I am trying to get the data of another function inside the controller, but there is a problem when I load it with the view. Anyway I placed the output of the controller inside the view and it still goes to the top of the HTML
this is the controller code
public function index()
{
$data['record'] = $this->samples();
$this->load->view('home',$data);
}//end index()
public function samples(){
echo "string";
}
this is the view
<!DOCTYPE html>
<html>
<head>
<title></title>
</head>
<body>
<?php echo $record;?>
<h1>This is a sample</h1>
</body>
</html>
Now when I go to the browser it looks ok, but when you go to the source code you can see the data is on top of HTML. Why is that?
source code from view
You should return it
public function index()
{
$data['record'] = $this->samples();
$this->load->view('home',$data);
}
public function samples(){
return "string";
}
Related
I am using Laravel 5.5 and Dusk 2.0. I have the following html.
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="utf-8">
</head>
<body class="my-body-class" id="my-body-div">
<div class="my-content-class" id="my-content-div">
Content goes here.
</div>
</body>
</html>
Here's my Dusk test.
public function testBasicExample()
{
$this->browse(function (Browser $browser) {
$browser->visit('/test/admin-fixed-layout');
$this->assertNotNull($browser->element('.my-content-class'));
$this->assertNotNull($browser->element('#my-content-div'));
// $this->assertNotNull($browser->element('.my-body-class'));
$this->assertNotNull($browser->element('#my-body-div'));
});
}
If I un-comment the assertion that uses the body class selector, the test fails. Why?
This is because by default prefix is set to body:
public function __construct($driver, $prefix = 'body')
{
$this->driver = $driver;
$this->prefix = trim($prefix);
}
in Laravel\Dusk\ElementResolver class.
If you really need to change this (but probably there is no point), you can add the following method into Tests/DuskTestCase class:
protected function newBrowser($driver)
{
return new \Laravel\Dusk\Browser($driver, new \Laravel\Dusk\ElementResolver($driver, ''));
}
This will override default browser and pass empty prefix instead of default body prefix
I have Controller on CI like this
class Testing extends CI_Controller {
//put your code here
public function xx() {
$this->load->helper('url');
$this->load->view('testing');
}
public function linkURL() {
$this->load->helper('url');
$data['test'] = "testing123";
$this->load->view('xxx_view', $data);
}
}
I'm running on function linkURL and call view xxx_view, the code on view like this
<html>
<head>
<meta charset="UTF-8">
<title></title>
</head>
<body>
<?php
$segment = array('Testing', 'xx');
?>
Link
</body>
view call a href and using helper site_url to call Controller Testing and function xx. But the link is not working. I am already capture on firebug and link looks like weird. The Link on href contain *http://::1*. How to solved that link
You can print_r($_SERVER) in your controller and check it. or You can use
$config['base_url'] = 'http://localhost:8081/your-project/'
In my opinion, seem to you sent data test to view xxx_view but not using this variable. try echo $test and I see in url using xxx not xx
You need to autoload URL helper in your config/autoload.php.This time you are loading URl helper in function. That will not work for your view.
From my previous question, I've gotten this code from a user.
// app/routes.php
Route::get('characters', 'CharactersController#all');
Route::get('characters/{name}', 'CharactersController#detail');
// app/controllers/CharactersController.php
class CharactersController extends BaseController
{
public function all()
{
// show all characters
}
public function detail($name)
{
// find character by name & show detail for example
return View::make('acc.test');
}
}
// app/views/acc/test.blade.php
// HTML::style('css/style.css') loads CSS file located at public/css/style.css
<!doctype html>
<html lang="en">
<head>
<meta charset="UTF-8">
<title>Document</title>
{{ HTML::style('css/style.css') }}
</head>
<body>
</body>
</html>
also, the search function:
<form action="{{ URL::action('CharactersController#search') }}" method="get">
<input type="text" name="search-term">
<input type="submit" value="Search">
public function search()
{
$name = Input::get('search-term');
$searchResult = Character::where('name', '=', $name)->get();
....
}
Route::get('characters/search', 'CharactersController#search');
how could I in the :
public function detail($name) { // find character by name & show detail for example return View::make('acc.test'); }
how could I find the character by name? I've tried doing something like
$name = $player->name
(I have a model called players, I've also changed Character::where to Player::where), what do I have to insert there? also, how could I display it in the view?
So I mean when I search a player by name it displays the players name ($player->name) for every specific player.
Also do I have to change the relations in the model toHasMany or something like that?
You can do it this way
public function detail($name) {
$player = Player::where('name', '=', $name)->first();
}
If more players can have same name I would rather pass ID instead of name, so in this case use this solution
public function detail($id) {
$player = Player::findOrFail($id);
}
I have a question. How could I create subpages (something like this: character.php?name=Xar) but I want it in Laravel. Do I have to create routes? Also to mention, when I create a route like this:
Route::get('account/test', 'HomeController#test');
and the view is in folder under views/aac/test, and the function is like:
public function test()
{
return View::make('aac.test');
}
it won't load the CSS. it's just an HTML page.
back to the problem again, how could I create sites like that? I'm also using Blade templating engine.
// app/routes.php
Route::get('characters', 'CharactersController#all');
Route::get('characters/{name}', 'CharactersController#detail');
// app/controllers/CharactersController.php
class CharactersController extends BaseController
{
public function all()
{
// show all characters
}
public function detail($name)
{
// find character by name & show detail for example
return View::make('acc.test');
}
}
// app/views/acc/test.blade.php
// HTML::style('css/style.css') loads CSS file located at public/css/style.css
<!doctype html>
<html lang="en">
<head>
<meta charset="UTF-8">
<title>Document</title>
{{ HTML::style('css/style.css') }}
</head>
<body>
</body>
</html>
Search function
Place search form somewhere in your view file
<form action="{{ URL::action('CharactersController#search') }}" method="get">
<input type="text" name="search-term">
<input type="submit" value="Search">
</form>
As specified, search form is submited to CharactersController and its search method.
Controller's method
public function search()
{
$name = Inpute::get('search-term');
$searchResult = Character::where('name', '=', $name)->get();
....
}
Register new route
Route::get('characters/search', 'CharactersController#search');
I am using a fresh build today of Laravel 4.
I have a dashboardController
class DashboardController extends BaseController {
protected $layout = 'layouts.dashboard';
public function index()
{
$this->layout->content = View::make('dashboard.default');
}
}
I have a simple route
Route::get('/', 'DashboardController#index');
I have a blade layout in views/layouts/dashboard.blade.php
For the sake of saving everyone from all of the actual HTML ill use a mock up.
<html>
<head>
<title></title>
</head>
<body>
#yield('content')
</body>
</html>
I have a default blade file in views/dashboard/ that has the following (edited for simplicity)
#section('content')
<p>This is not rocket science</p>
#stop
For some reason the content gets generated before the layout.
I am using a different approach to set the layouts globally to routes using a custom filter. Put the following filter into the app/filters.php
Route::filter('theme', function($route, $request, $response, $layout='layouts.default')
{
// Redirects have no content and errors should handle their own layout.
if ($response->getStatusCode() > 300) return;
//get original view object
$view = $response->getOriginalContent();
//we will render the view nested to the layout
$content = View::make($layout)->nest('_content',$view->getName(), $view->getData())->render();
$response->setContent($content);
});
and now instead of setting layout property in the controller class, you can group the routes and apply the filter as shown below.
Route::group(array('after' => 'theme:layouts.dashboard'), function()
{
Route::get('/admin', 'DashboardController#getIndex');
Route::get('/admin/dashboard', function(){ return View::make('dashboard.default'); });
});
When creating the views, make sure to use the #section('sectionName') in all the sub views and use #yield('sectionName') in the layout views.
I find it easier to do my layout like this for example. I would create my master blade file like so
<html>
<body>
#yield('content');
</body>
</html
And in the blade files that I want to use the master at the top i would put
#extends('master')
then content like so
#section('content')
// content
#stop
Hope this helps.
When you use controller layouts, i.e. $this->layout->..., then you get access to data as variables, not sections. So to access content in your layout you should use...
<html>
<head>
<title></title>
</head>
<body>
<?php echo $content; ?>
</body>
</html>
And in your partial, you would not use #section or #stop...
<p>This is not rocket science</p>