Expresiones Regulares Oracle 11g - oracle

I have a problem I want to compare values ​​from Column A that exist in Column B, regardless of the order they are in Column B
Ex:
Column A 177 Column B 177
Column A 2 : 3 : 1 : 18 : 123 : 170 Column B 18 : 123 : 3 : 2 : 3 : 1 : 1
Column A 2 : 3 : 177 : 123 Column B 3 : 123 : 2 : 177
Column A 2 : 3 : 1 : 123 : 177 Column B 1 : 123 : 2 : 3 : 3 : 1
Column A 172 Column B 1
Column A 2 : 3 : 1 : 18 : 123 : 177 Column B 3 : 1 : 18 : 123 : 3 : 2 : 1
We can see that the first record OK
second record, NO, since the value 170 does not exist
third registration, OK, although the order is not the same as column A, but there are values
fourth record, No
Fifth record, No
Sixth Registor No
Thank you very much for the help friends!
I'm using Oragle 11g.


You are trying to achieve string to table functionality in SQL.
As explained here, the below snippet would be a good start. You can extend the below by changing the delimiter to : instead of , and then include DENSE RANK to compare the column values within the group. Once you break the string into multiple rows then you can easily compare. So instead of a direct check like C1 = C2 you may include the DENSE RANK values to nail this.
I don't have access to any Oracle instance for a fiddle or test and even sqlfiddle.com is broken for ages now. But this pointer should help you in some way. The link I have included contains multiple choices for this functionality.
SQL> SELECT str
2 , REGEXP_SUBSTR(str, '[^,]+', 1, LEVEL) AS single_element
3 , LEVEL AS element_no
4 FROM (
5 SELECT ROWNUM AS id
6 , str
7 FROM t
8 )
9 CONNECT BY INSTR(str, ',', 1, LEVEL-1) > 0
10 AND id = PRIOR id
11 AND PRIOR DBMS_RANDOM.VALUE IS NOT NULL;
STR SINGLE_ELEMENT ELEMENT_NO
------------------------------ ------------------------------ ----------
X,Y,Z X 1
X,Y,Z Y 2
X,Y,Z Z 3
XXX,Y,ZZ,AAAAA,B,CCC,D,E,F,GGG XXX 1
XXX,Y,ZZ,AAAAA,B,CCC,D,E,F,GGG Y 2
XXX,Y,ZZ,AAAAA,B,CCC,D,E,F,GGG ZZ 3
XXX,Y,ZZ,AAAAA,B,CCC,D,E,F,GGG AAAAA 4
XXX,Y,ZZ,AAAAA,B,CCC,D,E,F,GGG B 5
XXX,Y,ZZ,AAAAA,B,CCC,D,E,F,GGG CCC 6
XXX,Y,ZZ,AAAAA,B,CCC,D,E,F,GGG D 7
XXX,Y,ZZ,AAAAA,B,CCC,D,E,F,GGG E 8
XXX,Y,ZZ,AAAAA,B,CCC,D,E,F,GGG F 9
XXX,Y,ZZ,AAAAA,B,CCC,D,E,F,GGG GGG 10

Related

Multiple sorting conditions in DolphinDB

Suppose I have a table as follows:
id=`A`B`A`B`B`B`A
item= 10 1 1 3 5 10 6
t=table(id,item)
id item
-- ----
A 10
B 1
A 1
B 3
B 5
B 10
A 6
For example, I want to sort the table with two conditions: first, by the most commonly occurring item in column item, then by the highest number in column item.
How can I sort like this:
id item
--- ----
A 10
B 10
A 1
B 1
A 6
B 5
B 3
Is there any way to go about this? Thanks!

Try this:
t1=table(id,item);
update t1 set count=count(item) context by item;
select * from t1 order by count desc, item desc;

Increase the numbers in apl

I have the following data:
a b c d
5 9 6 0
3 1 3 2
Characters in the first row, numbers in the second row.
How do I get the character corresponding to the highest number in the second row, and how do I increase the corresponding number in the second row? (For example, here, column b has the highest number, 9, so increase that number by 10%.)
I use Dyalog version 17.1.

With:
⎕←data←3 4⍴'a' 'b' 'c' 'd' 5 9 6 0 3 1 3 2
a b c d
5 9 6 0
3 1 3 2
You can extract the second row with:
2⌷data
5 9 6 0
Now grade it descending, that is, find the indices that would sort it from highest to lowest:
⍒2⌷data
2 3 1 4
The first number is the column we're looking for:
⊃⍒2⌷data
2
Now we can use this to extract the character from the first row:
data[⊂1,⊃⍒2⌷data]
b
But we only need the column index, not the actual character. The full index of the number we want to increase is:
2,⊃⍒2⌷data
2 2
Extracting the data to see that we got the right index:
data[⊂2,⊃⍒2⌷data]
9
Now we can either create a new array with the target value increased by 10%:
1.1×#(⊂2,⊃⍒2⌷data)⊢data
a b c d
5 9.9 6 0
3 1 3 2
Or change it in-place:
data[⊂2,⊃⍒2⌷data]×←1.1
data
a b c d
5 9.9 6 0
3 1 3 2
Try it online!

PL/SQL Oracle 11g Looping

I am having trouble solve. I am suppose to be getting a record every time there is a change to an account in our data warehouse, but I am only receiving one. The table below is a sample of what I am working with.
Row Acct1 Acct2 Date Total_Reissued Reissue_Per_Day
1 A 1 1/1/2016 2 2
2 A 1 1/2/2016 3 1
3 A 1 1/3/2016 5 2
4 A 1 1/4/2016 6 1
1 B 3 1/1/2016 1 1
2 B 3 1/2/2016 2 1
1 B 4 1/1/2016 1 1
2 B 4 1/2/2016 2 1
The Reissued Column is a running total. For Acct A on 1/1/2016 there were 2 reissues, then On 1/2/2016 there was 1 more making a total of 3. My problem is calculating the actual number of reissues per day.

You can use the lag() function to peek back at the previous row; assuming that 'previous' is the last date you saw for the acct1/acct2 combination you can do:
select row_number() over (partition by acct1, acct2 order by dt) as row_num,
acct1, acct2, dt, total_reissued,
total_reissued - nvl(lag(total_reissued)
over (partition by acct1, acct2 order by dt), 0) as reissue_per_day
from your_table;
ROW_NUM A ACCT2 DT TOTAL_REISSUED REISSUE_PER_DAY
---------- - ---------- ---------- -------------- ---------------
1 A 1 2016-01-01 2 2
2 A 1 2016-01-02 3 1
3 A 1 2016-01-03 5 2
4 A 1 2016-01-04 6 1
1 B 3 2016-01-01 1 1
2 B 3 2016-01-02 2 1
1 B 4 2016-01-01 1 1
2 B 4 2016-01-02 2 1
I'm not sure if your 'row' column actually exists, or is required, or was just to illustrate your data. I've generated it anyway, in case you need it.
The main bit of interest is:
lag(total_reissued) over (partition by acct1, acct2 order by dt)
which finds the previous date's value (using dt as a column name, since date isn't a valid name). That then has an nvl() wrapper so the first row sees a dummy value of zero instead of null. And then that is subtracted from the current row's value to get the difference.

Select the sum of occurances of first alphabetical character

Hi what i need to do is create a select statement which outputs the sum of the first character in a field within the table so the output would look something like
A,12
B,0
C,20
D,14
E,0
ect...
The table is called contacts, in the above there was 12 occurrences of people whose names begin with the letter A
I hope i have explained this correctly

Let's understand this with EMP table example.
SQL> with
2 letters
3 as
4 (select chr( ascii('A')+level-1 ) letter
5 from dual
6 connect by level <= 26
7 )
8 SELECT substr(ename, 1, 1) AS init_name,
9 count(*) cnt
10 FROM emp
11 WHERE substr(ename, 1, 1) IN (SELECT letter from letters)
12 GROUP BY substr(ename, 1, 1)
13 UNION
14 SELECT l.letter AS init_name,
15 0 cnt
16 FROM letters l
17 WHERE l.letter NOT IN (SELECT substr(ename, 1, 1) FROM emp)
18 ORDER BY init_name
19 /
I CNT
- ----------
A 2
B 1
C 1
D 0
E 0
F 1
G 0
H 0
I 0
J 2
K 1
L 0
M 2
N 0
O 0
P 0
Q 0
R 0
S 2
T 1
U 0
V 0
W 1
X 0
Y 0
Z 0
26 rows selected.
SQL>
So, it gives the count of each letter of first name, and for the other letters which does not exist in the first name, the count is 0.

Generate the 26 letters using connect then left join to the first letter of the name and count them:
select letter, count(name) count
from (select chr(ascii('A')+level-1) letter from dual connect by level < 27) l
left join emp on substr(name, 1, 1) = letter
group by letter order by 1
See SQLFiddle
Attribution: My technique of generating letters uses elements of Lalit's answer.

Fix numbering of many item groups in table

I have a table with these columns
create table demo (
ID integer not null,
INDEX integer not null,
DATA varchar2(10)
)
Example data:
ID INDEX DATA
1 1 A
1 3 B
2 1 C
2 1 D
2 5 E
I want:
ID INDEX DATA
1 1 A
1 2 B -- 3 -> 2
2 1 C or D -- 1 -> 1 or 2
2 2 D or C -- 1 -> 2 or 1
2 3 E -- 5 -> 3 (closing the gap)
Is there a way to renumber the INDEX per ID using a single SQL update? Note that the order of items should be preserved (i.e. the item "E" should still be after the items "C" and "D" but the order of "C" and "D" doesn't really matter.
The goal is to be able to create a primary key over ID and INDEX.
If that matters, I'm on Oracle 10g.

MERGE
INTO demo d
USING (
SELECT rowid AS rid, ROW_NUMBER() OVER (PARTITION BY id ORDER BY index) AS rn
FROM demo
) d2
ON (d.rowid = d2.rid)
WHEN MATCHED THEN
UPDATE
SET index = rn

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