How to create subpartition for Reference-Partitioned Tables - oracle

Consider the following scenario of Reference-Partitioned Tables. The table T_PARTNER_CUSTOMER borrows partition part1 and part2 from table T_PARTNER_CONFIG.
CREATE TABLE T_PARTNER_CONFIG (
ID NUMBER(38) NOT NULL,
SECURITY_CONTEXT_ID NUMBER(38) NOT NULL
)
PARTITION BY LIST(SECURITY_CONTEXT_ID)
(PARTITION part1 VALUES (0, 1, 2),
PARTITION part2 VALUES (4, 5, 6));
CREATE TABLE T_PARTNER_CUSTOMER (
ID NUMBER(38) NOT NULL,
PARTNER_CONFIG_ID NUMBER(38) NOT NULL
CUSTOMER_NUMBER VARCHAR2(10) NOT NULL,
CONSTRAINT FK_PC_PARTNER_CONFIG
FOREIGN KEY(PARTNER_CONFIG_ID) REFERENCES T_PARTNER_CONFIG (id)
)
PARTITION BY REFERENCE(FK_PC_PARTNER_CONFIG);
Now if we want to create further subpartition for table T_PARTNER_CUSTOMER, so that the partition part1 and part2 are further subdivided for table T_PARTNER_CUSTOMER. I tried the approach below, but it doesn't work. I am using Oracle 11g Enterprise edition.
CREATE TABLE T_PARTNER_CUSTOMER (
ID NUMBER(38) NOT NULL,
PARTNER_CONFIG_ID NUMBER(38) NOT NULL
CUSTOMER_NUMBER VARCHAR2(10) NOT NULL,
CONSTRAINT FK_PC_PARTNER_CONFIG
FOREIGN KEY(PARTNER_CONFIG_ID) REFERENCES T_PARTNER_CONFIG (id)
)
PARTITION BY REFERENCE(FK_PC_PARTNER_CONFIG)
SUBPARTITION BY HASH (CUSTOMER_NUMBER) SUBPARTITIONS 8;

Seems to be impossible, see documentation:
There is no "SUBPARTITON" clause available, unlike for other partition type, e.g. LIST:

Related

add interval monthly partition

I want to create this table, with a monthly partition on the endTime column.
I mean each month a partition added automatically by oracle.
create table T_CALLSESSION() PARTITON BY RANGE (C_ENDTIME )
INTERVAL(NUMTOYMINTERVAL(1,'month'); (
C_ID NUMBER(34, 0) not null,
C_ENDTIME timestamp not null,
C_STARTTIME timestamp not null,
C_TYPE number(10,0) not null,
F_CREATOR NUMBER(34, 0),
F_MESSAGE_THREAD NUMBER(34, 0),
primary key (C_ID)
);
is that works?
There are a few mistakes in your code.
Table name should not contain the parenthesis ()
The PARTITION clause must be after the declaration of columns and constraints.
You must use the INTERVAL partition so that new partitions are automatically created.
One partition must be created with some constant values and then after other partitions will be automatically created.
Use the following code:
create table T_CALLSESSION (
C_ID NUMBER(34, 0) not null,
C_ENDTIME timestamp not null,
C_STARTTIME timestamp not null,
C_TYPE number(10,0) not null,
F_CREATOR NUMBER(34, 0),
F_MESSAGE_THREAD NUMBER(34, 0),
primary key (C_ID)
) PARTITION BY RANGE (C_ENDTIME)
INTERVAL(NUMTOYMINTERVAL(1, 'MONTH'))
(
PARTITION T_CALLSESSION_P1 VALUES LESS THAN (TO_DATE('01-06-2020', 'DD-MM-YYYY'))
);

PLSQL Trigger on a table with collection of columns

I have a table with a collections:
CS_PARAM_COLLECTION,
create table CS_TEST_WORK_DATA
(
TRANS_ID VARCHAR2(12) not null,
TEST_ID VARCHAR2(12),
ITEMS CS_PARAM_COLLECTION,
ACTIVE NUMBER default 1,
UPDATE_USER VARCHAR2(8),
UPDATE_DATE DATE
)
nested table ITEMS store as TEST_DATA
How can I create a trigger for these table collection columns.

Error: ora-00917: missing comma

Create table A_15006977.vehicle. (
Vin varchar(20) primary key,
Vehicle_type char(20) not null,
Mileage number(20) not null,
Manufacturer char(20) not null
);
Insert all
Into A_15006977.vehicle(vin,vehicle_type,mileage,manufacturer)
values ('tf1bb2ve533093891','panel van',18 325,'man')
A_15006977.vehicle(vin,vehicle_type,mileage,manufacturer)
values
('tf1bb2ve533093822','standard van',79 885,'ford')
Select * from dual;
Create table A_15006977.vehicle (
Vin varchar(20) CONSTRAINT vehicle__vin__pk PRIMARY KEY,
Vehicle_type char(20) CONSTRAINT vehicle__vehicle_type__nn not null,
Mileage number(20) CONSTRAINT vehicle__mileage__nn not null,
Manufacturer char(20) CONSTRAINT vehicle__manufacturer__nn not null
);
Insert all
Into A_15006977.vehicle(vin,vehicle_type,mileage,manufacturer)
VALUES ( 'tf1bb2ve533093891', 'panel van', 18325, 'man' )
INTO A_15006977.vehicle (vin,vehicle_type,mileage,manufacturer)
values ( 'tf1bb2ve533093822', 'standard van', 79885, 'ford' )
SELECT 1 FROM DUAL;
Or:
Insert Into A_15006977.vehicle( vin,vehicle_type,mileage,manufacturer )
SELECT 'tf1bb2ve533093891','panel van', 18325, 'man' FROM DUAL UNION ALL
SELECT 'tf1bb2ve533093822','standard van', 79885, 'ford' FROM DUAL;
Note:
You had an extra . after the table name in the DDL statement and spaces in the mileage (18 325 and 79 885) which need removing and you needed an INTO keyword before the second insert.
It is also useful to name your constraints (then you can easily determine which constraint has been violated in later statements).

Tablespaces with interval partitioning

Is there any way to specify different tablespaces for each partition if I use interval partitioning?
My table is (it is just example, I have more columns in the table):
create table MY_TABLE
(
id NUMBER(20) not null,
type VARCHAR2(1 char) not null,
session_id NUMBER(12) not null,
date_of_beginning DATE not null,
account_number NUMBER not null
)
PCTFREE 1
PARTITION BY RANGE (date_of_beginning)
INTERVAL(NUMTOYMINTERVAL(1, ''MONTH''))
SUBPARTITION BY HASH(account_number) subpartitions 50
(
PARTITION p_1 VALUES LESS THAN (TO_DATE(''01.06.2015'', ''dd.mm.yyyy''))
)';
I want each partition to be stored in separate tablespase. Any ideas how can I achieve it? Maybe some trigger?
For other tables like this one, we have a job, which creates tablespace and partition in the beginning of the month. But this one creates partitions automatically because of intervals.

How do I create a partitioned table without initial partitions?

Say, I have the following DDL:
create table partition_test_table
(
id number(38,0) not null,
value varchar(255),
country_code varchar(2) not null,
creation_date date not null,
constraint pk_partition_test_table primary key (id)
)
partition by range ( creation_date )
subpartition by list ( country_code );
This doesn't work because it doesn't declare any initial partitions. How do I create a partitioned table without initial partitions? Is that even possible?
Thanks.

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