SpringBoot app - server context Path - spring

Question

I've generated a Spring Boot web application using Spring Initializer, embedded Tomcat, Thymeleaf template engine, and package as an executable JAR file.
Technologies used:
Spring Boot 2.0.0.M6 , Java 8, maven
Here my security config
#Override
protected void configure(HttpSecurity http) throws Exception {
final List<String> activeProfiles = Arrays.asList(env.getActiveProfiles());
if (activeProfiles.contains("dev")) {
http.csrf().disable();
http.headers().frameOptions().disable();
}
http
.authorizeRequests()
.antMatchers(publicMatchers()).permitAll()
.anyRequest().authenticated()
.and()
.formLogin().loginPage("/login").defaultSuccessUrl("/iberia/list")
.failureUrl("/login?error").permitAll()
.and()
.logout().permitAll();
}
in my application.properties
server.contextPath=/iberiaWebUtils
server.port=1234
But when I run the app at http://localhost:1234/iberiaWebUtils, instead of going to http://localhost:1234/iberiaWebUtils/login, the app. redirects to http://localhost:1234/login
I also tried with
server.context-path=/iberiaWebUtils
with the same result

Answer 1

Starting from Spring Boot 2.0.0 M1 servlet-specific server properties were moved to server.servlet:
Spring Boot 2.0.0 M1 Release Notes
Therefore, you should use the server.servlet.context-path property.

Answer 2

Try adding .loginProcessingUrl("/iberiaWebUtils/login") after loginPage("/login")
http
.authorizeRequests()
.antMatchers(publicMatchers()).permitAll()
.anyRequest().authenticated()
.and()
.formLogin().loginPage("/login")
.loginProcessingUrl("/iberiaWebUtils/login")
.defaultSuccessUrl("/iberia/list")
.failureUrl("/login?error").permitAll()
.and()
.logout().permitAll();