I needed to combine the two table product_price and trade_channels, when I use inner join,
the ID of product_price is remove.
Here is my code
DB::table('product_price')->where('product_id',$id)->where('action','customer_price')
->join('customers','product_price.action_id','=','customers.id')
->get();
A good practise is to select a column that you actually want to use no need of all columns.
Suppose in this case you require all column of product_price table and only customer id from customer_price table then you can do something like this:
DB::table('product_price')
->select(['product_price.*','customer_price.id AS customer_id'])
->where('product_price.product_id',$id)
->where('product_price.action','customer_price')
->join('customers','product_price.action_id','=','customers.id')
->get();
You can select any column but it's good to take alias of join table column in this case it is customer_price so it's not getting confusion if both table has same name column.
Good Luck
try
DB::table('product_price')
->select('*','product_price.id AS product_price_id')
->where('product_id',$id)
->where('action','customer_price')
->join('customers','product_price.action_id','=','customers.id')
->get();
the product_price id would be replace with customers id, so just print out the product_price id with other name.
hope it is help
Related
I need to add a by order with value in eloquent, how can I do it?
example
Order By
c.id = 23 DESC
enter image description here
Is this a joined table if yes show model and controller?
if it not joined table then try this:
->orderBy('c.id','DESC'), or ->orderByCId('DESC') or ->orderByDesc('c.id')
I have two tables contact_us and upload_new_car.
contact_us table contains columns:
id
name
email
phone
message
created_at
updated_at
upload_new_car contains columns:
id
name
phone_number
car_name
car_price
location
car_model_year
car_model
variant
driven
fuel
transmission
city
no_of_owners
upload_1
upload_2
upload_3
upload_4
upload_5
created_at
updated_at
How can I get the UNION of these tables in Laravel? Please help
Not allowing to different size of columns is not laravel's businuess. It is a matter of SQL .You can follow [this link] for more info about UNION statements .
On the other hand for laravel you can use those syntax using union (We can benefit from selecting the same count of columns from each tables).
$first = DB::table('contact_us')
->select('name','phone');
$users = DB::table('users')
->select('name','phone_number as phone')
->union($first)
->get();
dd($users)
I have two table 1. table_a 2. table_b
And all table have company_id. I want to make relationship among this two table using same company id . Like
select * from table_a left join table_b on table_a.company_id = table_b.company_id;
Please help me out if its really possible. Thank you in advance.
You can use this:
$data = DB::table('table_a')->leftJoin('table_b', 'table_a.company_id', '=', 'table_b.company_id')->get();
Or raw:
$users = DB::table('table_a')
->select(DB::raw('query here'))
->get();
More on:
https://laravel.com/docs/5.7/queries
I have the following tables:
Table1:
user_name Url
Rahul www.cric.info.com
ranbir www.rogby.com
sahil www.google.com
banit www.yahoo.com
Table2:
Keyword category
cric sports
footbal sports
google search
I want to search Table1 by matching the keyword in Table2. I can perform the same using case statement and the query works but it is not the right approach because each time I have to add the case statement when I will add new search keyword.
select user_name from table1
case when url like '%cric%' then sports
else 'undefined'
end as category
from table1;
Thanks find the soluntions for this approach. FIrst we need to do the Join and after that we need to filter the record.
select user_name,url,Keyword,catagory from(select table1.user_name,table1.url ,table2.keyword,table2.catagory from table1 left outer join table2)a where a.url like (concat('%',a.phrase,'%')
Not sure about more current versions, but I've run into a similar problem... the primary issue is that Hive only supports equi-join statements... when you apply logic to either side of the join, it has difficulty translating into a Map Reduce function.
The alternative method, if you have a reliably structured field, is that you can create a matching key from the larger field. For example, if you know that you're looking for your keyword to exist in the second position of a dot-delimited URI, you could do something like:
select
Uri
, split(Uri, "\\.")[1] as matchKey
from
Table1
join Table2 on Table2.keyword = Table1.matchKey
;
I have user with name, location, created_at as important fields in table.
I want to retrieve for each user the latest location,i.e, I want something like this:
username location created_at
abc New York 2012-08-18 16:18:57
xyz Mexico city 2012-08-18 16:18:57
abc Atlanta 2012-08-11 16:18:57
only input is UId(1,2) array of userids.please help me to accomplish this.I just want to know how to write query using active record query interface.
Generally, this should be a standard way to solve this kind of problems:
SELECT l1.user, l1.location
FROM locations l1
LEFT JOIN locations l2 ON l1.user = l2.user AND l2.created_at > l1.created_at
WHERE l2.id IS NULL
The idea is to join the table with itself, and find those rows which don't have any row with the same user and greater created_at.
Of course, you should have (user, created_at) index on your table.
Now you should see how would that be represented in AR interface.
When
u_id
is the array of user ids, then
u_id.map{|i| User.find(i).location}
should be an array of the users locations.
You can Use
User.where(:uid => [1,2,3]).maximum('location')
which will create something like
SELECT MAX(`users`.`location`) AS max_id FROM `users` WHERE `users`.`id` IN (1, 2,3)