using to access the database has decided that it is more useful to display the binary information as a formatted string rather than returning the raw byte values to you.
Typically, for SQL/Plus and SQL Developer, this is managed by the NLS_TIMESTAMP_FORMAT session parameter. Other user interfaces will have different mechanisms by which they manage the default format of dates and timestamps.
If you want to change the default for SQL/Plus (and SQl Developer) then you can use:
ALTER SESSION SET NLS_TIMESTAMP_FORMAT = 'YYYY-MM-DD HH24:MI:SS.FF9';
(Or whatever format you would like.)
How can I format the TIMESTAMP value?
If you then want to display the timestamp with a format (remember, a TIMESTAMP is not stored with any format) then you want to use TO_CHAR to convert it to a string where it can have a format.
If you want to format the TIMESTAMP as a YYYY-MM-DD HH24:MI:SS.FF3 string then use:
SELECT TO_CHAR( your_timestamp_column, 'YYYY-MM-DD HH24:MI:SS.FF3' )
FROM your_table
How can I convert a formatted string back to a TIMESTAMP?
From your comment:
I loaded the oracle data into a different SQL table where date format was varchar and data got loaded as '01-APR-21 12.02.00.496677000 AM'
Use TO_TIMESTAMP:
SELECT TO_TIMESTAMP( your_string_column, 'DD-MON-RR HH12:MI:SS.FF9 AM' )
FROM your_table
(Note: that this will convert your string to a binary TIMESTAMP and then whatever user interface you are using will use its rules on how to display it; and if the default format it is using is DD-MON-RR HH12:MI:SS.FF9 AM then the query above will look like it has done nothing; it has, the UI is just implicitly converting it back to a string to display it.)
say my usual Date format is '14-jan-2019' and i want my date to only be accepted as 'YYYY-MM-DD' how do i do that? and can i change jan to an actual number?
In my opinion, the right / correct way to do that is to declare your date column (or variable or whatever it is) as DATE, e.g.
create table test (date_column date);
or
declare
l_date_variable date;
begin
...
Doing so, you'd let the database take care about valid values.
You'd then be able to enter data any way you want, using any valid date format mask, e.g.
to_date('06.01.2020', 'dd.mm.yyyy')
date '2020-01-06'
to_date('2020-06-01', 'yyyy-dd-mm')
etc. - all those values would be valid.
A DATE data type has no format - it is stored internally as 7-bytes representing year (2 bytes) and month, day, hour, minute and second (1 byte each).
'14-JAN-2019' is not a date - it is a text literal.
If you want to store date values then use a DATE data type.
If you want to only accept strings of a specific format as input then in whatever user interface you use to talk to the database then accept only that format. If you are converting strings to DATEs and wanting an exact format then you can use:
TO_DATE( '2019-01-14', 'fxYYYY-MM-DD' )
Note: the fx format model will mean that the exact format is expected and the typical string-to-date conversion rules will not be applied.
I am trying to convert data from oracle date field which is in local eastern time to UTC format
and I'm using below function to achieve it
CAST("date field" AS TIMESTAMP) AT TIME ZONE 'UTC'
and my output looks like below
06-NOV-19 09.55.21.000000 AM
However i need to format the output to below format
11/6/2019 9:55:21.000000000 AM
Is there an oracle function which i directly use to do above format conversion?
Formatting and the actual value are separate things. The value, you say is correct, however you want it to look in a different style than the default.
Look into TO_CHAR if you want a specifically formatted string output. eg:
SELECT TO_char(cast(sysdate as timestamp) at time zone 'UTC','mm/dd/yyyy hh:mi:ssxFF am') from dual;
11/18/2019 07:39:42.000000 pm
I tried on my database and the same consult turn the expected result. Try to confer this web site that will show the config of date in oracle:
http://blog.marvinsiq.com/2018/08/23/formatar-data-e-hora-no-oracle-sql-developer/
I have the following date which is in varchar2(11) column in database:
select valid_untill from SALES_ORDERS_V where header_id = 7999410;
30-May-2016
Using rtf template and xml source, the report output (PDF) is:
4950-11-19 04:45:49:0
I don't know its equal to "30-May-2016".
Why this is showing this, as I did not do any formating in rtf?
Not familiar with either RTF or XML-Publisher, but whenever you retrieve a date saved in string format, IF you use it as a date in your code and not as a string, you must make sure you retrieve it correctly.
In this case, with your select statement: it shouldn't be select valid-until from... (or is it really misspelled, with two l at the end: valid_until?) If it is meant to be used as a date, it should be
select to_date(valid_until, 'dd-Mon-yyyy') from ...
Really the problem here is that the date is stored as a string and not in the date datatype. Good luck!
I need your assistance with converting Oracle dates.
I have a column that stores dates like this 20150731 00:00:34.220. However, I would like to show the column like this 20150731 but when I run a simple select statement to test output I get the following error.
select TO_DATE('20150731 00:00:34.550','YYYYMMDD')
from dual
Error
ORA-01830: date format picture ends before converting entire input string
This query
select TO_DATE('20150731 00:00:34.550','YYYYMMDD')
from dual
leads to error
ORA-01830: date format picture ends before converting entire input string
because you pass string with length 22 characters, but at the same time you pass date format with 8 characters, which obviously doesn't correspond to string. You should write the query as
select to_timestamp('20150731 00:00:34.550','yyyymmdd hh24:mi:ss.ff3')
from dual
As for your table, since you have varchar2 column with dates, you have to take care about table content. Query requires exect matching of the source string and date format.
If you want to show only date without time and you don't need to process this string as date, you can make just
select substr('20150731 00:00:34.550', 1, 8)
from dual
What is the data type of the column? If it is DATE (as it should be) then not it is not stored in the format you say. It is stored in an internal binary format. You would/should use the to_char function to DISPLAY it in whatever format you choose. If you do not use the to_char function, it will be displayed in the format specified by NLS_DATE_FORMAT, which can be specified at several locations.
As for your example, you passed a string format of yyyymmd hh:mi:ss.fff', but you provided a description mask of only YYYYMMDD. It doesn't know what to do with time component. In addition to that when you SELECT TO_DATE, oracle also has to do an implied TO_CHAR to convert it back to a string for display purposes.
In addition, you provided your to_date with a character string that included fractions of seconds. A DATE data type only resolves to seconds. If you need fractional seconds, you need to use TIMESTAMP, not DATE.
If your column is a varchar and you need a date output:
select TO_DATE(substr('20150731 00:00:34.550', 1, 8),'YYYYMMDD') from dual
If it's in a date format and you need a string output:
select to_char(your_column, 'YYYYMMDD') from your_table
Is that being stored in an Oracle datetime column? If not, you may have to do some manipulation to get it into a DD-MON-YYYY format. If it is being stored as a text string you could use SUBSTR( Date_field, Start_Position, Length) to get the first 8 characters. check out this link SUBSTR
Working on the assumption that you're not trying to change the value in the column, and are just trying to show it in the YYYYMMDD format -
As mentioned by a_horse_with_no_name, you'll just need to convert it to a character string. In this example I used systimestamp as my date:
SELECT TO_CHAR(systimestamp,'YYYYMMDD') FROM DUAL
Result:
20160121
That should give you the YYYYMMDD format you want to display.